374. Guess Number Higher or Lower 简单的二分法运用
We are playing the Guess Game. The game is as follows:
I pick a number from 1 to n. You have to guess which number I picked.
Every time you guess wrong, I'll tell you whether the number is higher or lower.
You call a pre-defined API guess(int num) which returns 3 possible results (-1, 1, or 0):
-1 : My number is lower
1 : My number is higher
0 : Congrats! You got it!
Example:
n = 10, I pick 6. Return 6. 简单的猜高猜低,运用二分法折半寻找。
在做题过程中,遇到了Time limit exceeded 百思不得其解
另外发现 自己对于一般的算法没有什么概念,每次做题都是从简单的数学原创方法开始,
找时间要去看一下算法的归纳,这样就可以在看见题目的同时知道对应的什么算法。
下面是程序:
// Forward declaration of guess API.
// @param num, your guess
// @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
int guess(int num); class Solution {
public:
int guessNumber(int n) {
if (guess(n) == 0) return n;
int left = 1, right = n;
while (left < right) {
int mid = left + (right - left) / 2, t = guess(mid);
if (t == 0) return mid;
else if (t == 1) left = mid;
else right = mid;
}
return left;
}
};
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