time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Students in a class are making towers of blocks. Each student makes a (non-zero) tower by stacking pieces lengthwise on top of each other. n of the students use pieces made of two blocks and m of the students use pieces made of three blocks.

The students don’t want to use too many blocks, but they also want to be unique, so no two students’ towers may contain the same number of blocks. Find the minimum height necessary for the tallest of the students' towers.

Input

The first line of the input contains two space-separated integers n and m (0 ≤ n, m ≤ 1 000 000, n + m > 0) — the number of students using two-block pieces and the number of students using three-block pieces, respectively.

Output

Print a single integer, denoting the minimum possible height of the tallest tower.

Examples
Input
1 3
Output
9
Input
3 2
Output
8
Input
5 0
Output
10
Note

In the first case, the student using two-block pieces can make a tower of height 4, and the students using three-block pieces can make towers of height 3, 6, and 9 blocks. The tallest tower has a height of 9 blocks.

In the second case, the students can make towers of heights 2, 4, and 8 with two-block pieces and towers of heights 3 and 6 with three-block pieces, for a maximum height of 8 blocks.

题意就是n个人用2的倍数,m个人用3的倍数,然后所有人要求数不一样,要使得最大的数最小,输出结果。

二分讨论2的倍数,3的倍数,6的倍数,然后注意一下边界,wa在边界上了。。。

代码:

#include<bits/stdc++.h>
using namespace std;
int main(){
int n,m,l,r,mid,ans;
int a,b,c;
while(~scanf("%d%d",&n,&m)){
int l=1,r=1e8;
while(l<=r){
mid=(l+r)/2;
a=mid/2;
b=mid/3;
c=mid/6;
if(a>=n&&b>=m&&a+b-c>=n+m){
ans=mid;
r=mid-1;
}
else
l=mid+1;
}
printf("%d\n",ans);
}
return 0;
}

智障萌新,加油(ง •_•)ง

Codeforces 626 C. Block Towers-二分 (8VC Venture Cup 2016-Elimination Round)的更多相关文章

  1. 8VC Venture Cup 2016 - Elimination Round C. Block Towers 二分

    C. Block Towers 题目连接: http://www.codeforces.com/contest/626/problem/C Description Students in a clas ...

  2. 8VC Venture Cup 2016 - Elimination Round

    在家补补题   模拟 A - Robot Sequence #include <bits/stdc++.h> char str[202]; void move(int &x, in ...

  3. 8VC Venture Cup 2016 - Elimination Round (C. Block Towers)

    题目链接:http://codeforces.com/contest/626/problem/C 题意就是给你n个分别拿着2的倍数积木的小朋友和m个分别拿着3的倍数积木的小朋友,每个小朋友拿着积木的数 ...

  4. 8VC Venture Cup 2016 - Elimination Round E. Simple Skewness 暴力+二分

    E. Simple Skewness 题目连接: http://www.codeforces.com/contest/626/problem/E Description Define the simp ...

  5. codeforces 8VC Venture Cup 2016 - Elimination Round C. Lieges of Legendre

    C. Lieges of Legendre 题意:给n,m表示有n个为2的倍数,m个为3的倍数:问这n+m个数不重复时的最大值 最小为多少? 数据:(0 ≤ n, m ≤ 1 000 000, n + ...

  6. Codeforces 8VC Venture Cup 2016 - Elimination Round F. Group Projects 差分DP*****

    F. Group Projects   There are n students in a class working on group projects. The students will div ...

  7. 8VC Venture Cup 2016 - Elimination Round G. Raffles 线段树

    G. Raffles 题目连接: http://www.codeforces.com/contest/626/problem/G Description Johnny is at a carnival ...

  8. 8VC Venture Cup 2016 - Elimination Round F. Group Projects dp

    F. Group Projects 题目连接: http://www.codeforces.com/contest/626/problem/F Description There are n stud ...

  9. 8VC Venture Cup 2016 - Elimination Round D. Jerry's Protest 暴力

    D. Jerry's Protest 题目连接: http://www.codeforces.com/contest/626/problem/D Description Andrew and Jerr ...

随机推荐

  1. delphi Edit 控制最大值,只能输入数字型 控制小数位数

    delphi语言受众多程序员追捧,主要原因之一就是它有很多第三方的控件可供使用.很多资深的delphi程序员都把自己积累的函数.过程等设计成控件,以方便使用,提高开发效率. 本文通过一个只允许输入数字 ...

  2. 【bzoj1977】[BeiJing2010组队]次小生成树 Tree 最小生成树+权值线段树合并

    题目描述 求一张图的严格次小生成树的边权和,保证存在. 输入 第一行包含两个整数N 和M,表示无向图的点数与边数. 接下来 M行,每行 3个数x y z 表示,点 x 和点y之间有一条边,边的权值为z ...

  3. jenkins+Docker持续化部署(笔记)

    参考资料:https://www.cnblogs.com/leolztang/p/6934694.html (Jenkins(Docker容器内)使用宿主机的docker命令) https://con ...

  4. 在.net2.0下使用System.Web.Script.Serialization;

    最近,在弄json字符串转为对象.需要添加这个引用System.Web.Script.Serialization;因为版本必须是dotnet2.0的原因,发现很多解决方案不适合自己.故使用这种解决办法 ...

  5. BZOJ4651 NOI2016网格(割点)

    首先显然可以通过孤立角落里的跳蚤使其不连通,所以只要有解答案就不会大于2.同样显然的一点是当且仅当跳蚤数量<=2且连通时无解.做法其实也很显然了:特判无解,若跳蚤不连通输出0,否则看图中是否无割 ...

  6. URAL1696 Salary for Robots

    题目戳这里. 最长下降子序列单调队列求法. \(f_{i,j,k}\)表示考虑前\(i\)个数,\(g_1 = j,g_2 = k\)的方案数.转移: \[f_{i,j,k} = \sum_{p = ...

  7. React生命周期总结

    React的生命周期总共8个钩子,三个will,两个Did,一个RecciveProps,一个ShouldUpdate,一个render.分为三个阶段,分别是 装载 Mounting更新 Updati ...

  8. [USACO08DEC] 秘密消息Secret Message

    题目描述 Bessie is leading the cows in an attempt to escape! To do this, the cows are sending secret bin ...

  9. angular的一些问题

    引入第三方类库 1.安装依赖 npm install jquey --save 2.引入项目 在angular-cli.json "scripts": [ "../nod ...

  10. 在Global.asax中过滤POST请求的非法参数。

    using System;using System.Collections.Generic;using System.Collections.Specialized;using System.Linq ...