"""
here are N network nodes, labelled 1 to N.
Given times, a list of travel times as directed edges times[i] = (u, v, w), where u is the source node, v is the target node, and w is the time it takes for a signal to travel from source to target.
Now, we send a signal from a certain node K. How long will it take for all nodes to receive the signal? If it is impossible, return -1.
Example 1:
Input: times = [[2,1,1],[2,3,1],[3,4,1]], N = 4, K = 2
Output: 2
"""
"""
此题很经典,是求源点到目标结点的最短路径
Dijkstra算法,纯模板题。
时间复杂度是O(N^2 + E),空间复杂度是O(N+E).
"""
class Solution1:
def networkDelayTime(self, times, N, K):
"""
:type times: List[List[int]]
:type N: int
:type K: int
:rtype: int
"""
dist = [float('inf')] * N
dist[K - 1] = 0 #K-1是存到距离数组的下标
for i in range(N): #N个结点,遍历N遍更新最短路径
for time in times:
u = time[0] - 1 #减1是为了dist的下标一致
v = time[1] - 1
w = time[2]
dist[v] = min(dist[v], dist[u] + w) #更新最短路径
return -1 if float('inf') in dist else max(dist) ss = Solution1()
ss.networkDelayTime([[1, 2, 1], [2, 3, 7], [1, 3, 4], [2, 1, 2]], 3, 2)

leetcode743 Network Delay Time的更多相关文章

  1. 【LeetCode】743. Network Delay Time 解题报告(Python)

    [LeetCode]743. Network Delay Time 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: ht ...

  2. [Swift]LeetCode743. 网络延迟时间 | Network Delay Time

    There are N network nodes, labelled 1 to N. Given times, a list of travel times as directededges tim ...

  3. [LeetCode] Network Delay Time 网络延迟时间

    There are N network nodes, labelled 1 to N. Given times, a list of travel times as directed edges ti ...

  4. [LeetCode] Network Delay Time 网络延迟时间——最短路算法 Bellman-Ford(DP) 和 dijkstra(本质上就是BFS的迭代变种)

    There are N network nodes, labelled 1 to N. Given times, a list of travel times as directed edges ti ...

  5. 743. Network Delay Time

    题目来源: https://leetcode.com/problems/network-delay-time/ 自我感觉难度/真实难度: 题意: 分析: 自己的代码: class Solution: ...

  6. [LeetCode] 743. Network Delay Time 网络延迟时间

    There are N network nodes, labelled 1 to N. Given times, a list of travel times as directededges tim ...

  7. LeetCode 743. Network Delay Time

    原题链接在这里:https://leetcode.com/problems/network-delay-time/ 题目: There are N network nodes, labelled 1  ...

  8. 【leetcode】Network Delay Time

    题目: There are N network nodes, labelled 1 to N. Given times, a list of travel times as directed edge ...

  9. 排队时延(Queuing delay)

    网络时延的构成 Network delay including four parts: Processing delay - time routers take to process the pack ...

随机推荐

  1. 吴裕雄 python 神经网络——TensorFlow 自定义损失函数

    import tensorflow as tf from numpy.random import RandomState batch_size = 8 x = tf.placeholder(tf.fl ...

  2. 安装Ubuntu后的一些配置

    Ubuntu安装的一些配置 搜狗拼音的安装 卸载ibus和它的配置, 卸载顶部面板的键盘指示 sudo apt remove ibus sudo apt purge ibus sudo apt rem ...

  3. 修改oracle数据库用户密码的方法

    WIN+R打开运行窗口,输入cmd进入命令行: 输入sqlplus ,输入用户名,输入口令(如果是超级管理员SYS的话需在口令之后加上as sysdba)进入sql命令行:    连接成功后,输入“s ...

  4. Spring、SpringMvc、MyBatis 整合

    web.xml   SSMProject示例项目下载    SSMProject_jar包 <?xml version="1.0" encoding="UTF-8& ...

  5. 【PAT甲级】1042 Shuffling Machine (20 分)

    题意: 输入洗牌次数K(<=20),输入54张牌每次洗入的位置(不是交换的位置),输出洗好的牌. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC ...

  6. ajax发送GET和POST请求

    1.ajax-get请求demo <script> document.getElementById("buttonname").onclik=function(){ / ...

  7. JS清除空格之trim()方法

    JQ: $.trim() 函数用于去除字符串两端的空白字符. 注意:$.trim()函数会移除字符串开始和末尾处的所有换行符,空格(包括连续的空格)和制表符.如果这些空白字符在字符串中间时,它们将被保 ...

  8. nodejs的forEach不支持break打断

  9. stack的使用-Hdu 1062

    Text Reverse Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Tota ...

  10. kubernetes从入门到放弃(二)

    kubernetes对象之pod 1.pod的认识 Pod直译是豆荚,可以把容器想像成豆荚里的豆子,把一个或多个关系紧密的豆子包在一起就是豆荚(一个Pod).在Kubernetes中我们不会直接操作容 ...