动态规划-Distinct Subsequences
2020-01-03 13:29:04
问题描述:

问题求解:
经典的动态规划题目,一般来说dp题目是递推关系公式难想,但是实际代码量还是比较少的。
有尝试过dfs来做,但是由于时间复杂度是指数级别的,所以会TLE。
public int numDistinct(String s, String t) {
int n1 = s.length();
int n2 = t.length();
int[][] dp = new int[n2 + 1][n1 + 1];
for (int i = 0; i <= n1; i++) dp[0][i] = 1;
for (int i = 1; i <= n2; i++) {
for (int j = 1; j <= n1; j++) {
if (t.charAt(i - 1) == s.charAt(j - 1)) dp[i][j] = dp[i - 1][j - 1] + dp[i][j - 1];
else dp[i][j] = dp[i][j - 1];
}
}
return dp[n2][n1];
}
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