Packet Anatomy

This is the anatomy of one packet. It is inspired by the CAN and SAE AS-4 standards.

Byte Index Content Value Explanation
0 Packet start sign v1.0: 0xFE (v0.9: 0x55) Indicates the start of a new packet.
1 Payload length 0 - 255 Indicates length of the following payload.
2 Packet sequence 0 - 255 Each component counts up his send sequence. Allows to detect packet loss
3 System ID 1 - 255 ID of the SENDING system. Allows to differentiate different MAVs on the same network.
4 Component ID 0 - 255 ID of the SENDING component. Allows to differentiate different components of the same system, e.g. the IMU and the autopilot.
5 Message ID 0 - 255 ID of the message - the id defines what the payload “means” and how it should be correctly decoded.
6 to (n+6) Data (0 - 255) bytes Data of the message, depends on the message id.
(n+7) to (n+8) Checksum (low byte, high byte) ITU X.25/SAE AS-4 hash, excluding packet start sign, so bytes 1..(n+6)
Note: The checksum also includes MAVLINK_CRC_EXTRA (Number computed
from message fields. Protects the packet from decoding a different
version of the same packet but with different variables).
    • The checksum is the same as used in ITU X.25 and SAE AS-4 standards (CRC-16-CCITT), documented in SAE AS5669A. Please see the MAVLink source code for a documented C-implementation of it. LINK TO CHECKSUM
    • The minimum packet length is 8 bytes for acknowledgement packets without payload
    • The maximum packet length is 263 bytes for full payload

mavlink 笔记1的更多相关文章

  1. MAVLink Linux/QNX/MacOs Integration Tutorial (UDP)

    MAVLink Linux/QNX/MacOs Integration Tutorial (UDP) Overview This program was written to test the udp ...

  2. MAVLink Onboard Integration Tutorial

    MAVLink Onboard Integration Tutorial MAVLink is a header-only library, which means that you don't ha ...

  3. [pixhawk笔记]5-uORB消息传递

    本文主要内容翻译自官方文档:https://dev.px4.io/en/middleware/uorb.html 在前一篇笔记中使用uORB完成消息传递,实现了一个简单示例程序,本文将对uORB进行系 ...

  4. [pixhawk笔记]4-如何写一个简单的应用程序

    本文主要内容来自于:https://dev.px4.io/en/tutorials/tutorial_hello_sky.html,并对文档中的部分问题进行更正. 本文假设已经建立好开发环境并能正确编 ...

  5. 移植mavlink到stm32详细教程,后面附快速移植方法

    一:准备材料: mavlink源码 stm32串口程序    1.mavlink源码:        a.进入mavlink官网(http://qgroundcontrol.org/mavlink/s ...

  6. 移植mavlink协议到STM32详细教程

    1准备材料, 首先准备一个带串口的stm32程序(这里选用整点原子的官方串口例程这里自己去找不讲)作者:恒久力行 QQ:624668529,然后去mavlink官网下载mavlink源码,这里重点讲解 ...

  7. Mavlink协议理解

    来源:blog.csdn.net/super_mice/article/details/44836585 之前看了mavlink协议,网上关于mavlink的资料不多.本文大概总结了下对mavlink ...

  8. Mavlink消息包解析

    Byte Index 字节索引 Content 内容 Value 值 Explanation 说明 0 包起始标志 v1.0: 0xFE (v0.9: 0x55) 指示新消息帧的开始.在v1.0版本中 ...

  9. Mavlink 协议 理解

    来源:blog.csdn.net/super_mice/article/details/44836585 之前看了mavlink协议,网上关于mavlink的资料不多.本文大概总结了下对mavlink ...

随机推荐

  1. redis数据备份还原

    安装ruby yum install ruby rubygems ruby-devel -y 安装rvm gpg2 --keyserver hkp://pool.sks-keyservers.net ...

  2. leetcood学习笔记-226- 翻转二叉树

    题目描述: 第一次提交: class Solution(object): def invertTree(self, root): """ :type root: Tree ...

  3. Nginx的静态代理

    Nginx的静态代理 Nginx的web请求的处理机制 Nginx结合多进程和异步机制对外提供服务,异步机制使用的是异步非阻塞机制,即AIO,Nginx的master进程会生成多个worker进程,m ...

  4. 下面是一段delphi代码,你在c# 中引入api 即可

    procedure TForm1.Button1Click(Sender: TObject);var i:HWND; cs:CREATESTRUCT;begin// i := FindWindowEx ...

  5. delphi 压缩

    DELPHI 通过ZLib来压缩文件夹 unit Unit1; interface uses ZLib, Windows, Messages, SysUtils, Variants, Classes, ...

  6. Optimal Marks SPOJ - OPTM

    传送门 一个无向图,每个点有点权,某些点点权确定了,某些点由你来确定,边权为两个点的异或和,要使边权和最小. 这不是一道按位做最小割的大水题么 非常开心地打了,还非常开心地以为有spj,然后非常开心地 ...

  7. NTT数论变换

    数论变换NTT 前置知识 FFT:NTT的思想和FFT一样(FFT介绍) 概述 数论变换,即NTT(Number Theory Transformation?),是基于数论域的FFT,一般我们默认FF ...

  8. Spring-Security (补充)

    一.配置静态资源过滤 直接在xml中配置即可 <!-- 配置静态资源过滤 --> <security:http security="none" pattern=& ...

  9. P2004 领地选择

    P2004 领地选择 题目描述 作为在虚拟世界里统帅千军万马的领袖,小Z认为天时.地利.人和三者是缺一不可的,所以,谨慎地选择首都的位置对于小T来说是非常重要的. 首都被认为是一个占地C*C的正方形. ...

  10. LeetCode 1041. Robot Bounded In Circle (困于环中的机器人)

    题目标签:Math 题目让我们判断机器人是否是一直在走一个圈. 当我们把 instructions 走完一遍时候: 1. 如果机器人回到了原点,那么它是在走一个圈. 2. 如果机器人的方向没有改变,那 ...