Arrange seat of a bench for people
Given a bench with n seats and few people sitting, tell the seat number each time when a new person goes to sit on the bench such that his distance from others is maximum?
G jia
A few clarifying questions that i would ask:
1. What if the bench is emtpy. Can i return any seat number?
2. What if bench is full. Should i return -1.
3. How big can n be?
4. How many queries are we making?
Algo:
1. Traverse the bench once (saved as array or vector) and populate a max heap based on distance between two occupied seats. For each node in heap have distance, start seat no and end seat no.
2. When a query is made return the seat no as (end seat no - start seat no)/2 for the root node in heap.
3. Replace the root node with one node formed by (end seat no - start seat no)/2 and end seat no and call heapIfY() on heap.
4. insert the seconds node formed by start node no and (end seat no - start seat no)/2 in the heap.
Repeat process from 2 to 4 for each query.
Complexity:
Forming heap: O(n)
For each query: O(log(n))
Arrange seat of a bench for people的更多相关文章
- 2018SDIBT_国庆个人第三场
A - A CodeForces - 1042A There are nn benches in the Berland Central park. It is known that aiai peo ...
- CodeForce--Benches
A. Benches There are nn benches in the Berland Central park. It is known that aiai people are curr ...
- Codeforces Round #510 (Div. 2) A&B By cellur925
第一次CF祭== 由于太菜了只做了前两题== 因为在第一题上耗费时间太多了,我还是太菜了==. A. Benches time limit per test 1 second memory limit ...
- Codeforces Round #460 (Div. 2)-C. Seat Arrangements
C. Seat Arrangements time limit per test1 second memory limit per test256 megabytes Problem Descript ...
- Codeforces 919 C. Seat Arrangements
C. Seat Arrangements time limit per test 1 second memory limit per test 256 megabytes input standa ...
- codeforces 919C Seat Arrangements 思维模拟
C. Seat Arrangements time limit per test 1 second memory limit per test 256 megabytes input standard ...
- MySQL可视化软件Work Bench导出导入数据库
首先打开你的work bench,输入你的密码进入主页面 A:导入数据库 在Schemas空白处右键选择Create~:建立一个数据库,然后就可以导入你的sql文件了 File-->Open S ...
- bench.sh 跑分测速
#!/bin/bash #==============================================================# # Description: bench te ...
- 通过Measure & Arrange实现UWP瀑布流布局
简介 在以XAML为主的控件布局体系中,有用于完成布局的核心步骤,分别是measure和arrange.继承体系中由UIElement类提供Measure和Arrange方法,并由其子类Framewo ...
随机推荐
- MGR测试及搭建
一.部署规划:本次布署使用单机多实例进行basedir: /usr/local/mysql端口号 数据目录 group_repplication通信端口3306 /data/mysql/mysql_3 ...
- 中文乱码 encodeURI来解决URL传递时的中文问题
解决中文乱麻问题,页面端发出的数据作两次encodeURI var name="张三"; encodeURI(encodeURI(name)); 后台解码: URLDecoder. ...
- 解决每次执行Java等命令时都要重新source /etc/profile后才能执行,否则找不到命令
linux mint 我们通常将环境变量设置在/etc/profile这个文件中,这个文件是全局的. /etc/profile:在登录时,操作系 统定制用户环境时使用的第一个文件 ,此文件为系统的每个 ...
- [USACO19OPEN]Snakes
题目链接 题目简介:有n组,每组有若干个蛇的蛇队伍.(也可以理解为n条长度若干的蛇.)我们要用网捕捉,中途可以改变网的大小.目标是浪费空间最小. 解法:首先明确方法:DP.设f[i][t]为捕捉了n条 ...
- pyecharts v1 版本 学习笔记 柱状图
柱状图 bar 基本演示例子 from pyecharts import options as opts from pyecharts.charts import Bar c =( Bar().add ...
- bzoj 1924
所用点的编号为输入顺序,因为只有在存在联通门的宫室中存在宝藏.其余点不考虑 对于每一行,选定一个横天门,向该行横天门连双向边,其余门单向边纵列同理自.由门用map判周围八个点是否存在,存在即连边 Ta ...
- 2018年 第43届ACM-ICPC亚洲区域赛(青岛)现场赛 赛后总结
下了动车后,又颠颠簸簸的在公交车上过了接近一个小时,本来就晕车,于是,到的时候脑子晕死了,而且想吐.可能是没吃早饭的缘故,午饭好好次QWQ. 开幕式 还是第一次在这种环境下参赛,记得以前是看老师发的学 ...
- Python3使用openpyxl读写Excel文件
Python中常用的操作Excel的三方包有xlrd,xlwt和openpyxl等,xlrd支持读取.xls和.xlsx格式的Excel文件,只支持读取,不支持写入.xlwt只支持写入.xls格式的文 ...
- 常用exporter下载
1.node_exporter https://github.com/prometheus/node_exporter/releases/download/v0.18.1/node_exporter- ...
- mapreduce 倒序 排序 最简单 易上手
对于mapreduce倒序只需要建立一个类,然后继承WritableComparator 在重写 Compare函数最后在main里调用一下,就可以实现倒序排序: 代码: public static ...