SQL

LINQ

Lambda

SELECT *

FROM HumanResources.Employee

from e in Employees

select e

Employees
   .Select (e => e)

SELECT e.LoginID, e.JobTitle

FROM HumanResources.Employee AS e

from e in Employees

select new {e.LoginID, e.JobTitle}

Employees
   .Select (
      e =>
         new
         {
            LoginID = e.LoginID,
            JobTitle = e.JobTitle
         }
   )

SELECT e.LoginID AS ID, e.JobTitle AS Title

FROM HumanResources.Employee AS e

from e in Employees

select new {ID = e.LoginID, Title = e.JobTitle}

Employees
   .Select (
      e =>
         new
         {
            ID = e.LoginID,
            Title = e.JobTitle
         }
   )

SELECT DISTINCT e.JobTitle

FROM HumanResources.Employee AS e

(from e in Employees

select e.JobTitle).Distinct()

Employees
   .Select (e => e.JobTitle)
   .Distinct ()

SELECT e.*

FROM HumanResources.Employee AS e

WHERE e.LoginID = 'test'

from e in Employees

where e.LoginID == "test"

select e

Employees
   .Where (e => (e.LoginID == "test"))

SELECT e.*

FROM HumanResources.Employee AS e

WHERE e.LoginID = 'test' AND e.SalariedFlag = 1

from e in Employees

where e.LoginID == "test" && e.SalariedFlag

select e

Employees
   .Where (e => ((e.LoginID == "test") && e.SalariedFlag))

SELECT e.*
FROM HumanResources.Employee AS e

WHERE e.VacationHours >= 2 AND e.VacationHours <= 10

from e in Employees

where e.VacationHours >= 2 && e.VacationHours <= 10

select e

Employees
   .Where (e => (((Int32)(e.VacationHours) >= 2) && ((Int32)(e.VacationHours) <= 10)))

SELECT e.*

FROM HumanResources.Employee AS e
ORDER BY e.NationalIDNumber

from e in Employees

orderby e.NationalIDNumber

select e

Employees
   .OrderBy (e => e.NationalIDNumber)

SELECT e.*

FROM HumanResources.Employee AS e

ORDER BY e.HireDate DESC, e.NationalIDNumber

from e in Employees

orderby e.HireDate descending, e.NationalIDNumber

select e

Employees
   .OrderByDescending (e => e.HireDate)
   .ThenBy (e => e.NationalIDNumber)

SELECT e.*
FROM HumanResources.Employee AS e

WHERE e.JobTitle LIKE 'Vice%' OR SUBSTRING(e.JobTitle, 0, 3) = 'Pro'

from e in Employees

where e.JobTitle.StartsWith("Vice") || e.JobTitle.Substring(0, 3) == "Pro"

select e

Employees
   .Where (e => (e.JobTitle.StartsWith ("Vice") || (e.JobTitle.Substring (0, 3) == "Pro")))

SELECT SUM(e.VacationHours)

FROM HumanResources.Employee AS e

Employees.Sum(e => e.VacationHours);

SELECT COUNT(*)

FROM HumanResources.Employee AS e

Employees.Count();

SELECT SUM(e.VacationHours) AS TotalVacations, e.JobTitle

FROM HumanResources.Employee AS e

GROUP BY e.JobTitle

from e in Employees

group e by e.JobTitle into g

select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)}

Employees
   .GroupBy (e => e.JobTitle)
   .Select (
      g =>
         new
         {
            JobTitle = g.Key,
            TotalVacations = g.Sum (e => (Int32)(e.VacationHours))
         }
   )

SELECT e.JobTitle, SUM(e.VacationHours) AS TotalVacations

FROM HumanResources.Employee AS e

GROUP BY e.JobTitle

HAVING e.COUNT(*) > 2

from e in Employees

group e by e.JobTitle into g

where g.Count() > 2

select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)}

Employees
   .GroupBy (e => e.JobTitle)
   .Where (g => (g.Count () > 2))
   .Select (
      g =>
         new
         {
            JobTitle = g.Key,
            TotalVacations = g.Sum (e => (Int32)(e.VacationHours))
         }
   )

