443. String Compression

Easy

Given an array of characters, compress it in-place.

The length after compression must always be smaller than or equal to the original array.

Every element of the array should be a character (not int) of length 1.

After you are done modifying the input array in-place, return the new length of the array.

Follow up:
Could you solve it using only O(1) extra space?

Example 1:

Input:
["a","a","b","b","c","c","c"] Output:
Return 6, and the first 6 characters of the input array should be: ["a","2","b","2","c","3"] Explanation:
"aa" is replaced by "a2". "bb" is replaced by "b2". "ccc" is replaced by "c3".

Example 2:

Input:
["a"] Output:
Return 1, and the first 1 characters of the input array should be: ["a"] Explanation:
Nothing is replaced.

Example 3:

Input:
["a","b","b","b","b","b","b","b","b","b","b","b","b"] Output:
Return 4, and the first 4 characters of the input array should be: ["a","b","1","2"]. Explanation:
Since the character "a" does not repeat, it is not compressed. "bbbbbbbbbbbb" is replaced by "b12".
Notice each digit has it's own entry in the array.

Note:

  1. All characters have an ASCII value in [35, 126].
  2. 1 <= len(chars) <= 1000.
package leetcode.easy;

public class StringCompression {
public int compress(char[] chars) {
int indexAns = 0, index = 0;
while (index < chars.length) {
char currentChar = chars[index];
int count = 0;
while (index < chars.length && chars[index] == currentChar) {
index++;
count++;
}
chars[indexAns] = currentChar;
indexAns++;
if (count != 1) {
for (char c : String.valueOf(count).toCharArray()) {
chars[indexAns] = c;
indexAns++;
}
}
}
return indexAns;
} @org.junit.Test
public void test() {
char[] chars1 = { 'a', 'a', 'b', 'b', 'c', 'c', 'c' };
char[] chars2 = { 'a' };
char[] chars3 = { 'a', 'b', 'b', 'b', 'b', 'b', 'b', 'b', 'b', 'b', 'b', 'b', 'b' };
System.out.println(compress(chars1));
System.out.println(compress(chars2));
System.out.println(compress(chars3));
}
}

LeetCode_443. String Compression的更多相关文章

  1. 【leetcode】443. String Compression

    problem 443. String Compression Input ["a","a","b","b"," ...

  2. UVA 1351 十三 String Compression

    String Compression Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit ...

  3. 443. String Compression

    原题: 443. String Compression 解题: 看到题目就想到用map计数,然后将计数的位数计算处理,这里的解法并不满足题目的额外O(1)的要求,并且只是返回了结果array的长度,并 ...

  4. CF825F String Compression 解题报告

    CF825F String Compression 题意 给定一个串s,其中重复出现的子串可以压缩成 "数字+重复的子串" 的形式,数字算长度. 只重复一次的串也要压. 求压缩后的 ...

  5. 213. String Compression【LintCode java】

    Description Implement a method to perform basic string compression using the counts of repeated char ...

  6. 213. String Compression【easy】

    Implement a method to perform basic string compression using the counts of repeated characters. For ...

  7. codeforces 825F F. String Compression dp+kmp找字符串的最小循环节

    /** 题目:F. String Compression 链接:http://codeforces.com/problemset/problem/825/F 题意:压缩字符串后求最小长度. 思路: d ...

  8. Codeforces 825F - String Compression

    825F - String Compression 题意 给出一个字符串,你要把它尽量压缩成一个短的字符串,比如一个字符串ababab你可以转化成3ab,长度为 3,比如bbbacacb转化成3b2a ...

  9. 区间DP UVA 1351 String Compression

    题目传送门 /* 题意:给一个字符串,连续相同的段落可以合并,gogogo->3(go),问最小表示的长度 区间DP:dp[i][j]表示[i,j]的区间最小表示长度,那么dp[i][j] = ...

随机推荐

  1. Python入门篇-数据结构树(tree)篇

    Python入门篇-数据结构树(tree)篇 作者:尹正杰 版权声明:原创作品,谢绝转载!否则将追究法律责任. 一.树概述 1>.树的概念 非线性结构,每个元素可以有多个前躯和后继 树是n(n& ...

  2. Java 返回字符串中第一个不重复字符的下标 下标从0开始

    比如abcdefgabdef 其中字符c和g不重复,返回c的小标,下标从0开始,那么是2 package com.example.demo; import org.testng.annotations ...

  3. redis启动异常处理一例

    rm -rf /var/log/redis/redis.log echo "net.core.somaxconn= 1024" >> /etc/sysctl.conf ...

  4. Linux的rwx

  5. 2019安徽省程序设计竞赛 D.自驾游(最短路)

    这道题最后没过,估计是痛失省一了,现在来补一下,当时思路是对的应该是代码出了问题导致样例没过最后nc的除了2,一直WA 题意: 给一张联通图,有两个导航系统,其中一个系统认为第i条边的权值是Pi,另一 ...

  6. 基于appium快速实现H5自动化测试

    一.下载Appium-Server及库文件 库文件:jar包:java-client-3.1.0.jar Appium-Server:Appium服务器: 注:Appium包含客户端和服务端,客户端就 ...

  7. linux 服务器配置 ASF 云挂卡

    关于社区打不开:https://github.com/zyfworks/AnotherSteamCommunityFix 下载asf:https://github.com/JustArchi/Arch ...

  8. js正则实现从一段复杂html代码字符串中匹配并处理特定信息

    js正则实现从一段复杂html代码字符串中匹配并处理特定信息 问题: 现在要从一个复杂的html代码字符串(包含各种html标签,数字.中文等信息)中找到某一段特别的信息(被一对“|”包裹着),并对他 ...

  9. Linux安装部署项目实例

    本次安装jdk,mysql,maven,redis,nginx,tomcat 安装之前先升级系统 使用命令:/bin/yum - y update 1.安装jdk 先建立一个项目的目录-jiaoton ...

  10. P3232 [HNOI2013]游走——无向连通图&&高斯消元

    题意 一个无向连通图,顶点从1编号到N,边从1编号到M. 小Z在该图上进行随机游走,初始时小Z在1号顶点,每一步小Z以相等的概率随机选 择当前顶点的某条边,沿着这条边走到下一个顶点,获得等于这条边的编 ...