sicily 1459. The Dragon of Loowater

	Time Limit: 1sec    Memory Limit:32MB  Description Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance. One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom. The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height." Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp! Input The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres. The last test case is followed by a line containing: 0 0 Output For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line: Loowater is doomed! Sample Input aaarticlea/jpeg;base64,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" alt="" /> Copy sample input to clipboard  2 3 5 4 7 8 4 2 1 5 5 10 0 0 Sample Output 11 Loowater is doomed!

分析：
    根据题意，要找到能砍掉所有龙头的最小代价，也就是说所需要的骑士的数量是确定的，那么只需要从小到大找到 n 个满足情况的骑士。
    所有对龙头直径和骑士分别排序，然后从龙头的从小到大找符合条件的骑士即可

#include <iostream>
#include <algorithm>

using namespace std;

int getMinCost(int *dragon, int *warrior, int n, int m) {
    sort(dragon, dragon + n);
    sort(warrior, warrior + m);
    int minCost = ;
    int i = , j = ;
    for (; i < n && j < m;) {
        if (dragon[i] <= warrior[j]) {
            minCost += warrior[j];
            ++i;
        }
        ++j;
    }
    if (i != n)
        minCost = ;
    return minCost;
}

int main(int argc, char const *argv[])
{
    int m, n;
    int dragon[];
    int warrior[];
    while (cin >> n >> m && (n !=  && m != )) {
        for (int i = ; i != n; ++i)
            cin >> dragon[i];
        for (int i = ; i != m; ++i)
            cin >> warrior[i];

        int minCost = ;
        if (n <= m) {
            minCost = getMinCost(dragon, warrior, n, m);
        }
        if (minCost == )
            cout << "Loowater is doomed!" << endl;
        else
            cout << minCost << endl;
    }
    return ;
}