Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) A. Forgetting Things
链接:
https://codeforces.com/contest/1247/problem/A
题意:
Kolya is very absent-minded. Today his math teacher asked him to solve a simple problem with the equation a+1=b with positive integers a and b, but Kolya forgot the numbers a and b. He does, however, remember that the first (leftmost) digit of a was da, and the first (leftmost) digit of b was db.
Can you reconstruct any equation a+1=b that satisfies this property? It may be possible that Kolya misremembers the digits, and there is no suitable equation, in which case report so.
思路:
特判9 1,其他的照着搞。
代码:
//#include <iostream>
//#include <fstream>
//#include <process.h>
//#include "ch08/ch08Func.cpp"
#include <bits/stdc++.h>
typedef long long LL;
using namespace std;
int main()
{
ios::sync_with_stdio(false);
int a, b;
cin >> a >> b;
if (a == b)
{
cout << a << '1' << ' ' << b << '2' << endl;
return 0;
}
if (a == 9 && b == 1)
{
cout << 9 << ' ' << 10 << endl;
return 0;
}
if (a > b || b-a > 1)
{
cout << -1 << endl;
return 0;
}
cout << a << '9' << ' ' << b << '0' << endl;
return 0;
}
Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) A. Forgetting Things的更多相关文章
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2)
A - Forgetting Things 题意:给 \(a,b\) 两个数字的开头数字(1~9),求使得等式 \(a=b-1\) 成立的一组 \(a,b\) ,无解输出-1. 题解:很显然只有 \( ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) D. Power Products
链接: https://codeforces.com/contest/1247/problem/D 题意: You are given n positive integers a1,-,an, and ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) C. p-binary
链接: https://codeforces.com/contest/1247/problem/C 题意: Vasya will fancy any number as long as it is a ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) B2. TV Subscriptions (Hard Version)
链接: https://codeforces.com/contest/1247/problem/B2 题意: The only difference between easy and hard ver ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) F. Tree Factory 构造题
F. Tree Factory Bytelandian Tree Factory produces trees for all kinds of industrial applications. Yo ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) E. Rock Is Push dp
E. Rock Is Push You are at the top left cell (1,1) of an n×m labyrinth. Your goal is to get to the b ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) B. TV Subscriptions 尺取法
B2. TV Subscriptions (Hard Version) The only difference between easy and hard versions is constraint ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) A. Forgetting Things 水题
A. Forgetting Things Kolya is very absent-minded. Today his math teacher asked him to solve a simple ...
- Codeforces Round #596 (Div. 2, based on Technocup 2020 Elimination Round 2) D. Power Products 数学 暴力
D. Power Products You are given n positive integers a1,-,an, and an integer k≥2. Count the number of ...
随机推荐
- [转帖]Linux 中的零拷贝技术,第 1 部分
Linux 中的零拷贝技术,第 1 部分 https://www.ibm.com/developerworks/cn/linux/l-cn-zerocopy1/index.html 引言 传统的 ...
- ASP.NET请求过程-Handler
什么事Handler asp.net程序所有的请求都是handler处理的.以前的webform我们访问的地址是xxxxx.aspx地址,其实他也会到一个handler(我们写的业务代码都在handl ...
- (十四)JDBC入门
目录 什么是JDBC 操作JDBC的步骤 DriverManager对象 数据库URL Connection对象 Statement对象 ResultSet对象 常用数据类型转换表 释放资源 SQL注 ...
- GCC 高版本7.4 编译链接 boost 报错 boost::thread::XXX’未定义的引用 解决方法
背景:开发中的项目之前一直用GCC4.8,boost库1.48版本的开发环境.现在因业务需求,需要更换GCC7.4,boost库1.70. 问题:可以正常编译BOOST的链接库文件,但是链接时候报错. ...
- scratch少儿编程第一季——02、scratch界面介绍
各位小伙伴大家好: 上期我们简单的介绍了Scratch的一些基本信息,和scratch软件的下载. 今天我们一起来了解一下Scratch的编程界面的介绍. 关于版本我考虑之后还是决定基于Scratch ...
- SAS学习笔记18 length、lengthn、lengthc函数
- VS2013+WDK8.1 驱动开发环境配置
Windows Driver Kit 是一种完全集成的驱动程序开发工具包,它包含 WinDDK 用于测试 Windows 驱动器的可靠性和稳定性,本次实验使用的是 WDK8.1 驱动开发工具包,该工具 ...
- 时间格式_java
@Test public void testDate(){ Date date=new Date(); System.out.println(date); /*日期格式*/ DateFormat df ...
- Unity中的Character Controller
Unity中默认提供了一个Character Controller的组件用于实现角色控制,一个3D的游戏物体,可以直接添加.Character Controller会自动模拟出Capsule Coll ...
- Django对postgresql数据库进行分组聚合查询
action(methods=['GET'], detail=False, url_path='count') def count(self, request): """ ...