php 算法之------------怎样打印出下图

自己偶尔看到了下图。于是用php打印出下图。

watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQveGluZ2ppZ29uZ3Np/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast" alt="">

两种方法解决此问题：

方法一：依据图分析该图是一个二维数组，可用二维数组解决此类问题，6行就是6个数组，每一行就代表数组有多少个元素。知道每一个数组元素的个数。不就能够知道数组中有哪几个元素吗？

function array_chunk_vertical($arr, $colun)
{
    $arr_length = count($arr);
    $parem = floor($arr_length / $colun);
    $pare = $arr_length % $colun;
    $ar = array();
    for ($i = 0; $i < $colun; $i ++) {
        $par = $i == $colun - 1 ? 1 : 5;
        $ar[] = $par;
    }
    $newarray = array();
    foreach ($ar as $value) {
        for ($i = 0; $i < $value; $i ++) {
            $newarray[$i][] = array_shift($arr);
        }
    }
    return $newarray;
}

$arr = range(1, 31);
$data = array_chunk_vertical($arr, 7);
foreach ($data as $value) {
    foreach ($value as $va) {
        printf('[%2s]', $va);
    }
    echo "<br/>";
}

方法二：如代码。先给出size个空数组。在空数组中填充元素。

详细方法例如以下：

<?

php
function array_chunk_vertical($input, $size, $preserve_keys = FALSE, $size_is_horizontal = false)
{
    $chunks = array();

    if ($size_is_horizontal) {
        $chunk_count = ceil(count($input) / $size);
    } else {
        $chunk_count = $size;
    }

    for ($chunk_index = 0; $chunk_index < $chunk_count; $chunk_index++) {
        $chunks[] = array();
    }

    $chunk_index = 0;
    foreach ($input as $key => $value)
    {
        if ($preserve_keys) {
            $chunks[$chunk_index][$key] = $value;
        } else {
            $chunks[$chunk_index][] = $value;
        }

        if (++$chunk_index == $chunk_count) {
            $chunk_index = 0;
        }
    }

    return $chunks;
}

$data=range(1,31);
$newdata=array_chunk_vertical($data,6);
foreach ($newdata as $root){
    foreach ($root as $val){
        printf('[%2s]',$val);
    }
    echo "<br/>";
}