Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers of deduction, he came to know that the killer has a strategy for selecting his next victim.

The killer starts with two potential victims on his first day, selects one of these two, kills selected victim and replaces him with a new person. He repeats this procedure each day. This way, each day he has two potential victims to choose from. Sherlock knows the initial two potential victims. Also, he knows the murder that happened on a particular day and the new person who replaced this victim.

You need to help him get all the pairs of potential victims at each day so that Sherlock can observe some pattern.

Input

First line of input contains two names (length of each of them doesn't exceed 10), the two initials potential victims. Next line contains integer n(1 ≤ n ≤ 1000), the number of days.

Next n lines contains two names (length of each of them doesn't exceed 10), first being the person murdered on this day and the second being the one who replaced that person.

The input format is consistent, that is, a person murdered is guaranteed to be from the two potential victims at that time. Also, all the names are guaranteed to be distinct and consists of lowercase English letters.

Output

Output n + 1 lines, the i-th line should contain the two persons from which the killer selects for the i-th murder. The (n + 1)-th line should contain the two persons from which the next victim is selected. In each line, the two names can be printed in any order.

Examples
input
ross rachel
4
ross joey
rachel phoebe
phoebe monica
monica chandler
output
ross rachel
joey rachel
joey phoebe
joey monica
joey chandler
input
icm codeforces
1
codeforces technex
output
icm codeforces
icm technex
Note

In first example, the killer starts with ross and rachel.

  • After day 1, ross is killed and joey appears.
  • After day 2, rachel is killed and phoebe appears.
  • After day 3, phoebe is killed and monica appears.
  • After day 4, monica is killed and chandler appears.

题意:看样列

解法:没啥说的

 #include<bits/stdc++.h>
typedef long long LL;
typedef unsigned long long ULL;
typedef long double LD;
using namespace std;
int main(){
string s1,s2;
cin>>s1>>s2;
cout<<s1<<" "<<s2<<endl;
int n;
cin>>n;
for(int i=;i<=n;i++){
string s3,s4;
cin>>s3>>s4;
if(s3==s1){
s1=s4;
}else{
s2=s4;
}
cout<<s1<<" "<<s2<<endl;
}
return ;
}

ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) A的更多相关文章

  1. ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) A map B贪心 C思路前缀

    A. A Serial Killer time limit per test 2 seconds memory limit per test 256 megabytes input standard ...

  2. ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) D. The Door Problem 2-SAT

    题目链接:http://codeforces.com/contest/776/problem/D D. The Door Problem time limit per test 2 seconds m ...

  3. ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined)

    前四题比较水,E我看出是欧拉函数傻逼题,但我傻逼不会,百度了下开始学,最后在加时的时候A掉了 AC:ABCDE Rank:182 Rating:2193+34->2227 终于橙了,不知道能待几 ...

  4. 【2-SAT】【并查集】ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) D. The Door Problem

    再来回顾一下2-SAT,把每个点拆点为是和非两个点,如果a能一定推出非b,则a->非b,其他情况同理. 然后跑强连通分量分解,保证a和非a不在同一个分量里面. 这题由于你建完图发现都是双向边,所 ...

  5. 【枚举】【前缀和】【map】ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) C. Molly's Chemicals

    处理出前缀和,枚举k的幂,然后从前往后枚举,把前面的前缀和都塞进map,可以方便的查询对于某个右端点,有多少个左端点满足该段区间的和为待查询的值. #include<cstdio> #in ...

  6. ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) D

    Moriarty has trapped n people in n distinct rooms in a hotel. Some rooms are locked, others are unlo ...

  7. ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) C

    Molly Hooper has n different kinds of chemicals arranged in a line. Each of the chemicals has an aff ...

  8. ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) B

    Sherlock has a new girlfriend (so unlike him!). Valentine's day is coming and he wants to gift her s ...

  9. ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) C. Molly's Chemicals

    感觉自己做有关区间的题目方面的思维异常的差...有时简单题都搞半天还完全没思路,,然后别人提示下立马就明白了...=_= 题意:给一个含有n个元素的数组和k,问存在多少个区间的和值为k的次方数. 题解 ...

随机推荐

  1. malloc、calloc、realloc和alloca各种的区别

    需要先包含头文件 #include"malloc.h" malloc是标准的在堆中开辟新的空间 比如 char *pt=(char *)malloc(10*sizeof(char) ...

  2. HDU2896 病毒侵袭 —— AC自动机

    题目链接:https://vjudge.net/problem/HDU-2896 病毒侵袭 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit ...

  3. zk使用通知移除节点

    前面:https://www.cnblogs.com/toov5/p/9899238.html 服务发生宕机 咋办? 发个事件通知,告知大家哟, 会有通知事件哦 看项目: 服务端: package c ...

  4. Pyhton:汉诺塔游戏

    #汉诺塔游戏攻略! def hanoi(n,x,y,z): if n == 1: print(x,'-->',z) else: hanoi(n-1,x,z,y) #将前n-1个盘子从x移动到y上 ...

  5. 【EOJ Monthly 2018.2 (Good bye 2017)】

    23333333333333333 由于情人节要回家,所以就先只放代码了. 此题是与我胖虎过不去. [E. 出老千的 xjj] #include<cstdio> #include<c ...

  6. python 基础之第十三天(xineted服务器,forking,多线程)

  7. main.o: In function `__static_initialization_and_destruction_0′:

    原因: gcc编译C++文件时,需要添加一选项:-lstdc++  解决方法如下: 可以将gcc换成g++编译器编译. 如果坚持使用gcc的话,可以在gcc后面加上-lstdc++,即:    gcc ...

  8. DataWindow.NET 控件 实现点击列头排序

    1.定义字段                         Boolean ib_SetSort = true;                string is_SortType = " ...

  9. 免证书发布ipa文件真机测试

    首先设备得越狱 众所周知,在Xcode上开发的程序只能在模拟器中运行,如果要放到真机上则要花费99美金购买开发者证书iDP.这严重阻碍了我等草根开发者探索的脚步.写个小程序,同学间分享一下这个小小的愿 ...

  10. jquery中innerheight outerHeight()与height()的区别

    1. .height() 获取匹配元素集合中的第一个元素的当前计算高度值 或 设置每一个匹配元素的高度值(带一个参数). 注意:1).css('height')和.height()之间的区别是后者返回 ...