225 Implement Stack using Queues 队列实现栈
Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
empty() -- Return whether the stack is empty.
Notes:
You must use only standard operations of a queue -- which means only push to back, peek/pop from front, size, and is empty operations are valid.
Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
详见:https://leetcode.com/problems/implement-stack-using-queues/description/
Java实现:
方法一:两个队列实现,始终保持一个队列为空即可
class MyStack {
private Queue<Integer> queue1;
private Queue<Integer> queue2;
/** Initialize your data structure here. */
public MyStack() {
queue1=new LinkedList<Integer>();
queue2=new LinkedList<Integer>();
}
/** Push element x onto stack. */
public void push(int x) {
if(queue1.isEmpty()){
queue1.offer(x);
while(!queue2.isEmpty()){
queue1.offer(queue2.poll());
}
}else if(queue2.isEmpty()){
queue2.offer(x);
while(!queue1.isEmpty()){
queue2.offer(queue1.poll());
}
}
}
/** Removes the element on top of the stack and returns that element. */
public int pop() {
if(queue1.isEmpty()){
return queue2.poll();
}else{
return queue1.poll();
}
}
/** Get the top element. */
public int top() {
if(queue1.isEmpty()){
return queue2.peek();
}else{
return queue1.peek();
}
}
/** Returns whether the stack is empty. */
public boolean empty() {
return queue1.isEmpty()&&queue2.isEmpty();
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/
方法二:一个队列实现栈
class MyStack {
private Queue<Integer> queue;
/** Initialize your data structure here. */
public MyStack() {
queue=new LinkedList<Integer>();
}
/** Push element x onto stack. */
public void push(int x) {
queue.offer(x);
for(int i=0;i<queue.size()-1;++i){
queue.offer(queue.poll());
}
}
/** Removes the element on top of the stack and returns that element. */
public int pop() {
return queue.poll();
}
/** Get the top element. */
public int top() {
return queue.peek();
}
/** Returns whether the stack is empty. */
public boolean empty() {
return queue.isEmpty();
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/
C++实现:
方法一:两个队列实现,始终保持一个队列为空即可
class MyStack {
public:
/** Initialize your data structure here. */
MyStack() {
}
/** Push element x onto stack. */
void push(int x) {
if(que1.empty())
{
que1.push(x);
while(!que2.empty())
{
que1.push(que2.front());
que2.pop();
}
}
else if(que2.empty())
{
que2.push(x);
while(!que1.empty())
{
que2.push(que1.front());
que1.pop();
}
}
}
/** Removes the element on top of the stack and returns that element. */
int pop() {
int val;
if(que1.empty())
{
val=que2.front();
que2.pop();
}
else if(que2.empty())
{
val=que1.front();
que1.pop();
}
return val;
}
/** Get the top element. */
int top() {
if(que1.empty())
{
return que2.front();
}
else if(que2.empty())
{
return que1.front();
}
}
/** Returns whether the stack is empty. */
bool empty() {
return que1.empty()&&que2.empty();
}
private:
queue<int> que1;
queue<int> que2;
};
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* bool param_4 = obj.empty();
*/
方法二:一个队列实现栈
class MyStack {
public:
/** Initialize your data structure here. */
MyStack() {
}
/** Push element x onto stack. */
void push(int x) {
que.push(x);
for(int i=0;i<que.size()-1;++i)
{
que.push(que.front());
que.pop();
}
}
/** Removes the element on top of the stack and returns that element. */
int pop() {
int val=que.front();
que.pop();
return val;
}
/** Get the top element. */
int top() {
return que.front();
}
/** Returns whether the stack is empty. */
bool empty() {
return que.empty();
}
private:
queue<int> que;
};
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* bool param_4 = obj.empty();
*/
225 Implement Stack using Queues 队列实现栈的更多相关文章
- leetcode 155. Min Stack 、232. Implement Queue using Stacks 、225. Implement Stack using Queues
155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } v ...
- 232. Implement Queue using Stacks,225. Implement Stack using Queues
232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Im ...
- LeetCode 225 Implement Stack using Queues(用队列来实现栈)(*)
翻译 用队列来实现栈的例如以下操作. push(x) -- 将元素x加入进栈 pop() -- 从栈顶移除元素 top() -- 返回栈顶元素 empty() -- 返回栈是否为空 注意: 你必须使用 ...
- [LeetCode] 225. Implement Stack using Queues 用队列来实现栈
Implement the following operations of a stack using queues. push(x) -- Push element x onto stack. po ...
- 225 Implement Stack using Queues(用队列实现栈Medium)
题目意思:用队列实现栈,push(),pop(),top(),empty() 思路:用两个queue,pop时将一个queue的元素pop再push到另一个队列,queue只留最后一个元素,并pop, ...
- LeetCode 225 Implement Stack using Queues 用队列实现栈
1.两个队列实现,始终保持一个队列为空即可 class MyStack { public: /** Initialize your data structure here. */ MyStack() ...
- 【LeetCode】225. Implement Stack using Queues
题目: Implement the following operations of a stack using queues. push(x) -- Push element x onto stack ...
- 【LeetCode】225. Implement Stack using Queues 解题报告(Python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.c ...
- (easy)LeetCode 225.Implement Stack using Queues
Implement the following operations of a stack using queues. push(x) -- Push element x onto stack. po ...
随机推荐
- Python 之 读取txt文件
本文直接给出三种实现方法,代码例如以下. 方法一: f = open("Proc_Data.txt") # 返回一个文件对象 line = f.readline() # 调用文件的 ...
- 分享:Mac与Phy组成原理的简单分析
原文链接:http://blog.chinaunix.net/uid-20528014-id-3050217.html 1.General 下图是网口结构简图.网口由CPU.MAC和PHY三部分组成. ...
- 解决javah生成.h头文件找不到找不到android.support.v7.app.AppCompatActivity的问题
问题描写叙述: 在使用Android Studio进行JNI开发时,须要使用javah生成C或C++的头文件,可是可能会遇到: 错误: 无法訪问android.support.v7.app.AppCo ...
- HDU 5405 Sometimes Naive 树链剖分+bit*****
Sometimes Naive Problem Description Rhason Cheung had a naive problem, and asked Teacher Mai for h ...
- ou've likely run out of ephemeral ports on your system
redis.exceptions.ConnectionError: Error 99 connecting to 127.0.0.1:6379. Cannot assign requested add ...
- 文件上传Apache
Map<String, Object> rtnMap = new HashMap<String, Object>(); // 获取文件 String tempPath = re ...
- Lightoj 1025 - The Specials Menu
区间dp /* *********************************************** Author :guanjun Created Time :2016/6/30 23:2 ...
- HDU1069 Monkey and Banana —— DP
题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=1069 Monkey and Banana Time Limit: 2000/1000 MS ...
- YTU 2556: 空洞
2556: 空洞 时间限制: 1 Sec 内存限制: 128 MB 提交: 24 解决: 17 题目描述 春天来了,单身的霞姐越发地空虚寂寞,于是她想到一个办法,她认 为只要把英文字母上的洞都涂满 ...
- [Usaco2013 DEC] Vacation Planning
[题目链接] https://www.lydsy.com/JudgeOnline/problem.php?id=4093 [算法] 对于k个枢纽 , 分别在正向图和反向图上跑dijkstra最短路 , ...