SELECT *

FROM Production.Product AS p, Production.ProductReview AS pr

from p in Products

from pr in ProductReviews

select new {p, pr}

Products
   .SelectMany (
      p => ProductReviews,
      (p, pr) =>
         new
         {
            p = p,
            pr = pr
         }
   )

SELECT *

FROM Production.Product AS p

INNER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID

from p in Products

join pr in ProductReviews on p.ProductID equals pr.ProductID

select new {p, pr}

Products
   .Join (
      ProductReviews,
      p => p.ProductID,
      pr => pr.ProductID,
      (p, pr) =>
         new
         {
            p = p,
            pr = pr
         }
   )

SELECT *

FROM Production.Product AS p

INNER JOIN Production.ProductCostHistory AS pch ON p.ProductID = pch.ProductID AND p.SellStartDate = pch.StartDate

from p in Products

join pch in ProductCostHistories on new {p.ProductID, StartDate = p.SellStartDate} equals new {pch.ProductID, StartDate = pch.StartDate}

select new {p, pch}

Products
   .Join (
      ProductCostHistories,
      p =>
         new
         {
            ProductID = p.ProductID,
            StartDate = p.SellStartDate
         },
      pch =>
         new
         {
            ProductID = pch.ProductID,
            StartDate = pch.StartDate
         },
      (p, pch) =>
         new
         {
            p = p,
            pch = pch
         }
   )

SELECT *

FROM Production.Product AS p

LEFT OUTER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID

from p in Products

join pr in ProductReviews on p.ProductID equals pr.ProductID

into prodrev

select new {p, prodrev}

Products
   .GroupJoin (
      ProductReviews,
      p => p.ProductID,
      pr => pr.ProductID,
      (p, prodrev) =>
         new
         {
            p = p,
            prodrev = prodrev
         }
   )

SELECT p.ProductID AS ID

FROM Production.Product AS p

UNION

SELECT pr.ProductReviewID

FROM Production.ProductReview AS pr

(from p in Products

select new {ID = p.ProductID}).Union(

from pr in ProductReviews

select new {ID = pr.ProductReviewID})

Products
   .Select (
      p =>
         new
         {
            ID = p.ProductID
         }
   )
   .Union (
      ProductReviews
         .Select (
            pr =>
               new
               {
                  ID = pr.ProductReviewID
               }
         )
   )

SELECT TOP (10) *

FROM Production.Product AS p

WHERE p.StandardCost < 100

(from p in Products

where p.StandardCost < 100

select p).Take(10)

Products
   .Where (p => (p.StandardCost < 100))
   .Take (10)

SELECT *

FROM [Production].[Product] AS p

WHERE p.ProductID IN(

SELECT pr.ProductID

FROM [Production].[ProductReview] AS [pr]

WHERE pr.[Rating] = 5

)

from p in Products

where (from pr in ProductReviews

where pr.Rating == 5

select pr.ProductID).Contains(p.ProductID)

select p

Products
   .Where (
      p =>
         ProductReviews
            .Where (pr => (pr.Rating == 5))
            .Select (pr => pr.ProductID)
            .Contains (p.ProductID)
   )

SQL Linq lamda区别的更多相关文章

  1. SQL/LINQ/Lamda 写法[转发]

    SQL LINQ Lambda SELECT * FROM HumanResources.Employee from e in Employees select e Employees   .Sele ...

  2. SQL/LINQ/Lamda

    SQL LINQ Lambda SELECT * FROM HumanResources.Employee from e in Employees select e Employees   .Sele ...

  3. SQL,LINQ,Lambda语法对照图（转载）

    如果你熟悉SQL语句,当使用LINQ时,会有似曾相识的感觉.但又略有不同.下面是SQL和LINQ,Lambda语法对照图 SQL LINQ Lambda SELECT * FROM HumanReso ...

  4. Oracle与Sql server的区别

    一直搞不明白Oracle数据库和sql server的区别,今天我特意查资料把他们的区别整理出来 Oracle数据库:Oracle Database,又名Oracle RDBMS,或简称Oracle. ...

