Lintcode482-Binary Tree Level Sum-Easy

482. Binary Tree Level Sum

Given a binary tree and an integer which is the depth of the target level.

Calculate the sum of the nodes in the target level.

Example

Example 1:

Input:

     1
   /   \
  2     3
 / \   / \
4   5 6   7
   /       \
  8         9
and depth=2
Output:5 

Example 2:

Input:

     1
   /   \
  2     3
 / \   / \
4   5 6   7
   /       \
  8         9
and depth=3
Output:22

 

思路：递归法

注意：

1. sum 定义为类成员变量

代码：

/**
 * Definition of TreeNode:
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left, right;
 *     public TreeNode(int val) {
 *         this.val = val;
 *         this.left = this.right = null;
 *     }
 * }
 */

public class Solution {
    /**
     * @param root: the root of the binary tree
     * @param level: the depth of the target level
     * @return: An integer
     */
    int sum = 0;
    public int levelSum(TreeNode root, int level) {
       helper(root, 1, level);
       return sum;
    }
    public void helper(TreeNode root, int depth, int level) {
        if (root == null) {
            return;
        }

        if (depth == level) {
            sum += root.val;
            return;
        }

        helper(root.left, depth + 1, level);
        helper(root.right, depth + 1, level);
    }
}