TOJ 1885 Triangles

Description

It is always very nice to have little brothers or sisters. You can tease them, lock them in the bathroom or put red hot chili in their sandwiches. But there is also a time when all meanness comes back!
As
you know, in one month it is Christmas and this year you are honored to
make the big star that will be stuck on the top of the Christmas tree.
But when you get the triangle-patterned silver paper you realize that
there are many holes in it. Your little sister has already cut out
smaller triangles for the normal Christmas stars. Your only chance is to
find an algorithm that tells you for each piece of silver paper the
size of the largest remaining triangle.
Given a triangle
structure with white and black fields inside you must find the largest
triangle area of white fields, as shown in the following figure.

Input

The
input contains several triangle descriptions. The first line of each
description contains an integer n (1 <= n <= 100), which gives the
height of the triangle. The next n lines contain characters of the set
{space, #, -} representing the rows of the triangle, where `#' is a
black and `-' a white field. The spaces are used only to keep the
triangle shape in the input by padding at the left end of the lines.
(Compare with the sample input. The first test case corresponds to the
figure.)
For each triangle, the number of the characters `#' and `-' per line is odd and decreases from 2n - 1 down to 1.

The input is terminated by a description starting with n = 0.

Output

For
each triangle in the input, first output the number of the triangle, as
shown in the sample output. Then print the line "The largest triangle
area is a.", where a is the number of fields inside the largest triangle
that consists only of white fields. Note that the largest triangle can
have its point at the top, as in the second case of the sample input.

Output a blank line after each test case.

Sample Input

5
#-##----#
 -----#-
  ---#-
   -#-
    -
4
#-#-#--
 #---#
  ##-
   -
0

Sample Output

Triangle #1
The largest triangle area is 9.

Triangle #2
The largest triangle area is 4.

Source

Southwestern Europe 1997

今天组队练习的题目，cjx因为要赶学校所以就木有做了。跟想的一样应该用dp。暴力应该也可以。

当n=5时：

1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7
0 0 1 2 3 4 5
0 0 0 1 2 3
0 0 0 0 1

因为输入的前面有空格所以要+k
(1->((n-i+1)*2-1)+k) i=[1...n]

输入：
0 1 0 0 1 1 1 1 0
   1 1 1 1 1 0 1
      1 1 1 0 1
         1 0 1
            1

仔细观察三角形第偶数个的小三角形（无法跟上，左上，右上）组成新三角形。
从上往下遍历：j=[1,3,5,7]
dp[i][j]=min(dp[i-1][j-1],dp[i-1][j+1])+1

0 1 0 0 1 1 1 1 0
   1 1 1 1 2 0 1
      2 1 2 0 1
         3 0 1
           1

同样第奇数个的小三角形（无法跟下，左下，右下）组成新三角形。
从下往上遍历：j=[2,4,6,8]
dp[i][j]=min(dp[i+1][j-1],dp[i+1][j+1])+1

0 1 0 0 1 1 1 1 0
   1 1 1 1 2 0 1
      2 1 2 0 1
         3 0 1
            1

输出：max(dp[i][j])^2

 #include <stdio.h>
 #include <string.h>
 #include <iostream>
 #define MAXN 205
 using namespace std;

 int n;
 int dp[MAXN][MAXN];

 int main()
 {
     while( scanf("%d",&n)!=EOF && n ){
         memset(dp,,sizeof(dp));
         int k=;
         char ch;
         for(int i=; i<=n; i++){
             getchar();
             for(int j=; j<=((n-i+)*-)+k; j++){
                 scanf("%c",&ch);
                 if(ch==' ' || ch=='#'){
                     dp[i][j]=;
                 }
                 if(ch=='-'){
                     dp[i][j]=;
                 }
             }
             k++;
         }
         for(int i=; i<=n; i++){
             for(int j=i; j<=*n-i; j+=){
                 if(dp[i][j] && dp[i-][j]){
                     dp[i][j]=min( dp[i-][j-] , dp[i-][j+] )+;
                 }
             }
         }
         for(int i=n-; i>=; i--){
             for(int j=i+; j<=*n-i; j+=){
                 if(dp[i][j] && dp[i+][j]){
                     dp[i][j]=min( dp[i+][j-] , dp[i+][j+] )+;
                 }
             }
         }
         int ans=-;
         for(int i=; i<=n; i++){
             for(int j=i; j<=*n-i; j++){
                 if(dp[i][j]>ans){
                     ans=dp[i][j];
                 }
             }
         }
         printf("Triangle #%d\n",++c);
         printf("The largest triangle area is %d.\n",ans*ans);
         puts("");
     }
     return ;
 }