Leetcode4__findMedianSortedArrays

findMedianSortedArrays

基本思路：通过指针按顺序移动来判断大小顺序，思路和有一道用链表求中间值一样；

class Solution {
    public double findMedianSortedArrays(int[] nums1, int[] nums2) {

        double mediumNum = 0;
       //判断奇偶，取中间还是平均
        boolean odd = true;
        mediumNum = (nums1.length+nums2.length)/2 + 1;

        if((nums1.length+nums2.length)%2==0){
            odd = false;
        }
        int count = 1;
        int i = 0;
        int j = 0;
        double current = 0;
        double result = 0;
        while(count<=mediumNum){
            if(i<nums1.length && j<nums2.length ){
                if(nums1[i]<nums2[j]){
                    current = nums1[i];
                    i++;
                }else{
                    current = nums2[j];
                    j++;
                }
            }else if(!(i<nums1.length)){
                    current = nums2[j];
                    j++;
            }else if(!(j<nums2.length)){
                    current = nums1[i];
                    i++;
            }

            if(odd){

                if(count == mediumNum){
                    result = (double)current;
                }
            }else{

                if(count == mediumNum -1){
                    result = current;
                }else{
                    result += current;
                    result = (double)result/2 ;
                }
            }
            count++;
        }
        return result;
    }
}　

　　

　

运行结果