Maximum Subarray:

Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array [-2,1,-3,4,-1,2,1,-5,4],

the contiguous subarray [4,-1,2,1] has the largest sum = 6.

这是动态规划的一道较简单的题目。主要思想是,以下标为index的数字作为结尾的所有subarray中,和最大的那个子数列 ,与以下标为index-1的数字作为结尾的和最大的子数列有关系。

class Solution {
public:
int maxSubArray(vector<int>& nums) {
int temp[nums.size()],max;
for(int i = 0; i < nums.size(); i++){
if(i==0){
temp[i] = nums[i];
max = nums[i];
}
else{
if(temp[i-1]>0){
temp[i] = temp[i-1] + nums[i];
}else{
temp[i] = nums[i];
}
}
max = max>temp[i]?max:temp[i];
}
return max;
}
};

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