You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.

Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.

For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.

Hint:

  1. If there are 5 stones in the heap, could you figure out a way to remove the stones such that you will always be the winner

    bool canWinNim(int n)
    {
    return n% != ;
    }

LeetCode292:Nim Game的更多相关文章

  1. [Swift]LeetCode292. Nim游戏 | Nim Game

    You are playing the following Nim Game with your friend: There is a heap of stones on the table, eac ...

  2. [LeetCode] Nim Game 尼姆游戏

    You are playing the following Nim Game with your friend: There is a heap of stones on the table, eac ...

  3. CodeForces - 662A Gambling Nim

    http://codeforces.com/problemset/problem/662/A 题目大意: 给定n(n <= 500000)张卡片,每张卡片的两个面都写有数字,每个面都有0.5的概 ...

  4. HDU 5795 A Simple Nim 打表求SG函数的规律

    A Simple Nim Problem Description   Two players take turns picking candies from n heaps,the player wh ...

  5. LeetCode 292. Nim Game

    Problem: You are playing the following Nim Game with your friend: There to stones. The one who remov ...

  6. 【SRM】518 Nim

    题意 \(K(1 \le K \le 10^9)\)堆石子,每堆石子个数不超过\(L(2 \le 50000)\),问Nim游戏中先手必败局面的数量,答案对\(10^9+7\)取模. 分析 容易得到\ ...

  7. HDU 2509 Nim博弈变形

    1.HDU 2509  2.题意:n堆苹果,两个人轮流,每次从一堆中取连续的多个,至少取一个,最后取光者败. 3.总结:Nim博弈的变形,还是不知道怎么分析,,,,看了大牛的博客. 传送门 首先给出结 ...

  8. HDU 1907 Nim博弈变形

    1.HDU 1907 2.题意:n堆糖,两人轮流,每次从任意一堆中至少取一个,最后取光者输. 3.总结:有点变形的Nim,还是不太明白,盗用一下学长的分析吧 传送门 分析:经典的Nim博弈的一点变形. ...

  9. Nim游戏

    目前有3堆石子,每堆石子个数也是任意的,双方轮流从中取出石子,规则如下:1)每一步应取走至少一枚石子:每一步只能从某一堆中取走部分或全部石子:2)如果谁不能取谁就失败. Bouton定理: 必败状态当 ...

随机推荐

  1. 51nod1294 修改数组

    看题解的...就是将必须要修改的数去掉后求最长的不递减子序列. upper_bound+lower_bound要理解.有时候-1有时候不用是有原因的. #include<cstdio> # ...

  2. poj 1195 mobile phone

    题目连接: 题意:要求设计这样一个数据结构,支持下列操作 1.add(x,y,a).对二维数组的第x行,第y列加上a. 2.sum(l,b,r,t).求所有满足l<=x<=r,b<= ...

  3. 新手学vim配置

    我是新手啦,以前都没接触过Vim编辑器,所以感觉不怎么顺手,毕竟还没有用习惯.也没有什么基础,所以在配置的时候就一直在网上查资料....想要把vim编辑器配置成VS的话可以参考这个:http://ww ...

  4. Hide/Show running Console

    http://stackoverflow.com/questions/3571627/show-hide-the-console-window-of-a-c-sharp-console-applica ...

  5. Android 系统属性

    /************************************************************************ * Android 系统属性 * 说明: * 由于需 ...

  6. PS4破解

    1.输入序列号: # 序列号: # 1330-1082-3503-2270-3738-6738# 1330-1776-8671-6289-7706-2916# 1330-1567-6599-8775- ...

  7. oracle数据库重建EM

    首先直接在文本控制台执行: [emca不像dbca.netca一样会出现图形化的界面,而是通过文本的交互式操作来完成重新配置]   emca -config dbcontrol db -repos   ...

  8. EIG集团简单介绍

    有朋友会问为什么要介绍EIG集团,他们是干什么的?与域名.主机.IDC行业资讯等有啥关系?EIG集团很牛逼么?带着这些疑问,简单的给大家做个介绍,希望能帮助大家了解这个IDC行业里面的“魔鬼”! EI ...

  9. Java多线程-工具篇-BlockingQueue

    前言: 在新增的Concurrent包中,BlockingQueue很好的解决了多线程中,如何高效安全“传输”数据的问题.通过这些高效并且线程安全的队列 类,为我们快速搭建高质量的多线程程序带来极大的 ...

  10. 使用JQuery Mobile实现手机新闻浏览器

    jQuery Mobile项目是jQuery项目下的在移动开发方面的又一力作,在本文中,笔者将带你一步步更深入学习使用jQuery Mobile框架去实现一个能在android手机上运行的新闻浏览器, ...