A Tour of Go Methods
Go does not have classes. However, you can define methods on struct types.
The method receiver appears in its own argument list between the func keyword and the method name.
package main import (
"fmt"
"math"
) type Vertex struct {
X, Y float64
}
func (v *Vertex) Abs() float64 {//相当于给类添加方法
return math.Sqrt(v.X * v.X + v.Y * v.Y)
}
func main() {
v := &Vertex{, }
fmt.Println(v.Abs())
}
A Tour of Go Methods的更多相关文章
- A Tour of Go Methods with pointer receivers
Methods can be associated with a named type or a pointer to a named type. We just saw two Abs method ...
- A Tour of Go Methods and Interfaces
The next group of slides covers methods and interfaces, the constructs that define objects and their ...
- A Tour of Go Methods continued
In fact, you can define a method on any type you define in your package, not just structs. You canno ...
- Go Methods and Interfaces
[Go Methods and Interfaces] 1.Go does not have classes. However, you can define methods on struct ty ...
- Go指南练习_图像
https://tour.go-zh.org/methods/25 一.题目描述 还记得之前编写的图片生成器吗?我们再来编写另外一个,不过这次它将会返回一个 image.Image 的实现而非一个数据 ...
- Go指南练习_rot13Reader
https://tour.go-zh.org/methods/23 一.题目描述 有种常见的模式是一个 io.Reader 包装另一个 io.Reader,然后通过某种方式修改其数据流. 例如,gzi ...
- Go指南练习_Reader
https://tour.go-zh.org/methods/22 一.题目描述 实现一个 Reader 类型,它产生一个 ASCII 字符 'A' 的无限流. 二.题目分析 io 包指定了 io.R ...
- Go指南练习_错误
源地址 https://tour.go-zh.org/methods/20 一.题目描述 从之前的练习中复制 Sqrt 函数,修改它使其返回 error 值. Sqrt 接受到一个负数时,应当返回一个 ...
- Go指南练习_Stringer
源地址 https://tour.go-zh.org/methods/18 一.题目描述 通过让 IPAddr 类型实现 fmt.Stringer 来打印点号分隔的地址. 例如,IPAddr{1, 2 ...
随机推荐
- java 读取文件中文乱码问题
很少写java io的代码,今天整了一个发现 本地调试好好的,放到jmeter里就打印乱码.一番折腾,终于搞定~直接上代码: List<Order> orderList = new Arr ...
- Win7 默认hosts文件
# Copyright (c) 1993-2009 Microsoft Corp. # # This is a sample HOSTS file used by Microsoft TCP/IP f ...
- Some projects cannot be imported because they already exist in the workspace
原文地址: Some projects cannot be imported because they already exist in the workspace - 浅尝辄止的博客 - 博客频道 ...
- 转:tar 常用命令
tar在linux上是常用的打包.压缩.加压缩工具,他的参数很多,折里仅仅列举常用的压缩与解压缩参数 参数: -c :create 建立压缩档案的参数: -x : 解压缩压缩档案的参数: -z : 是 ...
- (组合数学3.1.2.1)POJ 2249 Binomial Showdown(排列组合公式的实现)
/* * POJ_2249.cpp * * Created on: 2013年10月8日 * Author: Administrator */ #include <iostream> #i ...
- 排查Java线上服务故障的方法和实例分析
前言 作为在线系统负责人或者是一个技术专家,你可能刚刚接手一个项目就需要处理紧急故障,或者被要求帮忙处理一些紧急的故障,这个时候的情景是: (1)你可能对这个业务仅仅是听说过,而不怎么真正了解: (2 ...
- hdu 4642 Fliping game(博弈)
题目:http://acm.hdu.edu.cn/showproblem.php?pid=4642 题意:给定一个棋盘,0表示向下,1表示向上,选一个x,y, 然后翻转从x,y 到n,m.的所有硬币, ...
- 函数flst_init
/** The null file address */UNIV_INTERN fil_addr_t fil_addr_null = {FIL_NULL, 0}; /***************** ...
- UVa 1363 (数论 数列求和) Joseph's Problem
题意: 给出n, k,求 分析: 假设,则k mod (i+1) = k - (i+1)*p = k - i*p - p = k mod i - p 则对于某个区间,i∈[l, r],k/i的整数部分 ...
- shape的属性
<?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http: ...