test homework ~ coverage about method printPrimes

/*******************************************************
     * Finds and prints n prime integers
     * Jeff Offutt, Spring 2003
     ******************************************************/
    public static void printPrimes (int n)
    {
        int curPrime; // Value currently considered for primeness
        int numPrimes; // Number of primes found so far.
        boolean isPrime; // Is curPrime prime?
        int [] primes = new int [MAXPRIMES]; // The list of prime numbers. 

        // Initialize 2 into the list of primes.
        primes [0] = 2;
        numPrimes = 1;
        curPrime = 2;
        while (numPrimes < n)
        {
            curPrime++; // next number to consider ...
            isPrime = true;
            for (int i = 0; i <= numPrimes-1; i++)
            { // for each previous prime.
                if (curPrime%primes[i]==0)
                { // Found a divisor, curPrime is not prime.
                    isPrime = false;
                    break; // out of loop through primes.
                }
            }
            if (isPrime)
            { // save it!
                primes[numPrimes] = curPrime;
                numPrimes++;
            }
        } // End while 

        // Print all the primes out.
        for (int i = 0; i <= numPrimes-1; i++)
        {
            System.out.println ("Prime: " + primes[i]);
        }
    } // end printPrimes

First:

a. first draw the control flow graph, and we use the online tool (processon) to draw it.
    here is the result:

b. there are two test case t1=(n=3) and t2=(n=5),if t2 is easier to find a error than t1, it can be the boundary question.

if the list size(MAXSIZE=4) is 4. then t1 cannot find this error. However t2 willl find it.

c.  t=(n=1) don't pass throught the while body and just pass while header and for loop.

d. point coverage {1,2,3,4,5,6,7,8,9,10,11,12,13}

　 edge coverage {(1,2),(2,3),(3,4),(4,5),(4,6),(5,8),(5,9),(6,4),(6,7),(7,5),(8,9),(9,1),(1,10),(10,11),(11,12),(11,13),(12,11)}

prime path coverage {(1,10,11,12)

　　　　　　　　　　　　  (1,10,11,13)

　　　　　　　　　　　　  (11,12,11)

　　　　　　　　　　　　  (12，11，12)

　　　　　　　　　　　　  (1,2,3,4,5,8,9,1)

　　　　　　　　　　　　  (1,2,3,4,5,9,1)

　　　　　　　　　　　　  (1,2,3,4,6,7,5,8,9,1)

　　　　　　　　　　　　  (1,2,3,4,6,7,5,9,1)　

　　　　　　　　　　　　  (4,6,4)

　　　　　　　　　　　　　(6,4,6)}

Second: use junit to achieve the goal about prime path coverage for any program

code

package testHomework;

public class triangle {
    public String typeOfTriangle (int a, int b,int c)
    {
        String type = "not";
        if(a+b>c && a+c>b && c+a>b){
            type = "scalene";
            if(a==b || a==c || b==c){
                type="isosceles";
                if(a==b && b==c)
                    type="equilateral";
            }
            return type;
        }
        else{
            return type;
        }
    }
}

package testHomework;
import static org.junit.Assert.assertEquals;

import java.util.Arrays;
import java.util.Collection;

import org.junit.Test;
import org.junit.runner.RunWith;
import org.junit.runners.Parameterized;
import org.junit.runners.Parameterized.Parameters;

import testHomework.triangle;

@RunWith(Parameterized.class)
public class triangleTest {
    private String type;
    private int a;
    private int b;
    private int c;

    public triangleTest(String type, int a, int b, int c){
        this.type = type;
        this.a = a;
        this.b = b;
        this.c = c;
    }
    @Parameters
    public static Collection prepareData(){
        Object[][] object = {
                {"not",1,1,2},{"equilateral",1,1,1},
                {"isosceles",2,2,3},{"scalene",2,3,4}};
        return Arrays.asList(object);
    }
    @Test
    public void TestTypeOfTriangle()
    {
        triangle triangle = new triangle ();
        assertEquals (type, triangle.typeOfTriangle(a,b,c)); 

    }

}

the test case set T={(1,1,2),(1,1,1),(2,2,3),(2,3,4)} can achieve it for prime path coverage