hard or 9102 字符串DP---Educational Codeforces Round 57 (Rated for Div. 2)
题意:http://codeforces.com/problemset/problem/1096/D
思路:参考:https://blog.csdn.net/qq_41289920/article/details/100715683
#define IOS ios_base::sync_with_stdio(0); cin.tie(0);
#include <cstdio>//sprintf islower isupper
#include <cstdlib>//malloc exit strcat itoa system("cls")
#include <iostream>//pair
#include <fstream>//freopen("C:\\Users\\13606\\Desktop\\草稿.txt","r",stdin);
#include <bitset>
//#include <map>
//#include<unordered_map>
#include <vector>
#include <stack>
#include <set>
#include <string.h>//strstr substr
#include <string>
#include <time.h>// srand(((unsigned)time(NULL))); Seed n=rand()%10 - 0~9;
#include <cmath>
#include <deque>
#include <queue>//priority_queue<int, vector<int>, greater<int> > q;//less
#include <vector>//emplace_back
//#include <math.h>
//#include <windows.h>//reverse(a,a+len);// ~ ! ~ ! floor
#include <algorithm>//sort + unique : sz=unique(b+1,b+n+1)-(b+1);+nth_element(first, nth, last, compare)
using namespace std;//next_permutation(a+1,a+1+n);//prev_permutation
//******************
int abss(int a);
int lowbit(int n);
int Del_bit_1(int n);
int maxx(int a,int b);
int minn(int a,int b);
double fabss(double a);
void swapp(int &a,int &b);
clock_t __STRAT,__END;
double __TOTALTIME;
void _MS(){__STRAT=clock();}
void _ME(){__END=clock();__TOTALTIME=(double)(__END-__STRAT)/CLOCKS_PER_SEC;cout<<"Time: "<<__TOTALTIME<<" s"<<endl;}
//***********************
#define rint register int
#define fo(a,b,c) for(rint a=b;a<=c;++a)
#define fr(a,b,c) for(rint a=b;a>=c;--a)
#define mem(a,b) memset(a,b,sizeof(a))
#define pr printf
#define sc scanf
#define ls rt<<1
#define rs rt<<1|1
typedef long long ll;
const double E=2.718281828;
const double PI=acos(-1.0);
//const ll INF=(1LL<<60);
const int inf=(<<);
const double ESP=1e-;
const int mod=(int)1e9+;
const int N=(int)1e6+; char s[N];
ll dp[N][];
ll a[N]; int main()
{
int n;
sc("%d",&n);
sc("%s",s+);
for(int i=;i<=n;++i)sc("%lld",&a[i]);
for(int i=;i<=n;++i)
{
for(int j=;j<=;++j)dp[i][j]=dp[i-][j];
if(s[i]=='h')dp[i][]+=a[i];
else if(s[i]=='a')dp[i][]=min(dp[i][]+a[i],dp[i-][]);
else if(s[i]=='r')dp[i][]=min(dp[i][]+a[i],dp[i-][]);
else if(s[i]=='d')dp[i][]=min(dp[i][]+a[i],dp[i-][]);
}
pr("%lld\n",dp[n][]);
return ;
} /**************************************************************************************/ int maxx(int a,int b)
{
return a>b?a:b;
} void swapp(int &a,int &b)
{
a^=b^=a^=b;
} int lowbit(int n)
{
return n&(-n);
} int Del_bit_1(int n)
{
return n&(n-);
} int abss(int a)
{
return a>?a:-a;
} double fabss(double a)
{
return a>?a:-a;
} int minn(int a,int b)
{
return a<b?a:b;
}
hard or 9102 字符串DP---Educational Codeforces Round 57 (Rated for Div. 2)的更多相关文章
- Educational Codeforces Round 57 (Rated for Div. 2) D dp
https://codeforces.com/contest/1096/problem/D 题意 给一个串s,删掉一个字符的代价为a[i],问使得s的子串不含"hard"的最小代价 ...
- [贪心,dp] Educational Codeforces Round 71 (Rated for Div. 2) C. Gas Pipeline (1207C)
题目:http://codeforces.com/contest/1207/problem/C C. Gas Pipeline time limit per test 2 seconds memo ...
