Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) A. Forgetting Things 水题
A. Forgetting Things
Kolya is very absent-minded. Today his math teacher asked him to solve a simple problem with the equation
Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) A. Forgetting Things 水题的更多相关文章
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2)
A - Forgetting Things 题意:给 \(a,b\) 两个数字的开头数字(1~9),求使得等式 \(a=b-1\) 成立的一组 \(a,b\) ,无解输出-1. 题解:很显然只有 \( ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) D. Power Products
链接: https://codeforces.com/contest/1247/problem/D 题意: You are given n positive integers a1,-,an, and ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) C. p-binary
链接: https://codeforces.com/contest/1247/problem/C 题意: Vasya will fancy any number as long as it is a ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) B2. TV Subscriptions (Hard Version)
链接: https://codeforces.com/contest/1247/problem/B2 题意: The only difference between easy and hard ver ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) A. Forgetting Things
链接: https://codeforces.com/contest/1247/problem/A 题意: Kolya is very absent-minded. Today his math te ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) F. Tree Factory 构造题
F. Tree Factory Bytelandian Tree Factory produces trees for all kinds of industrial applications. Yo ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) E. Rock Is Push dp
E. Rock Is Push You are at the top left cell (1,1) of an n×m labyrinth. Your goal is to get to the b ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) B. TV Subscriptions 尺取法
B2. TV Subscriptions (Hard Version) The only difference between easy and hard versions is constraint ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) D. Power Products 数学 暴力
D. Power Products You are given n positive integers a1,-,an, and an integer k≥2. Count the number of ...
随机推荐
- MYSQL ERROR:1130 解决
MYSQL ERROR:1130 解决 ERROR 1130: Host '127.0.0.7' is not allowed to connect to this MySQL server 解决 ...
- python做中学(八)匿名函数lambda的用法
匿名函数,顾名思义即没有名称的函数,和def定义的函数的最大区别在于匿名函数创建后返回函数本身(即匿名函数不需要return来返回值),表达式本身结果就是返回值,而def创建后则赋值给一个变量名,在P ...
- Feign原理 (图解)
疯狂创客圈 Java 高并发[ 亿级流量聊天室实战]实战系列 [博客园总入口 ] 疯狂创客圈 正在进行分布式和高并发基础原理的研习,进行已经发布一些基础性的文章: 一.版本1 :springcloud ...
- 【TCP/IP网络编程】:01理解网络编程和套接字
1.网络编程和套接字 网络编程与C语言中的printf函数和scanf函数以及文件的输入输出类似,本质上也是一种基于I/O的编程方法.之所以这么说,是因为网络编程大多是基于套接字(socket,网络数 ...
- 15-scrapy-redis两种形式分布式爬虫
什么叫做分布式爬虫? 分布式爬虫,就是多台机器共用一个scrapy—redis程序高效爬取数据, 为啥要用分布式爬虫? 其一:因为多台机器上部署的scrapy会各自拥有各自的调度器,这样就使得多台机器 ...
- 解决centos下tomcat启动太慢 & JDBC连接oracle太慢的问题
近期遇到一个非常奇怪的问题,也不知道改了什么,tomcat启动非常慢,以前几秒就启动好了,现在要30秒左右. 而且,通过jdbc连接oracle数据库也非常慢,以前建立一个连接只要几十毫秒,现在也要1 ...
- Kubernetes容器日志收集
日志采集方式 日志从传统方式演进到容器方式的过程就不详细讲了,可以参考一下这篇文章Docker日志收集最佳实践,由于容器的漂移.自动伸缩等特性,日志收集也就必须使用新的方式来实现,Kubernetes ...
- angular 前端路由不生效解决方案
angular 前端路由不生效解决方案 Intro 最近使用 Angular 为我的活动室预约项目开发一个前后端分离的客户端,在部署上遇到了一个问题,前端路由不生效,这里记录一下.本地开发正常,但是部 ...
- Swagger UI in AspNetCore WebAPI
Swagger其实包含了三个部分,分别是Swagger Editor文档接口编辑器,根据接口文档生成code的Swagger Codegen,以及生成在线文档的Swagger UI.在AspNetCo ...
- java基础(12):构造方法、this、super
1. 构造方法 我们对封装已经有了基本的了解,接下来我们来看一个新的问题,依然以Person为例,由于Person中的属性都被private了,外界无法直接访问属性,必须对外提供相应的set和get方 ...