PAT-1005 Spell It Right 解答(C/C++/Java/python)

1.Description：

2.Example：

Input:
12345
Output:
one five

3.solutions:

C Version:

 #include <stdio.h>
 #include <string.h>
 #include <stdlib.h>

 int main() {
     char digits[] = {};
     char NUMBERS[][] = {"zero", "one", "two", "three", "four", "five","six",
                         "seven", "eight", "nine", "ten"};
     scanf("%s", digits);
     int sum = ;
     unsigned i;
     for (i = ; digits != NULL && i < strlen(digits); ++i) {
         sum += digits[i] - ;  // '0'的Ascill码为48
     }
     char* output;
     sprintf(output, "%d", sum);
     unsigned j;
     for (j = ; output[j] != '\0'; ++j) {
         if (j != strlen(output) - )
             printf("%s ", NUMBERS[output[j] - ]);
         else
             printf("%s", NUMBERS[output[j] - ]);
     }
     return ;
 }

Note: 自己的电脑上调试无误，提交时运行错误！

C++ Version:

 #include <iostream>
 using namespace std;

 int main() {
     string digits;
     string NUMBERS[] = {"zero", "one", "two", "three", "four", "five","six",
                         "seven", "eight", "nine", "ten"};
     getline(cin, digits);
     cout << digits << endl;
     int sum = ;
     for (int i = ; i < digits.size(); ++i) {
         sum += int(digits[i]);
     }
     string output = to_string(sum);
     for (int j = ; j < output.size(); ++j) {
         if (j != output.size() - )
             cout << NUMBERS[int(output[j])] << " ";
         else
             cout << NUMBERS[int(output[j])];
     }
     return ;
 }

Java Version:

 import java.util.Scanner;

 /**
  * Created by sheepcore on 2020-02-28
  */

 public class P1005_Spell_It_Right {
     public static void main(String[] args) {
         String digits;
         String NUMBERS[] = {"zero", "one", "two", "three", "four", "five","six",
                 "seven", "eight", "nine", "ten"};
         Scanner scan = new Scanner(System.in);
         digits = scan.nextLine();
         int sum = 0;
         for (int i = 0; i < digits.length(); ++i) {
             sum += Integer.parseInt(digits.charAt(i) + "");
         }
         String output = sum + "";
         int idx;
         for (int j = 0; j < output.length(); ++j) {
             if (j != output.length() - 1){
                 idx = Integer.parseInt(output.charAt(j) + "");
                 System.out.print(NUMBERS[idx] + " ");
             }
             else {
                 idx = Integer.parseInt(output.charAt(j) + "");
                 System.out.print(NUMBERS[idx]);
             }
         }
     }
 }

Python Version:

 """
     created by sheepcore on 2020-2-28
 """

 if __name__ == "__main__":
     digits = input()
     NUMBERS = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven',
                'eight', 'nine', 'ten']
     i = 0
     for ch in digits:
         i += eval(ch)
     sum = str(i)
     output = ""
     for num in sum:
         output += " " + str(NUMBERS[eval(num)])
     print(output.lstrip(), end='')

4.summary:

掌握C、C++、Java、Python中字符串与数字之间的转换方法。

水滴石穿，笨鸟先飞！