pat 甲级 1066. Root of AVL Tree (25)
1066. Root of AVL Tree (25)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Figures 1-4 illustrate the rotation rules.


Now given a sequence of insertions, you are supposed to tell the root of the resulting AVL tree.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (<=20) which is the total number of keys to be inserted. Then N distinct integer keys are given in the next line. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print ythe root of the resulting AVL tree in one line.
Sample Input 1:
5
88 70 61 96 120
Sample Output 1:
70
Sample Input 2:
7
88 70 61 96 120 90 65
Sample Output 2:
88 题意:AVL树的实现。
AC代码:
#define _CRT_SECURE_NO_DEPRECATE
#include<iostream>
#include<algorithm>
#include<cmath>
#include<cstring>
#include<string>
#include<set>
#include<queue>
#include<map>
using namespace std;
#define INF 0x3f3f3f
#define N_MAX 100+5
typedef long long ll;
int n,a[N_MAX];
struct AVLtree {
int key=INF;
AVLtree* l_child, *r_child;
int height;
}T;
AVLtree *NIL;
AVLtree* root;
int Height(AVLtree* T) {//返回x的高度
int l_height=, r_height=;
if (T) {
l_height = Height(T->l_child);
r_height = Height(T->r_child);
return T->height = max(l_height, r_height) + ;
}
return ;//节点不存在,没有高度
} AVLtree* LeftRotation(AVLtree* a) {//左单旋
AVLtree *b = a->l_child;
a->l_child = b->r_child;
b->r_child = a;
a->height = Height(a);
b->height = Height(b);
return b;
}
AVLtree* RightRotation(AVLtree* a) {//右单旋
AVLtree* b = a->r_child;
a->r_child = b->l_child;
b->l_child = a;
a->height = Height(a);
b->height = Height(b);
return b;
} AVLtree* LeftRightRotation(AVLtree* a) {
a->l_child = RightRotation(a->l_child);
return LeftRotation(a);
}
AVLtree* RightLeftRotation(AVLtree* a) {
a->r_child = LeftRotation(a->r_child);
return RightRotation(a);
} AVLtree* insert(int key,AVLtree*root) {//root是当前AVL树的根, 返回根
if (root == NIL) {
root = new AVLtree;
root->key = key;
root->height = ;
root->l_child = root->r_child = NIL;
}
if (key < root->key) {
root->l_child = insert(key,root->l_child);
if (Height(root->l_child)-Height(root->r_child)==) {
if (key < root->l_child->key) {
root = LeftRotation(root);
}
else root = LeftRightRotation(root);
}
}
else if (key > root->key) {
root->r_child = insert(key,root->r_child);
if (Height(root->r_child) - Height(root->l_child) == ) {
if (key > root->r_child->key) {
root = RightRotation(root);
}
else root = RightLeftRotation(root);
}
} root->height = Height(root);//节点插入完毕,计算当前根的高度
return root;
} int main() {
while (scanf("%d",&n)!=EOF) {
for (int i = ; i < n; i++) {
int a; scanf("%d",&a);
root=insert(a, root);
}
printf("%d\n",root->key);
}
return ;
}
pat 甲级 1066. Root of AVL Tree (25)的更多相关文章
- PAT 甲级 1066 Root of AVL Tree (25 分)(快速掌握平衡二叉树的旋转,内含代码和注解)***
1066 Root of AVL Tree (25 分) An AVL tree is a self-balancing binary search tree. In an AVL tree, t ...
- PAT甲级1066. Root of AVL Tree
PAT甲级1066. Root of AVL Tree 题意: 构造AVL树,返回root点val. 思路: 了解AVL树的基本性质. AVL树 ac代码: C++ // pat1066.cpp : ...
- PAT 甲级 1066 Root of AVL Tree
https://pintia.cn/problem-sets/994805342720868352/problems/994805404939173888 An AVL tree is a self- ...
- PAT Advanced 1066 Root of AVL Tree (25) [平衡⼆叉树(AVL树)]
题目 An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child ...
- PAT甲级:1066 Root of AVL Tree (25分)
PAT甲级:1066 Root of AVL Tree (25分) 题干 An AVL tree is a self-balancing binary search tree. In an AVL t ...
- PAT 1066. Root of AVL Tree (25)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- 1066. Root of AVL Tree (25)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- 1066 Root of AVL Tree (25)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- PAT甲级——A1066 Root of AVL Tree
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
随机推荐
- macbook pro开机键盘键盘和触摸板没反应问题
今天遇到开机键盘和触摸板没反应的问题,打电话给售后,他叫我插一个usb外置键盘,开机时按shift+alt+control+电源键开机,突然发现可以了,这bug我也是醉了
- JAVA 优先获取外网Ip,再获取内网Ip
1.获取内网Ip private String getLocalhostIp(){ String hostAddress = ""; try { InetAddress addre ...
- 第2 章Python 语言基础
必背必记 1.转义字符 Python 中的字符串还支持转义字符.所谓转义字符是指使用反斜杠“\”对一些特殊字符进行转义. \ 续行符 \n 换行符 \0 空 \t 水平制表符,用于横向跳到下一制表 ...
- 【CodeBase】PHP转换编码,读写文件/网页内容的防乱码方法
核心代码: //检查字符串的编码 $charset=mb_detect_encoding($doc,['ASCII','GB2312','GBK','BIG5','UTF8'],TRUE); //字符 ...
- tp5 使用paginate分页获取数据对象之后 如何对对象进行数据添加
tp5 使用paginate分页获取数据对象之后 如何对对象进行数据添加 大家都知道,在使用tp5的paginate获取分页数据之后,得到的是一个数据对象,但有时会碰到要对数据对象进行二次加工的情况, ...
- vue之神奇的动态按钮
今天我们将利用vue的条件指令来完成一个简易的动态变色功能按钮 首先我们还是要对vue进行配置,在上篇随笔中有相关下载教学. 然后我们要在html页面上搭建三个简易的按钮,颜色分别为紫,绿和蓝(颜色随 ...
- wusir 面试题答案在老男孩的视频里
注意:你问答案在哪里?答案在视频里了,就是不给你写. 第一部分 Python基础篇(80题) 为什么学习Python? 通过什么途径学习的Python? Python和Java.PHP.C.C#.C+ ...
- Oracle 数据库密码过期问题
(1)在CMD命令窗口中输入: sqlplus 用户名/密码@数据库本地服务名 as sysdba;(如:sqlplus scott/1234@oracle1 as sysdba; ...
- Altium Designer
抗干扰设计原则: 1.电源线的设计 选择合适的电源 尽量加宽电源线 保证电源线.底线走向和数据传输方向一致 使用抗干扰元器件(磁珠.电源滤波器等) 电源入口添加去耦电容 2.底线的设计 模拟地和数字地 ...
- Android 服务入门
前言:硬着头皮把数据库SQLite看完了,接下来就是android服务了,因为自己本身就是菜鸟,所以呢,也只是做做笔记,技术上的东西就别指望我了. 1.什么是服务呢?举个例子,百度地图,美团外卖,OF ...