题目要求:First Missing Positive

Given an unsorted integer array, find the first missing positive integer.

For example,
Given [1,2,0] return 3,
and [3,4,-1,1] return 2.

Your algorithm should run in O(n) time and uses constant space.

代码如下:

class Solution {
public:
int firstMissingPositive(int A[], int n) { for (int i = 0, temp = -1; i < n; i++) {
while (A[i] - 1 >= 0 && A[i] - 1 < n && A[i] - 1 != i) {
swap(A, i, A[i] - 1);
if (A[i] == temp) {
break;
}
else {
temp = A[i];
}
}
}
for (int i = 0; i < n; i++) {
if (A[i] - 1 != i) {
return i + 1;
}
}
return n + 1;
} private:
void swap(int A[], int idx1, int idx2) {
A[idx1] ^= A[idx2];
A[idx2] ^= A[idx1];
A[idx1] ^= A[idx2];
}
};

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