odeforces Beta Round #77 (Div. 2 Only)
2 seconds
256 megabytes
standard input
standard output
Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.
The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field.
Print "YES" if the situation is dangerous. Otherwise, print "NO".
001001
NO
1000000001
YES
#include<bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
if(s.find("")!=string::npos||s.find("")!=string::npos)cout<<"YES";
else cout<<"NO";
cout<<endl;
return ;
}
odeforces Beta Round #77 (Div. 2 Only)的更多相关文章
- Codeforces Beta Round #77 (Div. 2 Only)
Codeforces Beta Round #77 (Div. 2 Only) http://codeforces.com/contest/96 A #include<bits/stdc++.h ...
- Codeforces Beta Round #77 (Div. 1 Only) C. Volleyball (最短路)
题目链接:http://codeforces.com/contest/95/problem/C 思路:首先dijkstra预处理出每个顶点到其他顶点的最短距离,然后如果该出租车到某个顶点的距离小于等于 ...
- codeforces水题100道 第二十三题 Codeforces Beta Round #77 (Div. 2 Only) A. Football (strings)
题目链接:http://www.codeforces.com/problemset/problem/96/A题意:判断一个0-1字符串中出现的最长的0字串或者1字串的长度是否大于等于7.C++代码: ...
- Codeforces Beta Round #77 (Div. 2 Only) A. Football【字符串/判断是否存在连续7个0或7个1】
A. Football time limit per test 2 seconds memory limit per test 256 megabytes input standard input o ...
- Codeforces Beta Round #80 (Div. 2 Only)【ABCD】
Codeforces Beta Round #80 (Div. 2 Only) A Blackjack1 题意 一共52张扑克,A代表1或者11,2-10表示自己的数字,其他都表示10 现在你已经有一 ...
- Codeforces Beta Round #83 (Div. 1 Only)题解【ABCD】
Codeforces Beta Round #83 (Div. 1 Only) A. Dorm Water Supply 题意 给你一个n点m边的图,保证每个点的入度和出度最多为1 如果这个点入度为0 ...
- Codeforces Beta Round #79 (Div. 2 Only)
Codeforces Beta Round #79 (Div. 2 Only) http://codeforces.com/contest/102 A #include<bits/stdc++. ...
- Codeforces Beta Round #76 (Div. 2 Only)
Codeforces Beta Round #76 (Div. 2 Only) http://codeforces.com/contest/94 A #include<bits/stdc++.h ...
- Codeforces Beta Round #75 (Div. 2 Only)
Codeforces Beta Round #75 (Div. 2 Only) http://codeforces.com/contest/92 A #include<iostream> ...
随机推荐
- Dubbo超时和重连机制
dubbo启动时默认有重试机制和超时机制.超时机制的规则是如果在一定的时间内,provider没有返回,则认为本次调用失败,重试机制在出现调用失败时,会再次调用.如果在配置的调用次数内都失败,则认为此 ...
- asmlinkage
转自:http://www.cnblogs.com/china_blue/archive/2010/01/15/1648523.html 声明,仅为了便于自己记忆和查询,非原创,摘自:http://b ...
- 谈谈Delphi中的类和对象3---抽象类和它的实例
四.抽象类和它的实例 Delphi中有一个类称为是抽象类,你不能天真的直接为它创建一个实例,如 var StrLst: TString; begin StrLst:= TString.Create; ...
- sdut 1465 公共因子
公共因子 Time Limit: 1000MS Memory limit: 65536K 题目描述 题目链接:http://acm.sdut.edu.cn/sdutoj/problem.php?act ...
- ASP.NET 5探险(6):升级ASP.NET 5到beta6
(此文章同时发表在本人微信公众号"dotNET每日精华文章",欢迎右边二维码来关注.) 题记:微软根据ASP.NET 5的路线图如期发布了beta6,现在我们就来说说beta5升级 ...
- C[泊车管理系统]
// // main.c // 泊车管理系统 // // Created by 丁小未 on 13-7-14. // Copyright (c) 2013年 dingxiaowei. All ...
- BZOJ 1588: [HNOI2002]营业额统计 双向链表 / splay / treap
1588: [HNOI2002]营业额统计 Description 营业额统计 Tiger最近被公司升任为营业部经理,他上任后接受公司交给的第一项任务便是统计并分析公司成立以来的营业情况. Tiger ...
- Java学习笔记(四)——流程控制语句
一.条件语句 1.if条件语句 (1)语法: if(条件) { 条件成立时的代码 } (2)执行过程 2.if else语句 if(条件) { 条件成立时的代码 } else { 不成立的代码 } 3 ...
- 稀疏矩阵存储格式总结+存储效率对比:COO,CSR,DIA,ELL,HYB
稀疏矩阵是指矩阵中的元素大部分是0的矩阵,事实上,实际问题中大规模矩阵基本上都是稀疏矩阵,很多稀疏度在90%甚至99%以上.因此我们需要有高效的稀疏矩阵存储格式.本文总结几种典型的格式:COO,CSR ...
- 封装用className选元素
<!DOCTYPE html><html lang="en"><head> <meta charset="UTF-8" ...