1269. Obscene Words Filter

Time limit: 0.5 second
Memory limit: 8 MB
There is a problem to check messages of web-board visitors for the obscene words. Your elder colleagues commit this problem to you. You are to write a program, which check if there is at least one obscene word from the given list in the given text as a substring.

Input

The first line consists of integer n (1 ≤ n ≤ 10000) — an amount of words. The next n lines contain the list of words that we can’t allow to use in our well-educated society. A word may contain any symbol but the ones with codes 0, 10 and 13. The length of each word doesn’t exceed 10000 symbols. The total list of words doesn’t exceed 100 KB. Then there is an integer m — the number of lines of the text. A size of the text doesn’t exceed 900 KB.

Output

the number of line and the number of position separated with a space, where an obscene word occurs for the first time. If there are no obscene words, output “Passed”.

Sample

input output
5
dear
sweetie
angel
dream
baby
8
Had I the heavens' embroidered cloths,
Enwrought with golden and silver light,
The blue and the dim and the dark cloths
Of night and light and the half-light,
I would spread the cloths under your feet:
But I, being poor, have only my dreams;
I have spread my dreams under your feet;
Tread softly because you tread on my dreams.
6 33
Problem Author: Pavel Atnashev
Problem Source: Ural State University championship, October 25, 2003
Difficulty: 832
 
题意:问在文章中第一次出现禁忌单词的地方
分析:AC自动机,但这题卡时间卡内存
链表?边目录?No,卡时间
数组?对了一半,卡空间
所以,只能动态的分配孩子的空间
 #include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
#define For(i, s, t) for(int i = (s); i <= (t); i++)
#define INF (1000000001) const int N = ;
struct TreeType
{
char C;
int Next;
int *Child;
unsigned short Len, CLen, Size;
} Tree[N];
//int First[N], To[N], Next[N], Tot;
int n, m, Cnt, Ans = INF;
char Str[N * ];
int Q[N]; /*inline void Insert(int u, int v)
{
Tot++;
To[Tot] = v, Next[Tot] = First[u];
First[u] = Tot;
}*/ inline void Updata(TreeType &T)
{
T.Size += ;
int *p = new int[T.Size + ];
for(int i = ; i < T.CLen; i++) p[i] = T.Child[i];
delete []T.Child;
T.Child = p;
} inline void Ins(char *Str)
{
int Length = strlen(Str + ), x = , Tab;
bool Flag;
For(i, , Length)
{
Flag = ;
/*for(Tab = First[x]; Tab; Tab = Next[Tab])
if(Tree[To[Tab]].C == Str[i])
{
Flag = 1;
x = To[Tab];
break;
}*/
for(Tab = ; Tab < Tree[x].CLen; Tab++)
if(Tree[Tree[x].Child[Tab]].C == Str[i])
{
Flag = , x = Tree[x].Child[Tab];
break;
}
if(!Flag)
{
//Insert(x, ++Cnt);
if(Tree[x].CLen >= Tree[x].Size) Updata(Tree[x]);
Tree[x].Child[Tree[x].CLen++] = ++Cnt;
Tree[Cnt].C = Str[i], x = Cnt;
}
}
Tree[x].Len = Length;
} inline void Input()
{
scanf("%d", &n);
getchar();
For(i, , n)
{
gets(Str + );
Ins(Str);
}
} inline void Build()
{
int Head = , Tail = ;
int u, v, Tab, k, vv;
//for(Tab = First[0]; Tab; Tab = Next[Tab])
for(Tab = ; Tab < Tree[].CLen; Tab++)
Q[++Tail] = Tree[].Child[Tab];
while(Head <= Tail)
{
u = Q[Head++];
//for(Tab = First[u]; Tab; Tab = Next[Tab])
for(Tab = ; Tab < Tree[u].CLen; Tab++)
{
v = Tree[u].Child[Tab];
if(!v) continue;
//for(k = First[Tree[u].Next]; k; k = Next[k])
for(k = ; k < Tree[Tree[u].Next].CLen; k++)
if(Tree[vv = Tree[Tree[u].Next].Child[k]].C == Tree[v].C)
{
Tree[v].Next = vv;
if(Tree[v].Len < Tree[vv].Len)
Tree[v].Len = Tree[vv].Len;
break;
}
Q[++Tail] = v;
}
}
} inline void Solve()
{
//printf("%d\n", Cnt);
Build();
scanf("%d", &m), getchar();
int Length, x, Tab;
bool Flag;
For(Now, , m)
{
gets(Str + );
Length = strlen(Str + ), x = ;
For(i, , Length)
{
do
{
Flag = ;
//for(Tab = First[x]; Tab; Tab = Next[Tab])
for(Tab = ; Tab < Tree[x].CLen; Tab++)
if(Tree[Tree[x].Child[Tab]].C == Str[i])
{
x = Tree[x].Child[Tab], Flag = ;
break;
}
if(!Flag)
{
x = Tree[x].Next;
continue;
}
if(Tree[x].Len)
{
if(Ans > i - Tree[x].Len + ) Ans = i - Tree[x].Len + ;
}
break;
} while(x); }
if(Ans != INF)
{
printf("%d %d\n", Now, Ans);
return;
}
}
printf("Passed\n");
} int main()
{
freopen("F.in", "r", stdin);
freopen("F.out", "w", stdout);
Input();
Solve();
return ;
}

ural 1269. Obscene Words Filter的更多相关文章

  1. django 操作数据库--orm(object relation mapping)---models

    思想 django为使用一种新的方式,即:关系对象映射(Object Relational Mapping,简称ORM). PHP:activerecord Java:Hibernate C#:Ent ...

