题目原文:

Implement a queue with two stacks so that each queue operations takes a constant amortized number of stack operations.

题目要求用栈实现队列的所有操作。

 package week2;

 import java.util.Stack;

 /**
* Queue with two stacks. Implement a queue with two stacks so that each queue
* operations takes a constant amortized number of stack operations
* @author yangjingjing
*
*/
public class QueueWith2Stacks<E>{
Stack<E> inStack = new Stack<E>();
Stack<E> outStack = new Stack<E>();
public boolean isEmpty(){
if(inStack.isEmpty() && outStack.isEmpty())
return true;
else return false;
}
public int size(){
return (inStack.size() + outStack.size());
}
public void enqueue(E item){
inStack.push(item);
}
public E dequeue(){
if(outStack.isEmpty()){
if(inStack.isEmpty()) return null;
else{
while(!inStack.isEmpty()) {
outStack.push(inStack.pop());
}
return outStack.pop();
}
}else{
return outStack.pop();
}
}
public static void main(String[] args) {
QueueWith2Stacks<Object> queue = new QueueWith2Stacks<Object>();
queue.enqueue("a");
queue.enqueue("b");
queue.enqueue("c");
System.out.println(queue.dequeue());
queue.enqueue(1);
queue.enqueue(2);
Object o = null;
while((o = queue.dequeue()) != null) {
System.out.println(o);
}
}
}

Coursera Algorithms week2 栈和队列 练习测验: Queue with two stacks的更多相关文章

  1. Coursera Algorithms week2 栈和队列 练习测验: Stack with max

    题目原文: Stack with max. Create a data structure that efficiently supports the stack operations (push a ...

  2. Coursera Algorithms Programming Assignment 2: Deque and Randomized Queue (100分)

    作业原文:http://coursera.cs.princeton.edu/algs4/assignments/queues.html 这次作业与第一周作业相比,稍微简单一些.有三个编程练习:双端队列 ...

  3. LeetCode 232题用栈实现队列(Implement Queue using Stacks) Java语言求解

    题目链接 https://leetcode-cn.com/problems/implement-queue-using-stacks/ 题目描述 使用栈实现队列的下列操作: push(x) -- 将一 ...

  4. C#LeetCode刷题之#232-用栈实现队列​​​​​​​​​​​​​​(Implement Queue using Stacks)

    问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4108 访问. 使用栈实现队列的下列操作: push(x) -- ...

  5. Coursera Algorithms week2 基础排序 练习测验: Dutch national flag 荷兰国旗问题算法

    第二周课程的Elementray Sorts部分练习测验Interview Questions的第3题荷兰国旗问题很有意思.题目的原文描述如下: Dutch national flag. Given ...

  6. Coursera Algorithms week2 基础排序 练习测验: Permutation

    题目原文: Given two integer arrays of size n , design a subquadratic algorithm to determine whether one ...

  7. Coursera Algorithms week2 基础排序 练习测验: Intersection of two sets

    题目原文: Given two arrays a[] and b[], each containing n distinct 2D points in the plane, design a subq ...

  8. Coursera Algorithms week4 基础标签表 练习测验:Inorder traversal with constant extra space

    题目原文: Design an algorithm to perform an inorder traversal of a binary search tree using only a const ...

  9. Coursera Algorithms week4 基础标签表 练习测验:Check if a binary tree is a BST

    题目原文: Given a binary tree where each 

随机推荐

  1. 转:selenium自动化脚本错误总结

    https://blog.csdn.net/zxy987872674/article/details/53141118

  2. CAD处理键盘按钮被释放(com接口VB语言)

    主要用到函数说明: MxDrawXCustomEvent::KeyUp 键盘按钮被释放,详细说明如下: 参数 说明 iVk 是按钮码,如F8,的值为#define VK_F8 0x77 返回0消息继续 ...

  3. 【原】Pchart生成图片

    学习网址: http://wiki.pchart.net/doc.introduction.html http://pchart.sourceforge.net/index.php

  4. Windows压缩包安装MySQL

    一.下载zip版本 下载网址(如果浏览器下载很慢可以使用迅雷) http://dev.mysql.com/downloads/mysql/ 二.解压将得到的文件放置到任意目录 如果解压后的文件里没有d ...

  5. C#学习笔记_12_枚举&结构体

    12_枚举&结构体 枚举 是一种数据类型 适用于某些取值范围有限的数据 语法: [访问权限修饰符] enum 枚举名 { 枚举值 } 枚举名遵循大驼峰命名法 枚举一般情况下是和switch c ...

  6. 第六节:pandas函数应用

    1.pipe() :表格函数应用: 2.apply():表格行列函数应用: 3.applymap():表格元素应用.

  7. VS2017git 提交提示错误 Git failed with a fatal error.

    具体错误信息:Git failed with a fatal error.error: open("ConsoleApp1/.vs/ConsoleApp1/v15/Server/sqlite ...

  8. 【codeforces 527B】Error Correct System

    [题目链接]:http://codeforces.com/contest/527/problem/B [题意] 给你两个字符串; 允许你交换一个字符串的两个字符一次: 问你这两个字符串最少会有多少个位 ...

  9. (39.4) Spring Boot Shiro权限管理【从零开始学Spring Boot】

    在读此文章之前您还可能需要先了解: (39.1) Spring Boot Shiro权限管理[从零开始学Spring Boot] http://412887952-qq-com.iteye.com/b ...

  10. hdu_1048_The Hardest Problem Ever_201311052052

    The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java ...