来源:https://leetcode.com/problems/implement-queue-using-stacks

Implement the following operations of a queue using stacks.

  • push(x) -- Push element x to the back of queue.
  • pop() -- Removes the element from in front of queue.
  • peek() -- Get the front element.
  • empty() -- Return whether the queue is empty.

Notes:

  • You must use only standard operations of a stack -- which means only push to toppeek/pop from topsize, and is emptyoperations are valid.
  • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
  • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

栈A负责push,栈B负责pop和peek,当pop或peek时,如果栈B没有元素,就将栈A中的内容按栈的pop顺序push到栈B中

Java

 class MyQueue {
Stack<Integer> input;
Stack<Integer> output;
/** Initialize your data structure here. */
public MyQueue() {
input = new Stack<Integer>();
output = new Stack<Integer>();
} /** Push element x to the back of queue. */
public void push(int x) {
input.push(x);
} /** Removes the element from in front of queue and returns that element. */
public int pop() {
peek();
return output.pop();
} /** Get the front element. */
public int peek() {
if(output.empty()) {
int len = input.size();
for(int i=0; i<len; i++) {
output.push(input.pop());
}
}
return output.peek();
} /** Returns whether the queue is empty. */
public boolean empty() {
return input.empty() && output.empty();
}
} /**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/

Python

 class MyQueue(object):
i_stack = []
o_stack = []
def __init__(self):
"""
Initialize your data structure here.
"""
self.i_stack = []
self.o_stack = [] def push(self, x):
"""
Push element x to the back of queue.
:type x: int
:rtype: void
"""
self.i_stack.append(x) def pop(self):
"""
Removes the element from in front of queue and returns that element.
:rtype: int
"""
self.peek()
return self.o_stack.pop() def peek(self):
"""
Get the front element.
:rtype: int
"""
if len(self.o_stack) == 0:
i_len = len(self.i_stack)
for i in range(i_len):
self.o_stack.append(self.i_stack.pop())
return self.o_stack[-1] def empty(self):
"""
Returns whether the queue is empty.
:rtype: bool
"""
return len(self.i_stack) == 0 and len(self.o_stack) == 0 # Your MyQueue object will be instantiated and called as such:
# obj = MyQueue()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.peek()
# param_4 = obj.empty()

Implement Queue using Stacks(用两个栈实现队列)的更多相关文章

  1. LeetCode 232. 用栈实现队列(Implement Queue using Stacks) 4

    232. 用栈实现队列 232. Implement Queue using Stacks 题目描述 使用栈实现队列的下列操作: push(x) -- 将一个元素放入队列的尾部. pop() -- 从 ...

  2. [CareerCup] 3.5 Implement Queue using Two Stacks 使用两个栈来实现队列

    3.5 Implement a MyQueue class which implements a queue using two stacks. LeetCode上的原题,请参见我之前的博客Imple ...

  3. leetcode:Implement Stack using Queues 与 Implement Queue using Stacks

    一.Implement Stack using Queues Implement the following operations of a stack using queues. push(x) - ...

  4. LeetCode 232 Implement Queue using Stacks

    Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of ...

  5. Lintcode: Implement Queue by Stacks 解题报告

    Implement Queue by Stacks 原题链接 : http://lintcode.com/zh-cn/problem/implement-queue-by-stacks/# As th ...

  6. Leetcode 232 Implement Queue using Stacks 和 231 Power of Two

    1. 232 Implement Queue using Stacks 1.1 问题描写叙述 使用栈模拟实现队列.模拟实现例如以下操作: push(x). 将元素x放入队尾. pop(). 移除队首元 ...

  7. Leetcode 232 Implement Queue using Stacks STL

    本题用两个栈实现队列,用栈的基本操作去实现队列的所有基本操作push(),pop(),peek()以及empty() sa作为输入栈,sb作为输出栈,将sa输入元素的反转过来放到sb中 push与sa ...

  8. 【LeetCode】232 & 225 - Implement Queue using Stacks & Implement Stack using Queues

    232 - Implement Queue using Stacks Implement the following operations of a queue using stacks. push( ...

  9. 232. Implement Queue using Stacks,225. Implement Stack using Queues

    232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Im ...

  10. leetcode 155. Min Stack 、232. Implement Queue using Stacks 、225. Implement Stack using Queues

    155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } v ...

随机推荐

  1. 特殊权限位:suid、sgid、sticky

    linux系统特殊权限位 suid.sgid.stickysuid 使任意用户获得用文件属主相同的权限,sgid使用户获得与文件属组相同的权限(通过sgid获得的权限等同于同一用户组的权限) 表示方法 ...

  2. python 获取系统环境变量 os.environ and os.putenv

    从一段code说起 “if "BATCH_CONFIG_INI" in os.environ:” 判断环境变量的值有没有定义 如果定义的话就去环境变量的值,否则就取当前目录下的co ...

  3. quartz 时间配置

    Quartz中时间表达式的设置-----corn表达式 (注:这是让我看比较明白的一个博文,但是抱歉,没有找到原作者,如有侵犯,请告知) 时间格式: <!-- s m h d m w(?) y( ...

  4. 关于Ubuntu 14.04 安装Oracle 11gR2安装步骤(从开始到放弃--最终使用docker获取)

    最近在复习Oracle的相关内容,好准备在下一份工作中能够熟练一些,所以准备在自己虚拟机中安装Oracle的11gR2版本,主要参考内容为: https://blog.csdn.net/qq_4025 ...

  5. 【微信小程序】基础组件--view text image

    组件的通用属性: id class style hidden bind* catch* data-* view 小程序基础组件,基本等于最常用组件,类似于HTML中的div.view用于构建页面骨架, ...

  6. JavaScript正则表达式简介(一)

    一.正则表达式 正则表达式Regular Expression,可以简写为regexp.regex或是RE. 正则表达式使用单个字符串来描述或是匹配一系列符合某个句法规则的字符串模型. 按照某种规则去 ...

  7. 计蒜客 T2237 魔法 分类讨论

    Code: #include<bits/stdc++.h> #define setIO(s) freopen(s".in","r",stdin) # ...

  8. BZOJ 2097: [Usaco2010 Dec]Exercise 奶牛健美操 二分 + 贪心 + 树上问题

    Code: #include<bits/stdc++.h> using namespace std; #define setIO(s) freopen(s".in",& ...

  9. android 启动默认的邮件客户端,多附件的问题

    目前开发的app中需要发送邮件,所以需要调用android默认的邮件客户端,并需要添加多个邮件附件,我该通过哪个组件调用默认的客户端?用什么组件来支持多个附件的电子邮件? 是通过下面的哪一个?(Int ...

  10. IDEA集成java编程规范插件

    第一种:如图所示搜索 Alibaba Java Coding Guidelines(阿里巴巴) 安装完成后,重启idea,点击tools>阿里巴巴编程>编程规约扫描 即可