map Codeforces Round #Pi (Div. 2) C. Geometric Progression
/*
题意:问选出3个数成等比数列有多少种选法
map:c1记录是第二个数或第三个数的选法,c2表示所有数字出现的次数。别人的代码很短,思维巧妙
*/
/************************************************
* Author :Running_Time
* Created Time :2015-8-6 1:07:18
* File Name :C.cpp
************************************************/ #include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std; #define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int MAXN = 2e5 + ;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + ;
map<ll, ll> c1, c2; int main(void) { //Codeforces Round #Pi (Div. 2) C. Geometric Progression
ll ans = , x; ll n, k;
scanf ("%I64d%I64d", &n, &k);
for (int i=; i<=n; ++i) {
scanf ("%I64d", &x);
if (x % (k * k) == ) ans += c1[x/k]; //x可选作第三个数
if (x % k == ) c1[x] += c2[x/k]; //x第三个数或第二个数
c2[x]++;
} printf ("%I64d\n", ans); return ;
}
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