Baseball Game
You're now a baseball game point recorder.
Given a list of strings, each string can be one of the 4 following types:
Integer(one round's score): Directly represents the number of points you get in this round."+"(one round's score): Represents that the points you get in this round are the sum of the last twovalidround's points."D"(one round's score): Represents that the points you get in this round are the doubled data of the lastvalidround's points."C"(an operation, which isn't a round's score): Represents the lastvalidround's points you get were invalid and should be removed.
Each round's operation is permanent and could have an impact on the round before and the round after.
You need to return the sum of the points you could get in all the rounds.
Example 1:
Input: ["5","2","C","D","+"]
Output: 30
Explanation:
Round 1: You could get 5 points. The sum is: 5.
Round 2: You could get 2 points. The sum is: 7.
Operation 1: The round 2's data was invalid. The sum is: 5.
Round 3: You could get 10 points (the round 2's data has been removed). The sum is: 15.
Round 4: You could get 5 + 10 = 15 points. The sum is: 30.
Example 2:
Input: ["5","-2","4","C","D","9","+","+"]
Output: 27
Explanation:
Round 1: You could get 5 points. The sum is: 5.
Round 2: You could get -2 points. The sum is: 3.
Round 3: You could get 4 points. The sum is: 7.
Operation 1: The round 3's data is invalid. The sum is: 3.
Round 4: You could get -4 points (the round 3's data has been removed). The sum is: -1.
Round 5: You could get 9 points. The sum is: 8.
Round 6: You could get -4 + 9 = 5 points. The sum is 13.
Round 7: You could get 9 + 5 = 14 points. The sum is 27.
Note:
- The size of the input list will be between 1 and 1000.
- Every integer represented in the list will be between -30000 and 30000.
public int calPoints(String[] ops) {
if(ops == null || ops.length == 0)
return 0;
int []points = new int[ops.length];
int point = -1;
int sum = 0;
for(String op : ops){
if(op.equals("+")){
sum = points[point] + points[point - 1];
points[++ point] = sum;
}else if(op.equals("D")){
sum = points[point] * 2;
points[++ point] = sum;
}else if(op.equals("C")){
point --;
}else{
points[++point] = Integer.parseInt(op);
}
}
sum = 0;
for(int i = 0; i <= point; i++){
sum += points[i];
}
return sum;
}
优化,少遍历一遍
public int calPoints(String[] ops) {
if(ops == null || ops.length == 0)
return 0;
int []points = new int[ops.length];
int point = -1;
int sum = 0;
int temp = 0;
for(String op : ops){
if(op.equals("+")){
temp = points[point] + points[point - 1];
points[++point] = temp;
sum += temp;
}else if(op.equals("D")){
temp = points[point] * 2;
points[++ point] = temp;
sum += temp;
}else if(op.equals("C")){
sum -= points[point];
point --;
}else{
points[++point] = Integer.parseInt(op);
sum += points[point];
}
}
return sum;
}
Baseball Game的更多相关文章
- Simulation of empirical Bayesian methods (using baseball statistics)
Previously in this series: The beta distribution Empirical Bayes estimation Credible intervals The B ...
- [LeetCode] Baseball Game 棒球游戏
You're now a baseball game point recorder. Given a list of strings, each string can be one of the 4 ...
- [Swift]LeetCode682. 棒球比赛 | Baseball Game
You're now a baseball game point recorder. Given a list of strings, each string can be one of the 4 ...
- (string stoi 栈)leetcode682. Baseball Game
You're now a baseball game point recorder. Given a list of strings, each string can be one of the 4 ...
- LeetCode 682 Baseball Game 解题报告
题目要求 You're now a baseball game point recorder. Given a list of strings, each string can be one of t ...
- LeetCode - Baseball Game
You're now a baseball game point recorder. Given a list of strings, each string can be one of the 4 ...
- [LeetCode&Python] Problem 682. Baseball Game
You're now a baseball game point recorder. Given a list of strings, each string can be one of the 4 ...
- Stack-682. Baseball Game
You're now a baseball game point recorder. Given a list of strings, each string can be one of the 4 ...
- Programming Assignment 3: Baseball Elimination
编程作业三 作业链接:Baseball Elimination & Checklist 我的代码:BaseballElimination.java 问题简介 这是一个最大流模型的实际应用问题: ...
- 682. Baseball Game 棒球游戏 按字母处理
[抄题]: You're now a baseball game point recorder. Given a list of strings, each string can be one of ...
随机推荐
- [Swift]八大排序算法(六):希尔排序
排序分为内部排序和外部排序. 内部排序:是指待排序列完全存放在内存中所进行的排序过程,适合不太大的元素序列. 外部排序:指的是大文件的排序,即待排序的记录存储在外存储器上,待排序的文件无法一次装入内存 ...
- Python——selenium爬取斗鱼房间信息
from selenium import webdriver import os import json import time class Douyu: def __init__(self): # ...
- [译文]Casperjs1.1.0参考文档-快速开始
快速开始 只要casperjs被正确安装,你就可以开始写你的第一个脚本,你可以使用javascript或者coffiescript编译脚本. 提示: 如果你对javascript不是很熟悉,最好先看专 ...
- [ADB Shell]Android Debug Bridge常用命令
ADB用法 *:first-child { margin-top: 0 !important; } body>*:last-child { margin-bottom: 0 !important ...
- jquery遇到的坑
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...
- Python web前端 05 JavaScript
Python web前端 05 JavaScript 一.获取元素 1.初识JavaScript /* .. */ #这是多行注释 // #这是单行注释 #JavaScript是一种脚本语言,是一种动 ...
- [CSU1911]Card Game(FWT)
[vjudge-CSU1911] FWT_or #include<cstring> #include<iostream> #include<algorithm> # ...
- express运行www后,在http://localhost:3000/查看返回会报 Cannot find module 'jade'
解决方法:npm install --save express jade
- BZOJ - 2005 莫比乌斯水题
\(gcd=k+1\)时,每一个的贡献都是\(2k+1\) \(gcd=1\)时,每一个贡献为\(1\) #include<iostream> #include<algorithm& ...
- VBS添加Windows登陆账号
Set o=CreateObject( "Shell.Users" ) Set z=o.create("test") z.changePassword &quo ...