图论(网络流,二分图最小点权覆盖):POJ 2125 Destroying The Graph
Description
Alice assigns two costs to each vertex: Wi+ and Wi-. If Bob removes all arcs incoming into the i-th vertex he pays Wi+ dollars to Alice, and if he removes outgoing arcs he pays Wi- dollars.
Find out what minimal sum Bob needs to remove all arcs from the graph.
Input
file describes the graph Alice has drawn. The first line of the input
file contains N and M (1 <= N <= 100, 1 <= M <= 5000). The
second line contains N integer numbers specifying Wi+. The third line defines Wi- in a similar way. All costs are positive and do not exceed 106
. Each of the following M lines contains two integers describing the
corresponding arc of the graph. Graph may contain loops and parallel
arcs.
Output
the first line of the output file print W --- the minimal sum Bob must
have to remove all arcs from the graph. On the second line print K ---
the number of moves Bob needs to do it. After that print K lines that
describe Bob's moves. Each line must first contain the number of the
vertex and then '+' or '-' character, separated by one space. Character
'+' means that Bob removes all arcs incoming into the specified vertex
and '-' that Bob removes all arcs outgoing from the specified vertex.
Sample Input
3 6
1 2 3
4 2 1
1 2
1 1
3 2
1 2
3 1
2 3
Sample Output
5
3
1 +
2 -
2 +
#include <iostream>
#include <cstring>
#include <cstdio>
#include <queue>
using namespace std;
const int maxn=;
const int maxm=;
const int INF=;
int cnt,tot,fir[maxn],fron[maxn],dis[maxn];
int to[maxm],nxt[maxm],gap[maxn],path[maxn];
int cap[maxm];queue<int>q; struct Max_Flow{
void Init(int tot_=){
tot=tot_;cnt=;
memset(fir,,sizeof(fir));
memset(dis,,sizeof(dis));
memset(gap,,sizeof(gap));
} void add(int a,int b,int c){
nxt[++cnt]=fir[a];
fir[a]=cnt;
cap[cnt]=c;
to[cnt]=b;
} void addedge(int a,int b,int c){
add(a,b,c);
add(b,a,);
} bool BFS(int s,int t){
dis[t]=;q.push(t);
while(!q.empty()){
int x=q.front();q.pop();
for(int i=fir[x];i;i=nxt[i])
if(!dis[to[i]]){
dis[to[i]]=dis[x]+;
q.push(to[i]);
}
}
return dis[s];
} int Aug(int s,int t,int &p){
int f=INF;
while(p!=s){
f=min(f,cap[path[p]]);
p=to[path[p]^];
}p=t;
while(p!=s){
cap[path[p]]-=f;
cap[path[p]^]+=f;
p=to[path[p]^];
}
return f;
} int ISAP(int s,int t){
if(!BFS(s,t))return ;
for(int i=s;i<=t;i++)fron[i]=fir[i];
for(int i=s;i<=t;i++)gap[dis[i]]+=;
int p=s,ret=;
while(dis[s]<=tot){
if(p==t)ret+=Aug(s,t,p); for(int &i=fron[p];i;i=nxt[i])
if(cap[i]&&dis[p]==dis[to[i]]+){
path[p=to[i]]=i;
break;
} if(!fron[p]){
if(--gap[dis[p]]==)
break;
int Min=tot;
for(int i=fir[p];i;i=nxt[i])
if(cap[i])Min=min(Min,dis[to[i]]);
gap[dis[p]=Min+]+=;fron[p]=fir[p];
if(p!=s)p=to[path[p]^];
}
}
return ret;
}
}isap; int n,m,top;
int tag[maxn],st[maxn];
void DFS(int x){
tag[x]=;
for(int i=fir[x];i;i=nxt[i])
if(cap[i]&&!tag[to[i]])DFS(to[i]);
} int main(){
scanf("%d%d",&n,&m);
int s=,t=*n+;
isap.Init(t+);
for(int i=,v;i<=n;i++){
scanf("%d",&v);
isap.addedge(s,i,v);
}
for(int i=,v;i<=n;i++){
scanf("%d",&v);
isap.addedge(i+n,t,v);
}
for(int i=,a,b;i<=m;i++){
scanf("%d%d",&a,&b);
isap.addedge(b,a+n,INF);
} printf("%d\n",isap.ISAP(s,t));
DFS();
for(int i=;i<=n;i++){
if(!tag[i])
st[++top]=i;
if(tag[i+n])
st[++top]=i+n;
}
printf("%d\n",top);
for(int i=;i<=top;i++){
if(st[i]<=n)
printf("%d +\n",st[i]);
else
printf("%d -\n",st[i]-n);
}
return ;
}
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