The 2019 China Collegiate Programming Contest Harbin Site J. Justifying the Conjecture
链接:
https://codeforces.com/gym/102394/problem/J
题意:
The great mathematician DreamGrid proposes a conjecture, which states that:
Every positive integer can be expressed as the sum of a prime number and a composite number.
DreamGrid can't justify his conjecture, so you are invited to write a program to verify it. Given a positive integer n, find a prime number x and a composite number y such that x+y=n.
A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers. A natural number greater than 1 that is not prime is called a composite number. Note that 1 is neither a prime number nor a composite number.
思路:
小于6不行,偶数用2,奇数用3.
代码:
#include<bits/stdc++.h>
using namespace std;
int main()
{
ios::sync_with_stdio(false);
int t;
cin >> t;
while(t--)
{
int n;
cin >> n;
if (n <= 5)
cout << -1 << endl;
else if (n%2 == 0)
cout << 2 << ' ' << n-2 << endl;
else
cout << 3 << ' ' << n-3 << endl;
}
return 0;
}
The 2019 China Collegiate Programming Contest Harbin Site J. Justifying the Conjecture的更多相关文章
- The 2019 China Collegiate Programming Contest Harbin Site
题解: https://files.cnblogs.com/files/clrs97/HarbinEditorialV2.zip Code: A. Artful Paintings /* let x= ...
- The 2019 China Collegiate Programming Contest Harbin Site F. Fixing Banners
链接: https://codeforces.com/gym/102394/problem/F 题意: Harbin, whose name was originally a Manchu word ...
- The 2019 China Collegiate Programming Contest Harbin Site K. Keeping Rabbits
链接: https://codeforces.com/gym/102394/problem/K 题意: DreamGrid is the keeper of n rabbits. Initially, ...
- The 2019 China Collegiate Programming Contest Harbin Site I. Interesting Permutation
链接: https://codeforces.com/gym/102394/problem/I 题意: DreamGrid has an interesting permutation of 1,2, ...
- 模拟赛小结:The 2019 China Collegiate Programming Contest Harbin Site
比赛链接:传送门 上半场5题,下半场疯狂挂机,然后又是差一题金,万年银首也太难受了. (每次银首都会想起前队友的灵魂拷问:你们队练习的时候进金区的次数多不多啊?) Problem J. Justify ...
- The 2017 China Collegiate Programming Contest, Hangzhou Site Solution
A: Super_palindrome 题面:给出一个字符串,求改变最少的字符个数使得这个串所有长度为奇数的子串都是回文串 思路:显然,这个字符串肯定要改成所有奇数位相同并且所有偶数位相同 那统计一下 ...
- 2019 China Collegiate Programming Contest Qinhuangdao Onsite
传送门 D - Decimal 题意: 询问\(\frac{1}{n}\)是否为有限小数. 思路: 拆质因子,看是不是只包含2和5即可,否则除不尽. Code #include <bits/st ...
- 2019 China Collegiate Programming Contest Qinhuangdao Onsite F. Forest Program(DFS计算图中所有环的长度)
题目链接:https://codeforces.com/gym/102361/problem/F 题意 有 \(n\) 个点和 \(m\) 条边,每条边属于 \(0\) 或 \(1\) 个环,问去掉一 ...
- The 2015 China Collegiate Programming Contest A. Secrete Master Plan hdu5540
Secrete Master Plan Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Othe ...
随机推荐
- 1.IO的演进
1.Java IO 演进之路 本文围绕着一下几个问题 1.Java 中 BIO.NIO.AIO 之间的区别及应用场景. 2.阻塞(Block)与非阻塞(Non-Block)区别. 3.同步(Syn ...
- a+b的问题
题目描述: 给定两个整数 a, b (a, b 均不超过 int 类型的表示范围),求出 a + b 的和. 输入描述: 每行输入两个整数 a 和 b,用空格隔开. 输出描述: a + b 的值. 样 ...
- 剑指offer31:整数中1出现的次数(从1到n整数中1出现的次数)
1 题目描述 求出1~13的整数中1出现的次数,并算出100~1300的整数中1出现的次数?为此他特别数了一下1~13中包含1的数字有1.10.11.12.13因此共出现6次,但是对于后面问题他就没辙 ...
- python — 线程
目录 1.线程基础知识 2 Thread 类 3 锁 4 队列 1.线程基础知识 1.1 进程与线程的区别 进程: 创建进程 时间开销大 销毁进程 时间开销大 进程之间切换 时间开销大 线程: 线程是 ...
- PHP 中 include 和 require 的区别详解
require() 语句的性能与 include() 相类似,都是包括并运行指定文件.除了处理失败的方式不同之外.require 在出错时产生 E_COMPILE_ERROR 级别的错误,终止脚本运行 ...
- 开始Jupyter Notebooks
开始Jupyter Notebooks 安装Anaconda 因为不能有空格,所以没有选C:\Program Files 认识Jupyter Notebooks 修改 jupyter notebook ...
- PowerBuilder学习笔记之2PowerScript语言(二)
z教材地址:https://wenku.baidu.com/view/1e82d26925c52cc58ad6be05.html?sxts=1565679996440 2.4数组 声明数组:Integ ...
- DO、VO、DTO 区别
DTO:数据传输对象,主要用于外部接口参数传递封装,接口与接口进行传递使用. VO:视图对象,主要用于给前端返回页面参数使用. DO:数据对象,主要用于数据库层传递. DTO转DO:接口接收参数将参数 ...
- 浅谈(IOC)依赖注入与控制反转(DI)
前言:参考了百度文献和https://www.cnblogs.com/liuqifeng/p/11077592.html以及http://www.cnblogs.com/leoo2sk/archive ...
- 使用File类、StreamRead和StreamWrite读写数据、以及Path类操作文件路径和Directory
1.File类的概念: File类,是一个静态类,主要是来提供一些函数库用的.静态实用类,提供了很多静态的方法,支持对文件的基本操作,包括创建,拷贝,移动,删除和 打开一个文件. File类方法的参量 ...