LeetCode OJ：Length of Last Word（最后一个词的长度）

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

求最后一个非空单词的长度而已，没什么注意点，直接看代码，理解题目意思就可以了：

 class Solution {
 public:
     int lengthOfLastWord(string s) {
         int len  = s.length();
         if(len == ) return ;
         while(s[len - ] == ' ')
             if(len -  >= )
                 len--;
             else
                 return ;
         len--;
         int lenCount = ;
         while(s[len] != ' ' && len >= ){
             lenCount++, len--;
         }
         return lenCount;
     }
 };

java版本的代码如下所示，倒过来读很容易了：

 public class Solution {
     public int lengthOfLastWord(String s) {
         int i = s.length() - 1;
         while(i >= 0 && s.charAt(i) == ' ')
             i--;
         int end = i+1;
         while(i >= 0 && s.charAt(i) != ' ')
             i--;
         int start = i+1;
         return end - start;
     }
 }