多少个平方数小于等于X,二分。

PS:java BigInteger

import java.util.*;
import java.math.*; public class Solution {
public static void main(String args[]) {
Scanner in = new Scanner(System.in); BigInteger X = in.nextBigInteger(); BigInteger L = BigInteger.valueOf(1);
BigInteger R = BigInteger.valueOf(10).pow(500); while (L.compareTo(R) <= 0) {
BigInteger M = L.add(R).divide(BigInteger.valueOf(2));
if (M.pow(2).compareTo(X) <= 0) {
L = M.add(BigInteger.valueOf(1));
} else {
R = M.subtract(BigInteger.valueOf(1));
}
} System.out.println(R);
}
}

SGU111 Very simple problem的更多相关文章

  1. POJ 3468 A Simple Problem with Integers(线段树 成段增减+区间求和)

    A Simple Problem with Integers [题目链接]A Simple Problem with Integers [题目类型]线段树 成段增减+区间求和 &题解: 线段树 ...

  2. POJ 3468 A Simple Problem with Integers(线段树/区间更新)

    题目链接: 传送门 A Simple Problem with Integers Time Limit: 5000MS     Memory Limit: 131072K Description Yo ...

  3. poj 3468:A Simple Problem with Integers(线段树,区间修改求和)

    A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 58269   ...

  4. ACM: A Simple Problem with Integers 解题报告-线段树

    A Simple Problem with Integers Time Limit:5000MS Memory Limit:131072KB 64bit IO Format:%lld & %l ...

  5. poj3468 A Simple Problem with Integers (线段树区间最大值)

    A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 92127   ...

  6. POJ3648 A Simple Problem with Integers(线段树之成段更新。入门题)

    A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 53169 Acc ...

  7. BZOJ-3212 Pku3468 A Simple Problem with Integers 裸线段树区间维护查询

    3212: Pku3468 A Simple Problem with Integers Time Limit: 1 Sec Memory Limit: 128 MB Submit: 1278 Sol ...

  8. POJ 3468 A Simple Problem with Integers(线段树区间更新区间查询)

    A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 92632   ...

  9. A Simple Problem with Integers(树状数组HDU4267)

    A Simple Problem with Integers Time Limit: 5000/1500 MS (Java/Others) Memory Limit: 32768/32768 K (J ...

随机推荐

  1. htm5实现视差动画

    requestAnimationFrame.js window.requestAnimFrame = (function() { return window.requestAnimationFrame ...

  2. Emit

    http://www.cnblogs.com/zhuweisky/archive/2008/09/20/1294666.html http://www.cnblogs.com/xiaoxiangfei ...

  3. iOS 非ARC基本内存管理系列 -手把手教你ARC——iOS/Mac开发ARC入门和使用(转)

    手把手教你ARC——iOS/Mac开发ARC入门和使用 Revolution of Objective-c 本文部分实例取自iOS 5 Toturail一书中关于ARC的教程和公开内容,仅用于技术交流 ...

  4. Mysql 作业(Scheduler)

    200 ? "200px" : this.width)!important;} --> 介绍 作业也叫做事件调度,其实它也就是一个时间触发器:它可以定义某个时间点执行指定的数 ...

  5. MySQL学习笔记之数据存储类型

    说明:本文是作者对MySQL数据库数据存储类型的小小总结. Numeric Type (数字类型) 1.TINYINT.SMALLINT.MEDIUMINT.INT.BIGINT主要根据存储字节长度不 ...

  6. checkbox批量选中,获取选中的项的值

    <!doctype html><html lang="en"> <head>  <meta charset="UTF-8&quo ...

  7. String inputStream file转化

    String --> InputStreamByteArrayInputStream stream = new ByteArrayInputStream(str.getBytes()); Inp ...

  8. c#汉字转为拼音

    using System; using System.Collections.Generic; using System.Text; using System.Text.RegularExpressi ...

  9. Get code int value for different encoding

    http://msdn.microsoft.com/en-us/library/system.text.encodinginfo.getencoding%28v=vs.110%29.aspx usin ...

  10. Linux多进行之fork

    #include <unistd.h> //定义该函数 #include <sys/types.h> //定义函数的返回类型pid_t /* 功能:复制进程 参数:无 返回值: ...