  5. Access、SQLServer、Oracle常见SQL语句应用区别

    Access.SQLServer.Oracle常见SQL语句应用区别 关劲松 PMP 如果要兼容Access.SQL Server.Oracle三个数据库版本:我们在编写SQL语句的过程中,尽量使用一 ...

  6. sqlServer存储过程与sql语句的区别

    sqlServer   存储过程与sql语句的区别 sql存储过程与sql语句的区别: 从以下几个方面考虑: 1.编写: 存储过程:编写比较难: sql语句:相对简单: 2.性能: 存储过程:高,可移 ...

  7. java.util.Date和java.sql.Date的区别和相互转化 （转）

    java.util.Date和java.sql.Date的区别及应用   java.util.Date 就是在除了SQL语句的情况下面使用 java.sql.Date 是针对SQL语句使用的,它只包含 ...

  8. LINQ / LINQ to SQL / LINQ to XXX 它们到底有什么区别

    LINQ是新生事物,不过从不少文章和讨论上看来,这方面的概念也已经有点混沌不清了.因此我们经常可以看到这样的话: LINQ只能将数据表与实体属性一一对应…… LINQ开发指南:在LINQ中进行数据库字 ...

  9. SQL,Linq,Lambda之间的转换练习

    1.查询Student表中的所有记录的Sname.Ssex和Class列. SQL:select sname,ssex,class from Students linq:from s in Stude ...

随机推荐

  1. 在其他系统Iframe中显示SharePoint 页面

    前段时间在做一个项目,要求将SharePoint 的 OWA(Office Web Apps)中的文档显示页面嵌入到另外一个OA系统中,提供给用户可以通过浏览器查看SharePoint文档的能力. 嵌 ...

  2. Android自定义控件4--优酷菜单的菜单键及细节补充

    在上篇文章中实现了优酷菜单执行动画,本文接着完善已经实现的动画功能 本文地址:http://www.cnblogs.com/wuyudong/p/5915958.html ,转载请注明源地址. 已经实 ...

  3. Android 拍照后保证保证图片不失真，进行压缩

    今天在网上找了一下参考,得出把图片压缩至KB 其他不想多说.直接上代码 拍完照后调用下面代码 BitmapUtils.compressBitmap(photoPath, photoPath, 640) ...

  4. Ubuntu14.04 Django Mysql安装部署全过程

    Ubuntu14.04 Django Mysql安装部署全过程   一.简要步骤.(阿里云Ubuntu14.04) Python安装 Django Mysql的安装与配置 记录一下我的部署过程,也方便 ...

  5. iOS开发之Socket

    在IOS开发中,网络请求链接往往是HTTP请求,但是有些需求比较特殊,需要保持持续连接,就需要用到Socket了. 另外在游戏开发中,常常会用到Socket连接,因为http请求数据往往需要用户主动请 ...

  6. 在UTF-8中，一个汉字为什么需要三个字节？

    UNICODE是万能编码,包含了所有符号的编码,它规定了所有符号在计算机底层的二进制的表示顺序.有关Unicode为什么会出现就不叙述了,Unicode是针对所有计算机的使用者定义一套统一的编码规范, ...

  7. 关于Redis数据过期策略

    1.Redis中key的的过期时间 通过EXPIRE key seconds命令来设置数据的过期时间.返回1表明设置成功,返回0表明key不存在或者不能成功设置过期时间.在key上设置了过期时间后ke ...

  8. HDFS Federation (读书笔记)

    HDFS Federation (读书笔记) HDFS的架构 HDFS包含两个层次:命名空间管理(Namespace) 和 块/存储管理(Block Storage). 命名空间管理(Namespac ...

  9. Java环境变量的配置

    1.JAVA_HOMEjdk的路径,我的是安装在C:\Program Files (x86)\Java\jdk1.6.0_182.CLASSPATH .;%JAVA_HOME%\lib\dt.jar; ...

  10. C++智能指针详解

    本文出自http://mxdxm.iteye.com/ 一.简介 由于 C++ 语言没有自动内存回收机制,程序员每次 new 出来的内存都要手动 delete.程序员忘记 delete,流程太复杂,最 ...