SQLAlchemy 操作方法汇总

参考

1、查询：

   #简单查询
    print(session.query(User).all())
    print(session.query(User.name, User.fullname).all())
    print(session.query(User, User.name).all())

    #带条件查询
    print(session.query(User).filter_by(name='user1').all())
    print(session.query(User).filter(User.name == "user").all())
    print(session.query(User).filter(User.name.like("user%")).all())

    #多条件查询
    print(session.query(User).filter(and_(User.name.like("user%"), User.fullname.like("first%"))).all())
    print(session.query(User).filter(or_(User.name.like("user%"), User.password != None)).all())

    #sql过滤
    print(session.query(User).filter("id>:id").params(id=1).all())

    #关联查询
    print(session.query(User, Address).filter(User.id == Address.user_id).all())
    print(session.query(User).join(User.addresses).all())
    print(session.query(User).outerjoin(User.addresses).all())

    #聚合查询
    print(session.query(User.name, func.count('*').label("user_count")).group_by(User.name).all())
    print(session.query(User.name, func.sum(User.id).label("user_id_sum")).group_by(User.name).all())

    #子查询
    stmt = session.query(Address.user_id, func.count('*').label("address_count")).group_by(Address.user_id).subquery()
    print(session.query(User, stmt.c.address_count).outerjoin((stmt, User.id == stmt.c.user_id)).order_by(User.id).all())

    #exists
    print(session.query(User).filter(exists().where(Address.user_id == User.id)))
    print(session.query(User).filter(User.addresses.any()))
　　#限制返回字段查询

　　person = session.query(Person.name, Person.created_at,
             Person.updated_at).filter_by(name="zhongwei").order_by(
             Person.created_at).first()

记录总数查询

from sqlalchemy import func

# count User records, without
# using a subquery.
session.query(func.count(User.id))

# return count of user "id" grouped
# by "name"
session.query(func.count(User.id)).\
        group_by(User.name)

from sqlalchemy import distinct

# count distinct "name" values
session.query(func.count(distinct(User.name)))