PAT A1132 Cut Integer （20 分）——数学题

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <2​31​​). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

Sample Output:

Yes
No
No

 #include <stdio.h>
 #include <string>
 #include <iostream>
 using namespace std;
 int s2n(string s){
   int res=;
   for(int i=;i<s.length();i++){
     res = *res + s[i]-'';
   }
   return res;
 }
 int main(){
   string s;
   int n;
   scanf("%d",&n);
   for(int i=;i<n;i++){
     cin>>s;
     int pos=s.length()/;
     string s1,s2;
     int n1,n2;
     s1=s.substr(,pos);
     s2=s.substr(pos,s.length()-pos);
     n1=s2n(s1);
     n2=s2n(s2);
     if((n1== || n2==) || s2n(s)%(n1*n2)!=)printf("No\n");
     else printf("Yes\n");
   }
 }

注意点：后面两个测试点是其中一半为0的情况，要额外判断。显示浮点错误说明除数遇到了0。