  2. JavaScript Array -->map()、filter()、reduce()、forEach()函数的使用

    题目: 1.得到 3000 到 3500 之内工资的人. 2.增加一个年龄的字段,并且计算其年龄. 3.打印出每个人的所在城市 4.计算所有人的工资的总和. 测试数据: function getDat ...

  3. JavaWeb——Filter

    一.基本概念 之前我们用一篇博文介绍了Servlet相关的知识,有了那篇博文的知识积淀,今天我们学习Filter将会非常轻松,因为Filter有很多地方和Servlet类似,下面在讲Filter的时候 ...

  4. 以bank account 数据为例,认识elasticsearch query 和 filter

    Elasticsearch 查询语言(Query DSL)认识(一) 一.基本认识 查询子句的行为取决于 query context filter context 也就是执行的是查询(query)还是 ...

  5. AngularJS过滤器filter-保留小数,小数点-$filter

    AngularJS      保留小数 默认是保留3位 固定的套路是 {{deom | number:4}} 意思就是保留小数点 的后四位 在渲染页面的时候 加入这儿个代码 用来精确浮点数,指定小数点 ...

  6. 挑子学习笔记:特征选择——基于假设检验的Filter方法

    转载请标明出处: http://www.cnblogs.com/tiaozistudy/p/hypothesis_testing_based_feature_selection.html Filter ...

  7. [模拟电路] 2、Passive Band Pass Filter

    note: Some articles are very good in http://www.electronics-tutorials.ws/,I share them in the Cnblog ...

  8. AngularJS过滤器filter-时间日期格式-渲染日期格式-$filter

    今天遇到了这些问题索性就 写篇文章吧 话不多说直接上栗子 不管任何是HTML格式还是JS格式必须要在  controller 里面写 // new Date() 获取当前时间 yyyy-MM-ddd ...

  9. 《ES6基础教程》之 map、forEach、filter indexOf 用法

    1,map,对数组的每个元素进行一定操作,返回一个新的数组. var oldArr = [{first_name:"Colin",last_name:"Toh" ...

随机推荐

  1. 解决ie文本框不能输入和获取焦点问题

    解决办法:    从正常的机器上拷贝c:\windows\system32\mshtmled.dll到本机的system32目录下即可.或者从安装盘中提取该文件.    加载mshtmled.dll: ...

  2. rails获取json内容

    文章是从我的个人博客上粘贴过来的, 大家也可以访问 www.iwangzheng.com url点开后的json是这样的 { e:   { provider: ”searches.soku.top”, ...

  3. Jackson 框架,轻易转换JSON

    Jackson 框架,轻易转换JSON Jackson可以轻松的将Java对象转换成json对象和xml文档,同样也可以将json.xml转换成Java对象. 前面有介绍过json-lib这个框架,在 ...

  4. HTML5 自制本地网页视频播放器

    HTML5初试:本地视频用网页打开啦半个广告都可以没有,看来暴风什么的快要淘汰了. 视频格式还是有要求的,看来要备一个转码器. 格式 IE Firefox Opera Chrome Safari Og ...

  5. macbook air 安装win7双系统

    转自: http://jingyan.baidu.com/article/6d704a13f99f1a28da51ca49.html 1)遇到“No bootable device-insert bo ...

  6. VIM替换、截取及追加操作

    参考: http://blog.csdn.net/love__coder/article/details/6739670 http://blog.csdn.net/love__coder/articl ...

  7. 【转】Mybatis/Ibatis,数据库操作的返回值

    该问题,我百度了下,根本没发现什么有价值的文章:还是看源代码(详见最后附录)中的注释,最有效了!insert,返回值是:新插入行的主键(primary key):需要包含<selectKey&g ...

  8. tesseract3.02识别验证码需要注意的问题

    1.安装tesseract3.02后,在命令行里输入tesseract,看能否出现使用方法,不出现则是环境变量问题,可调整其顺序. 2.找到如下文件 C:\Python27\Lib\site-pack ...

  9. Android ViewPager轮播图

    Android客户端开发中很多时候需要用到轮播图的方式进行重点新闻的推送或者欢迎页面的制作,下面这个轮播图效果的Deamo来自互联网再经过修改而成. 1.布局文件activity_main.xml中添 ...

  10. Sql Server 深入的探讨锁机制

    一: 当select遇到性能低下的update会怎么样? 1. 还是使用原始的person表,插入6条数据,由于是4000字节,所以两条数据就是一个数据页,如下图: 1 DROP TABLE dbo. ...