【每日一题】 UVA - 1588 Kickdown

题意：uva的题，每道都是有背景的orz，都是阅读理解

题解：暴力模拟，拿着短的那个串，对着长的一格一格往左滑，每滑一格暴力扫一遍。然后再从头往右滑，我这里wa了三发，wa了后习惯性瞎改，改到后来循环都改错了。

shortest solution 用while循环ij当指针，还写了个函数处理左右滑。

#include<stdio.h>
#include<string.h>
#include<math.h>
#include<algorithm>
#include<iostream>
#include<queue>
#include<set>
#include<vector>
#include<string>
using namespace std;
typedef long long ll;
#define rep(i,t,n)  for(int i =(t);i<=(n);++i)
#define per(i,n,t)  for(int i =(n);i>=(t);--i)
#define mmm(a,b) memset(a,b,sizeof(a))

string s1, s2;

int main()
{

    while (cin >> s1 >> s2) {
        int len1 = s1.length(), len2 = s2.length();
        if (len1 < len2)swap(s1, s2);
        len1 = s1.length(), len2 = s2.length();
        rep(i, , len2)s1.push_back('');
        int ans = ;
        rep(i, , len1) {
            int ok = ;
            rep(j, , len2 - ) {
                if (s2[j] + s1[i + j] - '' - '' <= )continue;
                else { ok = ; break; }
            }
            if (ok == ) { ans =max( i + len2,len1); break; }
        }
        rep(i, , len2)s1 = '' + s1;
        rep(i, , len2 - ) {
            int ok = ;
            rep(j, i, len2 - ) {

                if (s2[j] + s1[len2+j-i] - '' - '' <= )continue;
                else { ok = ; break; }

            }
            if (ok == ) { ans = min(ans, len1 + i); break; }
        }
        ans = min(ans, len1 + len2);
        cout << ans<<endl;
    }

    return ;
}
/*

 22222
21111

*/