多校1010 Taotao Picks Apples

》》点击进入原题《《

思路：题解很有意思，适合线段树进阶

#include<cstdio>
#include<cmath>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;

#define lson l,m,o<<1
#define rson m+1,r,o<<1|1

const int maxn = 1e5 + ;
int a[maxn], d1[maxn], d2[maxn];
int tree[maxn << ], vis[maxn << ];
int ans, cur;

void build(int l, int r, int o){
    if (l == r){
        tree[o] = a[l];
        vis[o] = l;
        return;
    }
    int m = (l + r) >> ;
    build(lson);
    build(rson);
    tree[o] = max(tree[o << ], tree[o <<  | ]);
    if (tree[o << ] >= tree[o <<  | ])
        vis[o] = vis[o << ];
    else vis[o] = vis[o <<  | ];

}
void query(int l, int r, int o, int ql, int qr, int k){
    if (l == r){
        if (tree[o]>k)
            cur = min(cur, l);
        return;
    }
    int m = (l + r) >> ;
    if (l >= ql&&r <= qr){
        if (tree[o << ] > k)
            query(lson, ql, qr, k);
        else if (tree[o <<  | ] > k)
            query(rson, ql, qr, k);
        return;
    }
    if (ql <= m)
        query(lson, ql, qr, k);
    if (qr > m)query(rson, ql, qr, k);
}
void query1(int l, int r, int o, int ql, int qr){
    if (l >= ql&&r <= qr){
        if (tree[o] > a[cur])
            cur = vis[o];
        return;
    }
    int m = (l + r) >> ;
    if (ql <= m)query1(lson, ql, qr);
    if (qr > m)query1(rson, ql, qr);
}
int main(){
    ios::sync_with_stdio(false);

    int t; cin >> t;
    while (t--){
        int n, m, p, q, Max = ;
        cin >> n >> m;
        for (int i = ; i <= n; i++){
            cin >> a[i];
            if (a[i] > Max)
                d1[i] = d1[i - ] + , Max = a[i];
            else d1[i] = d1[i - ];
        }
        build(, n, );
        for (int i = n; i; i--){
            cur = n + ;
            query(, n, , i, n, a[i]);
            if (cur > n)cur = ;
            d2[i] = d2[cur] + ;
        }
        while (m--){
            cin >> p >> q;
            ans = cur = ;
            if (p != ){
                query1(, n, , , p - );
            }
            ans += d1[cur];
            if (q > a[cur])ans++;
            else q = a[cur];
            cur = n + ;

            if (p != n)query(, n, , p + , n, q);
            if (cur <= n)ans += d2[cur];
            cout << ans << endl;
        }
    }
}