Write a program to test if a give sequence Seq is a topological order of a given graph Graph.

Format of functions:

bool IsTopSeq( LGraph Graph, Vertex Seq[] );

where LGraph is defined as the following:

typedef struct AdjVNode *PtrToAdjVNode;
struct AdjVNode{
Vertex AdjV;
PtrToAdjVNode Next;
}; typedef struct Vnode{
PtrToAdjVNode FirstEdge;
} AdjList[MaxVertexNum]; typedef struct GNode *PtrToGNode;
struct GNode{
int Nv;
int Ne;
AdjList G;
};
typedef PtrToGNode LGraph;

The function IsTopSeq must return true if Seq does correspond to a topological order; otherwise return false.

Note: Although the vertices are numbered from 1 to MaxVertexNum, they are indexed from 0 in the LGraph structure.

Sample program of judge:

#include <stdio.h>
#include <stdlib.h> typedef enum {false, true} bool;
#define MaxVertexNum 10 /* maximum number of vertices */
typedef int Vertex; /* vertices are numbered from 1 to MaxVertexNum */ typedef struct AdjVNode *PtrToAdjVNode;
struct AdjVNode{
Vertex AdjV;
PtrToAdjVNode Next;
}; typedef struct Vnode{
PtrToAdjVNode FirstEdge;
} AdjList[MaxVertexNum]; typedef struct GNode *PtrToGNode;
struct GNode{
int Nv;
int Ne;
AdjList G;
};
typedef PtrToGNode LGraph; LGraph ReadG(); /* details omitted */ bool IsTopSeq( LGraph Graph, Vertex Seq[] ); int main()
{
int i, j, N;
Vertex Seq[MaxVertexNum];
LGraph G = ReadG();
scanf("%d", &N);
for (i=; i<N; i++) {
for (j=; j<G->Nv; j++)
scanf("%d", &Seq[j]);
if ( IsTopSeq(G, Seq)==true ) printf("yes\n");
else printf("no\n");
} return ;
} /* Your function will be put here */

Sample Input (for the graph shown in the figure):


Sample Output:

yes
yes
yes
no
no

题目的大致意思就是,给你一组数据,根据这组数据构建一个有向图,再给你几组序列,判断是不是拓扑序列。

思路:先确定每个结点的入度数,按拓扑顺序输出结点时,每输出一个结点,将其子结点的入度数 -1.

注意:输入的顶点是从 0 开始存放的,也就是

0 1 2 3 4
G1 G2 G3 G4 G5
struct AdjVNode{
Vertex AdjV;
PtrToAdjVNode Next;
};
中的 AdjV,也是从 0 开始存放。

代码

bool IsTopSeq( LGraph Graph, Vertex Seq[] ){
int inDegree[];
for(int i=;i<=Graph->Nv;i++)
inDegree[i]=;
PtrToAdjVNode temnode;
for(int i=;i<Graph->Nv;i++){
temnode=Graph->G[i].FirstEdge;
while (temnode){
inDegree[temnode->AdjV]++;
temnode=temnode->Next;
}
}
for(int i=;i<Graph->Nv;i++){
if(inDegree[Seq[i]-]!=)
return false;
else{
temnode=Graph->G[Seq[i]-].FirstEdge;
while(temnode){
inDegree[temnode->AdjV]--;
temnode=temnode->Next;
}
}
}
return true;
}

PTA Is Topological Order的更多相关文章

  1. A1146. Topological Order

    This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topol ...

  2. PAT A1146 Topological Order (25 分)——拓扑排序,入度

    This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topol ...

  3. PAT 甲级 1146 Topological Order

    https://pintia.cn/problem-sets/994805342720868352/problems/994805343043829760 This is a problem give ...

  4. PAT 1146 Topological Order[难]

    1146 Topological Order (25 分) This is a problem given in the Graduate Entrance Exam in 2018: Which o ...

  5. [PAT] 1146 Topological Order(25 分)

    This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topol ...

  6. PAT 1146 Topological Order

    This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topol ...

  7. PAT_A1146#Topological Order

    Source: PAT A1146 Topological Order (25 分) Description: This is a problem given in the Graduate Entr ...

  8. PAT 甲级 1146 Topological Order (25 分)(拓扑较简单,保存入度数和出度的节点即可)

    1146 Topological Order (25 分)   This is a problem given in the Graduate Entrance Exam in 2018: Which ...

  9. 1146. Topological Order (25)

    This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topol ...

随机推荐

  1. java.lang.NullPointerException at org.apache.jsp.**_jsp.jspInit(**_jsp.java)tomcat启动异常解决方法

    今天遇到的其他一个问题就是,启动tomcat时,报:java.lang.NullPointerException at org.apache.jsp.**_jsp.jspInit(index_jsp. ...

  2. Java实现多线程下载,支持断点续传

    完整代码:https://github.com/iyuanyb/Downloader 多线程下载及断点续传的实现是使用 HTTP/1.1 引入的 Range 请求参数,可以访问Web资源的指定区间的内 ...

  3. Codeforces_828

    A.模拟,注意单人的时候判断顺序. #include<bits/stdc++.h> using namespace std; int n,a,b; int main() { ios::sy ...

  4. 微信小程序开发技巧总结(二) -- 文件的选取、移动、上传和下载

    微信小程序开发技巧总结(二) -- 文件的选取.移动.上传和下载 1.不同类型文件的选取 1.1 常用的图片 视频 对于大部分开发者来说,需要上传的文件形式主要为图片,微信为此提供了接口. wx.ch ...

  5. 大数据篇:HDFS

    HDFS HDFS是什么? Hadoop分布式文件系统(HDFS)是指被设计成适合运行在通用硬件(commodity hardware)上的分布式文件系统(Distributed File Syste ...

  6. Go语言实现:【剑指offer】数字在排序数组中出现的次数

    该题目来源于牛客网<剑指offer>专题. 统计一个数字在排序数组中出现的次数. 看到排序数组,要想到用二分查找. 先找到最前面的数字k,再找到最后面的数字k,通过下标求出次数. Go语言 ...

  7. 实验楼-python3简明教程笔记

    #!/usr/bin/env python3 days = int(input("Enter days: ")) print("Months = {} Days = {} ...

  8. 性能优化-CPU占用过高问题排查

    1. 性能优化是什么? 1.1 性能优化就是发挥机器本来的性能 1.2 性能瓶颈在哪里,木桶效应.   CPU占用过高 1.现象重现 CPU占用过高一般情况是代码中出现了循环调用,最容易出现的情况有几 ...

  9. Pyinstaller 打包程序为可执行文件exe

    Pyiinstaller打包 pyinstaller是python的一个第三方模块,使用它可以将pythnon程序打包为可执行文件,实现打包后的程序在没有python环境的机器上也可以运行.pyins ...

  10. GNU C相关

    GNU __attribute__ 用于在函数声明时,定义函数参数的一些特殊属性,比如,如果函数的某个参数可能用不到,那么,将该参数增加unused属性即可,如下(一般用两个括号包括属性unused) ...