Safecracker

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12702    Accepted Submission(s): 6581

Problem Description
=== Op tech briefing, 2002/11/02 06:42 CST === 
"The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with Klein and his factory, were destroyed in World War II. Fortunately old Brumbaugh from research knew Klein's secrets and wrote them down before he died. A Klein safe has two distinguishing features: a combination lock that uses letters instead of numbers, and an engraved quotation on the door. A Klein quotation always contains between five and twelve distinct uppercase letters, usually at the beginning of sentences, and mentions one or more numbers. Five of the uppercase letters form the combination that opens the safe. By combining the digits from all the numbers in the appropriate way you get a numeric target. (The details of constructing the target number are classified.) To find the combination you must select five letters v, w, x, y, and z that satisfy the following equation, where each letter is replaced by its ordinal position in the alphabet (A=1, B=2, ..., Z=26). The combination is then vwxyz. If there is more than one solution then the combination is the one that is lexicographically greatest, i.e., the one that would appear last in a dictionary."

v - w^2 + x^3 - y^4 + z^5 = target

"For example, given target 1 and letter set ABCDEFGHIJKL, one possible solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are actually several solutions in this case, and the combination turns out to be LKEBA. Klein thought it was safe to encode the combination within the engraving, because it could take months of effort to try all the possibilities even if you knew the secret. But of course computers didn't exist then."

=== Op tech directive, computer division, 2002/11/02 12:30 CST ===

"Develop a program to find Klein combinations in preparation for field deployment. Use standard test methodology as per departmental regulations. Input consists of one or more lines containing a positive integer target less than twelve million, a space, then at least five and at most twelve distinct uppercase letters. The last line will contain a target of zero and the letters END; this signals the end of the input. For each line output the Klein combination, break ties with lexicographic order, or 'no solution' if there is no correct combination. Use the exact format shown below."

 
Sample Input
1 ABCDEFGHIJKL
11700519 ZAYEXIWOVU
3072997 SOUGHT
1234567 THEQUICKFROG
0 END
 
Sample Output
LKEBA
YOXUZ
GHOST
no solution

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN=;
int target,len;
char s[MAXN];
int vis[MAXN];
int buf[MAXN];
bool comp(char ch1,char ch2)
{
return ch1 > ch2;
}
bool dfs(int dep)
{
if(dep==)
{
long long sum=;
for(int i=;i<dep;i++)
{
long long e=;
for(int j=;j<=i;j++)
{
e*=buf[i];
}
if(i%==) sum+=e;
else sum-=e;
}
if(sum==(long long)target)
{
return true;
}
else
{
return false;
}
}
for(int i=;i<len;i++)
{
if(!vis[i])
{
vis[i]=;
buf[dep]=s[i]-'A'+;
if(dfs(dep+))
{
return true;
}
vis[i]=;
}
}
return false;
}
int main()
{
while(scanf("%d%s",&target,s)!=EOF)
{
if(target==&&strcmp(s,"END")==) break;
memset(vis,,sizeof(vis));
len=strlen(s);
sort(s,s+len,comp);
if(dfs())
{
for(int i=;i<;i++)
{
printf("%c",buf[i]+'A'-);
}
printf("%c\n",buf[]+'A'-);
}
else
{
printf("no solution\n");
}
}
return ;
}

HDOJ1015(简单深搜)的更多相关文章

  1. POJ 2386 Lake Counting (简单深搜)

    Description Due to recent rains, water has pooled in various places in Farmer John's field, which is ...

  2. 简单深搜:POJ1546——Sum it up

    结束了三分搜索的旅程 我开始迈入深搜的大坑.. 首先是一道比较基础的深搜题目(还是很难理解好么) POJ 1564 SUM IT UP 大体上的思路无非是通过深搜来进行穷举.匹配 为了能更好地理解深搜 ...

  3. poj 1562 简单深搜

    //搜八个方向即可 #include<stdio.h> #include<string.h> #define N 200 char ma[N][N]; int n,m,vis[ ...

