我们正在玩一个猜数字游戏。 游戏规则如下:
我从 1 到 n 选择一个数字。 你需要猜我选择了哪个数字。
每次你猜错了,我会告诉你这个数字是大了还是小了。
你调用一个预先定义好的接口 guess(int num),它会返回 3 个可能的结果(-1,1 或 0):
-1 : 我的数字比较小
 1 : 我的数字比较大
 0 : 恭喜!你猜对了!
示例:
n = 10, 我选择 6.
返回 6.
详见:https://leetcode.com/problems/guess-number-higher-or-lower/description/
C++:

// Forward declaration of guess API.
// @param num, your guess
// @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
int guess(int num); class Solution {
public:
int guessNumber(int n) {
if(guess(n)==0)
{
return n;
}
int left=1,right=n;
while(left<right)
{
int mid=left+(right-left)/2,t=guess(mid);
if(t==0)
{
return mid;
}
else if(t==1)
{
left=mid;
}
else
{
right=mid;
}
}
return left;
}
};

参考:https://www.cnblogs.com/grandyang/p/5666502.html

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