PAT甲级:1066 Root of AVL Tree (25分)
PAT甲级:1066 Root of AVL Tree (25分)
题干
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Figures 1-4 illustrate the rotation rules.


Now given a sequence of insertions, you are supposed to tell the root of the resulting AVL tree.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤20) which is the total number of keys to be inserted. Then N distinct integer keys are given in the next line. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print the root of the resulting AVL tree in one line.
Sample Input 1:
5
88 70 61 96 120
Sample Output 1:
70
Sample Input 2:
7
88 70 61 96 120 90 65
Sample Output 2:
88
思路
模拟一下AVL树的过程。
四个旋转方法,左单旋,右单旋,左右双旋,右左双旋。具体看代码,函数名写得挺清楚的。
还需要一个高度函数,递归一下就得出来了。
最后再弄一个insert 函数,注意AVL树的特点,左右子树的高度差为2时必须发生平衡旋转。
code
#include <iostream>
using namespace std;
struct node{
int data;
node *left, *right;
node(int data){this->data = data, this->left = this->right = NULL;}
};
node* rotate_left(node* root){
node* temp = root->left;
root->left = temp->right;
temp->right = root;
return temp;
}
node* rotate_right(node* root){
node* temp = root->right;
root->right = temp->left;
temp->left = root;
return temp;
}
node* rotate_left_right(node* root){
root->right = rotate_left(root->right);
return rotate_right(root);
}
node* rotate_right_left(node* root){
root->left = rotate_right(root->left);
return rotate_left(root);
}
int getHeight(node* root){
if(root == NULL) return 0;
return max(getHeight(root->right), getHeight(root->left)) + 1;
}
node* insert(int data, node* root){
if(root == NULL) root = new node(data);
else if(data > root->data) {
root->right = insert(data, root->right);
if(getHeight(root->right) - getHeight(root->left) >= 2)
root = root->right->data > data ? rotate_left_right(root) : rotate_right(root);
}
else {
root->left = insert(data, root->left);
if(getHeight(root->left) - getHeight(root->right) >= 2)
root = root->left->data < data ? rotate_right_left(root) : rotate_left(root);
}
return root;
}
int main(){
int n = 0, temp = 0;
scanf("%d", &n);
node *root = NULL;
for(int i = 0; i < n; i++){
scanf("%d", &temp);
root = insert(temp, root);
}
printf("%d", root->data);
return 0;
}
PAT甲级:1066 Root of AVL Tree (25分)的更多相关文章
- PAT 甲级 1066 Root of AVL Tree (25 分)(快速掌握平衡二叉树的旋转,内含代码和注解)***
1066 Root of AVL Tree (25 分) An AVL tree is a self-balancing binary search tree. In an AVL tree, t ...
- pat 甲级 1066. Root of AVL Tree (25)
1066. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An A ...
- PAT甲级1066. Root of AVL Tree
PAT甲级1066. Root of AVL Tree 题意: 构造AVL树,返回root点val. 思路: 了解AVL树的基本性质. AVL树 ac代码: C++ // pat1066.cpp : ...
- PAT 甲级 1066 Root of AVL Tree
https://pintia.cn/problem-sets/994805342720868352/problems/994805404939173888 An AVL tree is a self- ...
- PAT Advanced 1066 Root of AVL Tree (25) [平衡⼆叉树(AVL树)]
题目 An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child ...
- 1066 Root of AVL Tree (25分)(AVL树的实现)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- 【PAT甲级】1066 Root of AVL Tree (25 分)(AVL树建树模板)
题意: 输入一个正整数N(<=20),接着输入N个结点的值,依次插入一颗AVL树,输出最终根结点的值. AAAAAccepted code: #define HAVE_STRUCT_TIMESP ...
- PTA 04-树5 Root of AVL Tree (25分)
题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/668 5-6 Root of AVL Tree (25分) An AVL tree ...
- PAT 1066. Root of AVL Tree (25)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
随机推荐
- ffmpeg architecture(下)
ffmpeg architecture(下) 第3章-转码 TLDR:给我看代码和执行. $ make run_transcoding 我们将跳过一些细节,但是请放心:源代码可在github上找到. ...
- 使用Nginx配置服务静态文件(图片,文本,视频等)
安装Nginx 安装Nginx较为简单,请参考下方链接或自行百度. 参考链接:https://blog.csdn.net/qq_26666947/article/details/112272058 以 ...
- SQL Parameter参数的用法
SqlParameter 类 表示 SqlCommand 的参数,也可以是它到 DataSet 列的映射. 无法继承此类. 命名空间: System.Data.SqlClient 程序集: Sys ...
- 2、java数据结构和算法:单链表: 反转,逆序打印, 合并二个有序链表,获取倒数第n个节点, 链表的有序插入
什么也不说, 直接上代码: 功能点有: 1, 获取尾结点 2, 添加(添加节点到链表的最后面) 3, 添加(根据节点的no(排名)的大小, 有序添加) 4, 单向链表的 遍历 5, 链表的长度 6, ...
- mysql-8.0.16-winx64.zip安装教程详解
摘自:https://zhuanlan.zhihu.com/p/48531203 mysql-8.0.16-winx64.zip安装教程详解下载地址:https://dev.mysql.com/get ...
- Spring Cloud05: Zuul 服务网关
一.什么是Zuul 服务网关 Zuul 是 Netflix 提供的⼀个开源的 API ⽹关服务器,是客户端和⽹站后端所有请求的中间层,对外开放 ⼀个 API,将所有请求导⼊统⼀的⼊⼝,屏蔽了服务端的具 ...
- selenium常用方法集合
一.selenium定位元素的8种方法: 1.find_element_by_id() 2.find_element_by_name() 3.find_element_by_css() 4.find_ ...
- SpringMVC 进阶版
请求限制 一些情况下我们可能需要对请求进行限制,比如仅允许POST,GET等... RequestMapping注解中提供了多个参数用于添加请求的限制条件 value 请求地址 path 请求地址 m ...
- Oracle11g RAC详解
升级变化: Oracle10g,高版本都是由低版本升级得到的.要装10.2.0.4,必须先安装database10.2.0.1,然后给这个ORACLE_HOME打补丁p6180189 ...
- 怎么停掉或关闭运行的npm run dev
可以直接Ctrl+C就会出现 输入是就可以了