BZOJ2631——tree
1、题目大意:bzoj1798的lct版本
2、分析:这个把线段树改成splay就好
#include <stack> #include <cstdio> #include <cstdlib> #include <cstring> #include <algorithm> using namespace std; #define LL long long namespace LinkCutTree{ struct Node{ Node *ch[2], *fa; LL sum, num; LL size; bool rev; LL mul, plu; inline int which(); inline void reverse(){ if(this) rev ^= 1; } inline void pd(); inline void maintain(){ sum = (num + ch[0] -> sum + ch[1] -> sum) % 51061; size = (1 + ch[0] -> size + ch[1] -> size) % 51061; } Node(); } *null = new Node, tree[100010], *pos[100010]; Node::Node(){ num = sum = 1; rev = false; ch[0] = ch[1] = fa = null; mul = 1; plu = 0; size = 1; } inline void Node::pd(){ if(rev){ swap(ch[0], ch[1]); ch[0] -> reverse(); ch[1] -> reverse(); rev = false; } if(ch[0] != null){ ch[0] -> mul *= mul; ch[0] -> plu *= mul; ch[0] -> plu += plu; ch[0] -> num *= mul; ch[0] -> num += plu; ch[0] -> sum *= mul; ch[0] -> sum += plu * ch[0] -> size; ch[0] -> mul %= 51061; ch[0] -> plu %= 51061; ch[0] -> num %= 51061; ch[0] -> sum %= 51061; } if(ch[1] != null){ ch[1] -> mul *= mul; ch[1] -> plu *= mul; ch[1] -> plu += plu; ch[1] -> num *= mul; ch[1] -> num += plu; ch[1] -> sum *= mul; ch[1] -> sum += plu * ch[1] -> size; ch[1] -> mul %= 51061; ch[1] -> plu %= 51061; ch[1] -> num %= 51061; ch[1] -> sum %= 51061; } mul = 1; plu = 0; } inline int Node::which(){ if(fa == null || (this != fa -> ch[0] && this != fa -> ch[1])) return -1; return this == fa -> ch[1]; } inline void rotate(Node *o){ Node *p = o -> fa; int l = o -> which(), r = l ^ 1; o -> fa = p -> fa; if(p -> which() != -1) p -> fa -> ch[p -> which()] = o; p -> ch[l] = o -> ch[r]; if(o -> ch[r]) o -> ch[r] -> fa = p; o -> ch[r] = p; p -> fa = o; o -> ch[r] -> maintain(); o -> maintain(); } inline void splay(Node *o){ static stack<Node*> st; if(!o) return; Node *p = o; while(1){ st.push(p); if(p -> which() == -1) break; p = p -> fa; } while(!st.empty()){ st.top() -> pd(); st.pop(); } while(o -> which() != -1){ p = o -> fa; if(p -> which() != -1){ if(p -> which() ^ o -> which()) rotate(o); else rotate(p); } rotate(o); } } inline void Access(Node *o){ Node *y = null; while(o != null){ splay(o); o -> ch[1] = y; o -> maintain(); y = o; o = o -> fa; } } inline void MovetoRoot(Node *o){ Access(o); splay(o); o -> reverse(); } inline Node* FindRoot(Node *o){ Access(o); splay(o); while(o -> ch[0] != null) o = o -> ch[0]; return o; } inline void Link(Node *x, Node *y){ MovetoRoot(x); x -> fa = y; } inline void Cut(Node *x, Node *y){ MovetoRoot(x); Access(y); splay(y); y -> ch[0] = x -> fa = null; y -> maintain(); } } int main(){ using namespace LinkCutTree; null -> mul = 1; null -> size = 0; null -> plu = 0; null -> sum = 0; null -> num = 0; null -> ch[0] = null -> ch[1] = null -> fa = NULL; int n, q; scanf("%d%d", &n, &q); for(int i = 1; i <= n; i ++) pos[i] = &tree[i]; for(int i = 1; i < n; i ++){ int u, v; scanf("%d%d", &u, &v); Link(pos[u], pos[v]); } char op[5]; int x1, y1, x2, y2, c; while(q --){ scanf("%s", op); if(op[0] == '+'){ scanf("%d%d%d", &x1, &y1, &c); MovetoRoot(pos[x1]); Access(pos[y1]); splay(pos[y1]); pos[y1] -> num += c; pos[y1] -> num %= 51061; pos[y1] -> sum += pos[y1] -> size * c; pos[y1] -> sum %= 51061; pos[y1] -> plu += c; pos[y1] -> plu %= 51061; } else if(op[0] == '-'){ scanf("%d%d%d%d", &x1, &y1, &x2, &y2); Cut(pos[x1], pos[y1]); Link(pos[x2], pos[y2]); } else if(op[0] == '*'){ scanf("%d%d%d", &x1, &y1, &c); MovetoRoot(pos[x1]); Access(pos[y1]); splay(pos[y1]); pos[y1] -> num *= c; pos[y1] -> num %= 51061; pos[y1] -> sum *= c; pos[y1] -> sum %= 51061; pos[y1] -> mul *= c; pos[y1] -> mul %= 51061; pos[y1] -> plu *= c; pos[y1] -> plu %= 51061; } else{ scanf("%d%d", &x1, &y1); MovetoRoot(pos[x1]); Access(pos[y1]); splay(pos[y1]); pos[y1] -> sum %= 51061; printf("%lld\n", pos[y1] -> sum); } } return 0; }
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