  4. POJ-1321棋盘问题(简单深搜)

    简单搜索step1 POJ-1321 这是第一次博客,题目也很简单,主要是注意格式书写以及常见的快速输入输出和文件输入输出的格式. 递归的时候注意起始是从(-1,-1)开始,然后每次从下一行开始递归. ...

  5. NYoj The partial sum problem(简单深搜+优化)

    题目链接:http://acm.nyist.edu.cn/JudgeOnline/problem.php?pid=927 代码: #include <stdio.h> #include & ...

  6. nyoj587 hdu1045 简单深搜

    #include<iostream> #include<cstdio> #include<queue> #include<vector> #includ ...

  7. poj 2386:Lake Counting(简单DFS深搜)

    Lake Counting Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18201   Accepted: 9192 De ...

  8. 【笔记】「pj复习」深搜——简单剪枝

    深搜--简单剪枝 说在最前面: 因为马上要 NOIP2020 了,所以菜鸡开始了复习qwq. pj 组 T1 ,T2 肯定要拿到满分的,然后 T3 , T4 拿部分分, T3 拿部分分最常见的做法就是 ...

  9. 【BZOJ】1016: [JSOI2008]最小生成树计数 深搜+并查集

    最小生成树计数 Description 现在给出了一个简单无向加权图.你不满足于求出这个图的最小生成树,而希望知道这个图中有多少个不同的最小生成树.(如果两颗最小生成树中至少有一条边不同,则这两个最小 ...

随机推荐

  1. 自定义弹窗 VS AlertDialog分享弹窗

    一.摘要 弹窗通常用于提示用户进行某种操作,比如:点击分享按钮,弹窗分享对话框:双击返回按钮,弹窗退出对话框:下载文件,提示下载对话框等等,分享对话框/退出对话框/下载对话框,都可以直接使用Alert ...

  2. ExtJS4.2.1与Spring MVC实现Session超时控制

    假设你的项目使用ExtJS作为表现层.你会发现,SESSION超时控制将是一个问题. 本文将就自己的经验.来解决这一问题.当然,解决这个问题并不是仅仅有一种方法,我仅仅是提出我的方法. 首先.做超时控 ...

  3. linux c编程:Posix共享内存区

    Posix共享内存区:共享内存是最快的可用IPC形式.它允许多个不相关(无亲缘关系)的进程去访问同一部分逻辑内存.如果需要在两个进程之间传输数据,共享内存将是一种效率极高的解决方案.一旦这样的内存区映 ...

  4. 搜索ABAP程序代码中的字符串

    标准程序名:RPR_ABAP_SOURCE_SCAN /BEV1/NERM07DOCS

  5. Android动画效果animation

    1.Tween 根据指定动画开始和结束时的对象属性(位置.Alpha值(透明度).大小.角度等)以及动画播放的时间长度生成动画: 2.Frame 指定每一帧所播放的图片和时间长度.   建立动画的方法 ...

  6. VMware Integrated OpenStack (VIO)简介

    VMware Integrated OpenStack是一款由VMware提供支持的OpenStack发行版软件,用于帮助IT在现有的VMware基础架构之上更加轻松地运行基于生产级OpenStack ...

  7. Linux与Windows编译器的区别

    移植工作開始后的第一步就是在目标平台Linux上进行编译,并链接源码.因为须要移植的软件通常并未在Linux平台上编译过,编译的过程可能会遇到非常大的困难.普通情况下,由类型声明引起的编译错误是比較e ...

  8. ZOJ - 3705 Applications 【模拟】

    题目链接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3705 题意 给出N个队员 然后一个教练要从中选择 M名队员 要选 ...

  9. echarts相关设置

    1.显示隐藏工具栏 注释toolbox即可 /*    toolbox: {         show : true,         feature : {             dataView ...

  10. hiho一下 第四十八周 拓扑排序·二【拓扑排序的应用 + 静态数组 + 拓扑排序算法的时间优化】

    题目1 : 拓扑排序·二 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 小Hi和小Ho所在学校的校园网被黑客入侵并投放了病毒.这事在校内BBS上立刻引起了大家的讨论,当 ...