HDOJ 5384 Danganronpa AC自己主动机

 AC自己主动机裸题

Danganronpa

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 164    Accepted Submission(s): 80

Problem Description

Danganronpa is a video game franchise created and developed by Spike Chunsoft, the series' name is compounded from the Japanese words for "bullet" (dangan) and "refutation" (ronpa).

Now, Stilwell is playing this game. There are n verbal
evidences, and Stilwell has m "bullets".
Stilwell will use these bullets to shoot every verbal evidence.

Verbal evidences will be described as some strings Ai,
and bullets are some strings Bj.
The damage to verbal evidence Ai from
the bullet Bj is f(Ai,Bj).

f(A,B)=∑i=1|A|−|B|+1[ A[i...i+|B|−1]=B ]

In other words, f(A,B) is
equal to the times that string B appears
as a substring in string A.
For example: f(ababa,ab)=2, f(ccccc,cc)=4

Stilwell wants to calculate the total damage of each verbal evidence Ai after
shooting all m bullets Bj,
in other words is ∑mj=1f(Ai,Bj).

 

Input

The first line of the input contains a single number T,
the number of test cases.
For each test case, the first line contains two integers n, m.
Next n lines,
each line contains a string Ai,
describing a verbal evidence.
Next m lines,
each line contains a string Bj,
describing a bullet.

T≤10
For each test case, n,m≤105, 1≤|Ai|,|Bj|≤104, ∑|Ai|≤105, ∑|Bj|≤105
For all test case, ∑|Ai|≤6∗105, ∑|Bj|≤6∗105, Ai and Bj consist
of only lowercase English letters

 

Output

For each test case, output n lines,
each line contains a integer describing the total damage of Ai from
all m bullets, ∑mj=1f(Ai,Bj).

 

Sample Input

1
5 6
orz
sto
kirigiri
danganronpa
ooooo
o
kyouko
dangan
ronpa
ooooo
ooooo

 

Sample Output

1
1
0
3
7

 

Source

2015 Multi-University Training Contest 8

 

/* ***********************************************
Author        :CKboss
Created Time  :2015年08月13日 星期四 13时55分22秒
File Name     :1005.cpp
************************************************ */

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstdlib>
#include <vector>
#include <queue>
#include <set>
#include <map>

using namespace std;

typedef long long int LL;

const int maxn=110100;

int ch[maxn][26],fail[maxn];
LL End[maxn];
int root,sz;

int newnode()
{
    memset(ch[sz],-1,sizeof(ch[sz]));
    End[sz++]=0;
    return sz-1;
}

void init()
{
    sz=0; root=newnode();
}

void insert(const char str[])
{
    int len=strlen(str);
    int now=root;
    for(int i=0;i<len;i++)
    {
        int& temp=ch[now][str[i]-'a'];
        if(temp==-1) temp=newnode();
        now=temp;
    }
    End[now]++;
}

void build()
{
    queue<int> q;
    fail[root]=root;
    for(int i=0;i<26;i++)
    {
        int &temp=ch[root][i];
        if(temp==-1) temp=root;
        else
        {
            fail[temp]=root;
            q.push(temp);
        }
    }
    while(!q.empty())
    {
        int now=q.front(); q.pop();
        for(int i=0;i<26;i++)
        {
            if(ch[now][i]==-1)
            {
                ch[now][i]=ch[fail[now]][i];
            }
            else
            {
                fail[ch[now][i]]=ch[fail[now]][i];
                q.push(ch[now][i]);
            }
        }
    }
}

LL query(const char str[])
{
    int len=strlen(str);
    int now=root;
    LL ret=0;
    for(int i=0;i<len;i++)
    {
        now=ch[now][str[i]-'a'];
        int temp=now;
        while(temp!=root)
        {
            ret+=End[temp];
            temp=fail[temp];
        }
    }
    return ret;
}

int n,m;
string Ts[maxn],Tp[maxn];

int main()
{
    //freopen("in.txt","r",stdin);
    //freopen("out.txt","w",stdout);

    int T_T;
    scanf("%d",&T_T);
    while(T_T--)
    {
        scanf("%d%d",&n,&m);
        for(int i=0;i<n;i++) cin>>Ts[i];

        init();
        for(int i=0;i<m;i++)
        {
            cin>>Tp[i];
            insert(Tp[i].c_str());
        }

        build();

        for(int i=0;i<n;i++)
        {
            LL as=query(Ts[i].c_str());
            cout<<as<<endl;
        }
    }

    return 0;
}