#include<bits/stdc++.h>
using namespace std;
#define INF 0x3f3f3f3f
int dis[];
int visit[];
int SSSP[][];
void dijkstra(int x,int n)
{
int pos;
int minn;
for(int i=;i<=n;i++)
{
dis[i]=SSSP[][i];
}
visit[x]=;
dis[x]=;
for(int i=;i<=n;i++)
{
minn=INF;
pos=;
for(int j=;j<=n;j++)
{
if(!visit[j]&&dis[j]<minn)
{
pos=j;
minn=dis[j];
} }
if(pos==) break;
else
{
visit[pos]=;
for(int j=;j<=n;j++)
{
if(!visit[j]&& dis[pos]+SSSP[pos][j]<dis[j])
dis[j]=dis[pos]+SSSP[pos][j];
}
} }
}
int main()
{
while()
{
int n,m; cin>>n>>m;
if(n==&&m==) break; int zzzzz=; memset(visit,,sizeof(visit));
memset(dis,,sizeof(dis));
memset(SSSP,,sizeof(SSSP)); for(int i=;i<=n;i++)
{
for(int j=;j<=n;j++)
SSSP[i][j]=INF;
}
int a[];
int b[];
int t[];
for(int i=;i<=m;i++)
{
cin>>a[i]>>b[i]>>t[i];
SSSP[a[i]][b[i]]=t[i];
SSSP[b[i]][a[i]]=t[i];
}
dijkstra(,n); //cout<<"*****"<<dis[n]<<"*******"<<zzzzz<<"******"<<endl;
if(dis[n]==INF)
{
zzzzz=;
}
int maxn=dis[n]; for(int i=;i<n;i++)
{
// qu dian chong ding yi
if(zzzzz==) break;
for(int j=;j<=n;j++)
{
for(int j1=;j1<=n;j1++)
SSSP[j][j1]=INF;
}
for(int j=;j<=m;j++)
{
SSSP[a[j]][b[j]]=t[j];
SSSP[b[j]][a[j]]=t[j];
if(a[j]==i||b[j]==i)
{
SSSP[a[j]][b[j]]=INF;
SSSP[b[j]][a[j]]=INF;
}
}
// chong ding yi visit[] dis memset(visit,,sizeof(visit));
memset(dis,,sizeof(dis)); dijkstra(,n); // cout<<"*****"<<dis[n]<<"*******"<<zzzzz<<"******"<<endl;
if(dis[n]==INF)
{
zzzzz=;
}
if(dis[n]>maxn) maxn=dis[n];
}
if(zzzzz==)
cout<<maxn<<endl;
if(zzzzz==)
cout<<"Inf"<<endl;
}
}

hdu5173 How Many Maos Does the Guanxi Worth的更多相关文章

  1. hdu 5137 How Many Maos Does the Guanxi Worth 最短路 spfa

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  2. HDU 5137 How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 512000/5120 ...

  3. hdoj 5137 How Many Maos Does the Guanxi Worth【最短路枚举+删边】

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  4. HDU5137 How Many Maos Does the Guanxi Worth(枚举+dijkstra)

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  5. How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  6. HDU 5137 How Many Maos Does the Guanxi Worth 最短路 dijkstra

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  7. (hdoj 5137 floyd)How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  8. 杭电5137How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  9. ACM学习历程——HDU5137 How Many Maos Does the Guanxi Worth(14广州10题)(单源最短路)

    Problem Description    "Guanxi" is a very important word in Chinese. It kind of means &quo ...

随机推荐

  1. caffe模型参数解释

    作者:wjmishuai 出处: http://blog.csdn.net/wjmishuai/article/details/50890214 原始数据是28*28 1:数据层: layer { n ...

  2. VSTO:使用C#开发Excel、Word【8】

    office加载项Office开发中使用的第二种模式是加载项模式.本书涵盖了几种Office加载项.其中包括Outlook的VSTO加载项,Excel和Word的COM加载项以及Excel的自动化加载 ...

  3. 从R-CNN到FAST-RCNN再到Faster R-CNN

    (Faster R-CNN: Towards Real-Time Object Detection with Region Proposal Networks)   R-CNN: (1)输入测试图像: ...

  4. transiton,transform,animation,border-image

    animation,transition,transform三者联系与区别: https://www.jianshu.com/p/0e0e1903b80d transform: 使用小技巧: tran ...

  5. 8.2 C++标准输出流对象

    参考:http://www.weixueyuan.net/view/6408.html 总结: iostream头文件,包含了该头文件后,我们就可以直接使用这些对象,包含标准的输出流对象cout.ce ...

  6. Linux如何从零开始搭建rsync服务器(centOS6)

    Step1:检查rsync是否已经安装 rmp -qa rsync 如果没有安装的话,通过yum install rsync -y   Step2:给rsync服务添加本地用户,用于管理本地目录. u ...

  7. mybatis 配置文件 配置别名

    <?xml version="1.0" encoding="UTF-8"?><!DOCTYPE configuration PUBLIC &q ...

  8. Aimbat安装

    1:Pysmo下的sac和aimbat需要放在和前面的toolkits 相同的地方,Python就能找到: 在安装obspy时,需要装yum-plugin-copr; 方法在网址: https://c ...

  9. Asp.Net对Json字符串的解析和应用

    using System.Web.Script.Serialization; protected void Page_Load(object sender,EventArgs e) { //构建jso ...

  10. L310

    Facelift( 紧肤术) followed by a week on a beach in Thailand? Hip surgery with a side of shopping inSing ...