geeks上的解答复杂了些,用回溯就行了

 #include <iostream>
#include <vector>
#include <algorithm>
#include <queue>
#include <stack>
#include <string>
#include <fstream>
using namespace std; const int N = ;
vector<int> trace;
vector<bool> visit(N);
int graph[N][N] = {{, , , , },
{, , , , },
{, , , , },
{, , , , },
{, , , , }}; void cycle(int v) {
if (visit[v]) {
int beg = ;
for (; beg < trace.size(); ++beg)
if (trace[beg] == v) break;
for (int i = beg; i < trace.size(); i++) {
cout << trace[i] << " ";
}
cout << endl;
return;
}
visit[v] = true;
trace.push_back(v);
for (int i = ; i < N; i++) {
if (graph[v][i]) cycle(i);
}
trace.pop_back();
visit[v] = false;
} int main() {
cycle();
return ;
}

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