Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.

Hide Tags

Bit Manipulation

 

#include <iostream>
using namespace std;
class Solution {
public:
int hammingWeight(uint32_t n) {
int sum =;
while(n){
if(n&-n) sum++;
n = n&(n-);
}
return sum;
}
}; int main()
{
uint32_t n = ;
Solution sol;
cout<<sol.hammingWeight(n)<<endl;
return ;
}

[LeetCode] Number of 1 Bits 位操作的更多相关文章

  1. 2016.5.15——leetcode:Number of 1 Bits ,

    leetcode:Number of 1 Bits 代码均测试通过! 1.Number of 1 Bits 本题收获: 1.Hamming weight:即二进制中1的个数 2.n &= (n ...

  2. [LeetCode] Number of 1 Bits 位1的个数

    Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also know ...

  3. LeetCode Number of 1 Bits

    原题链接在这里:https://leetcode.com/problems/number-of-1-bits/ 题目: Write a function that takes an unsigned ...

  4. LeetCode——Number of 1 Bits

    //求一个整数的二进制串中1的个数 public int hammingWeight(int n) { String b_str = Integer.toBinaryString(n); int b_ ...

  5. LeetCode Number of 1 Bits 计算1的个数

    题意: 提供一个无符号32位整型uint32_t变量n,返回其二进制形式的1的个数. 思路: 考察二进制的特性,设有k个1,则复杂度为O(k).考虑将当前的数n和n-1做按位与,就会将n的最后一个1去 ...

  6. lc面试准备:Number of 1 Bits

    1 题目 Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also ...

  7. [LeetCode] 191. Number of 1 Bits 二进制数1的个数

    Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also know ...

  8. (easy)LeetCode 191.Number of 1 Bits

    Number of 1 Bits Write a function that takes an unsigned integer and returns the number of ’1' bits ...

  9. LeetCode 191. Number of 1 bits (位1的数量)

    Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also know ...

随机推荐

  1. ZendFramework-2.4 源代码 - ViewManager类图

  2. Mongodb内嵌对象关联查询

    db.-10-30T00:00:00Z"),"$lt":ISODate("2018-10-30T23:59:00Z")}, "equip.$ ...

  3. Jane Austen【简·奥斯汀】

    Jane Austen Jane Austen, a famous English writer, was born at Steventon, Hampshire, on December 16, ...

  4. stm32基本定时器timer6的原理与使用

    /********************基本定时器 TIM 参数定义,只限 TIM6.7************/ /* 一.定时器分类 STM32F1 系列中,除了互联型的产品,共有 8 个定时器 ...

  5. LCS及方案数(DP)

    Description 对于一个序列

  6. Network of Schools POJ - 1236 (强联通)

    一些学校连接到了一个计算机网络.网络中的学校间有如下约定:每个学校维护一个列表,当该学校收到软件或信息后将会转发给列表中的所有学校(也就是接收方列表).需要注意的是如果B学校在A学校的接收方列表中,A ...

  7. 查询语句为“%string_”的情况

    select * from t_user where user_name like '%Joe_%'实际查询出来的语句为: 而不像预计的前两条.

  8. Android Studio 快捷键(包含自定义)终极版

      [F] [F] F2 在错误代码之间切换 F3 往前定位(Shift + F3:往后定位 )有问题 F4\Ctrl+鼠标点击\Ctrl+B 转到定义,查看类继承关系 F5 但不调试进入函数内部. ...

  9. [原]sencha touch之表单(login demo)

    现在来说说sencha touch中的表单,举个简单的login的例子,相关的说明我都放在了注释中,看下面代码 Ext.application({ id:'itKingApp', launch:fun ...

  10. C 语言 习题 1-12

    练习 1-12 编写一个程序,以每行一个单词的形式打印其输入. #include <stdio.h> #define IN 1 #define OUT 0 int main(int arg ...