- Educational Codeforces Round 57 (Rated for Div. 2) ABCDEF题解
题目总链接:https://codeforces.com/contest/1096 A. Find Divisible 题意: 给出l,r,在[l,r]里面找两个数x,y,使得y%x==0,保证有解. ...
- Educational Codeforces Round 57 (Rated for Div. 2)
我好菜啊. A - Find Divisible 好像没什么可说的. #include<cstdio> #include<cstring> #include<algori ...
- Educational Codeforces Round 57 (Rated for Div. 2)D(动态规划)
#include<bits/stdc++.h>using namespace std;char s[100007];long long a[100007];long long dp[100 ...
- Educational Codeforces Round 57 (Rated for Div. 2) C 正多边形 + 枚举
https://codeforces.com/contest/1096/problem/C 题意 问是否存在一正多边形内三点构成的角度数为ang,若存在输出最小边数 题解 三点构成的角是个圆周角,假设 ...
- Educational Codeforces Round 57 (Rated for Div. 2) 前三个题补题
感慨 最终就做出来一个题,第二题差一点公式想错了,又是一波掉分,不过我相信我一定能爬上去的 A Find Divisible(思维) 上来就T了,后来直接想到了题解的O(1)解法,直接输出左边界和左边 ...
- Educational Codeforces Round 63 (Rated for Div. 2) 题解
Educational Codeforces Round 63 (Rated for Div. 2)题解 题目链接 A. Reverse a Substring 给出一个字符串,现在可以对这个字符串进 ...
- Educational Codeforces Round 64 (Rated for Div. 2)题解
Educational Codeforces Round 64 (Rated for Div. 2)题解 题目链接 A. Inscribed Figures 水题,但是坑了很多人.需要注意以下就是正方 ...
- Educational Codeforces Round 53 (Rated for Div. 2) (前五题题解)
这场比赛没有打,后来补了一下,第五题数位dp好不容易才搞出来(我太菜啊). 比赛传送门:http://codeforces.com/contest/1073 A. Diverse Substring ...
随机推荐
- 腾讯域名防封 微信/QQ域名检测,域名防封的原理
微信屏蔽网页的依据是什么?明面上的原因是网页内容有诱导.诈骗等不和谐的内容时候,被用户举报就会封闭.实际上这只是表面现象,因为我们能明确的感受到不同的阶段,同样的内容,被封杀的频率差别很大的,也就是说 ...
- js中的时间显示
var approveTime; approveTime=new Date(da[i].approveTime).toLocaleDateString(); 结果是 xxxx年xx月xx日
- Leetcode题目分类整理
一.数组 8) 双指针 ---- 滑动窗口 例题: 3. Longest Substring Without Repeating Characters 描述:Given a string, find ...
- Nginx之configure选项
1. 通用配置项 --prefix=<path>:Nginx 安装的根路径,所有其他的路径都要依赖于该选项. --sbin-path=<path>:指定 Nginx 二进制文件 ...
- 【log4j】log4j.properties 文件示例
# 下面的文件内容是写程序长期要用的,放在这里留个底#Output information(higher than INFO) to stdout and file.info/debug/error ...
- Python接口测试-模块引用与映射
PyCharm中发现模块引用老是有各种问题 可以用映射来解决,例如需要调用登录模块里面的东西的时,可以这样处理: 登录模块:1-login.py import this import requests ...
- qt+opencv编译环境的配置
第一步:安装与配置Qt 从https://account.qt.io/downloads下载Qt,并注册账户.开始安装.首先下载qt-opensource-windows-x86-mingw482_o ...
- easyUI之表单
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <hea ...
- 日志文件---log4j.properties
### direct log messages to stdout ### log4j.appender.stdout=org.apache.log4j.ConsoleAppender log4j.a ...
- MATLAB学习(八)神经网络拟合工具箱 Neural Net Fitting使用示例
>> x=-3:0.2:5;y=x.^2-1;xn=-2:0.1:7; >> >> %多元函数(z=sin(x2+y2)/(x2+y2))拟合 >&g ...