Dragon Balls[HDU3635]
Dragon Balls
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6086 Accepted Submission(s): 2248
Problem Description
Five hundred years later, the number of dragon balls will increase unexpectedly, so it's too difficult for Monkey King(WuKong) to gather all of the dragon balls together.
His country has N cities and there are exactly N dragon balls in the world. At first, for the ith dragon ball, the sacred dragon will puts it in the ith city. Through long years, some cities' dragon ball(s) would be transported to other cities. To save physical strength WuKong plans to take Flying Nimbus Cloud, a magical flying cloud to gather dragon balls.
Every time WuKong will collect the information of one dragon ball, he will ask you the information of that ball. You must tell him which city the ball is located and how many dragon balls are there in that city, you also need to tell him how many times the ball has been transported so far.
Input
The first line of the input is a single positive integer T(0 < T <= 100).
For each case, the first line contains two integers: N and Q (2 < N <= 10000 , 2 < Q <= 10000).
Each of the following Q lines contains either a fact or a question as the follow format:
T A B : All the dragon balls which are in the same city with A have been transported to the city the Bth ball in. You can assume that the two cities are different.
Q A : WuKong want to know X (the id of the city Ath ball is in), Y (the count of balls in Xth city) and Z (the tranporting times of the Ath ball). (1 <= A, B <= N)
Output
For each test case, output the test case number formated as sample output. Then for each query, output a line with three integers X Y Z saparated by a blank space.
Sample Input
2
3 3
T 1 2
T 3 2
Q 2
3 4
T 1 2
Q 1
T 1 3
Q 1
Sample Output
Case 1:
2 3 0
Case 2:
2 2 1
3 3 2
跟上道题差不多,忘记输出case了,mdzz。
#include <stdio.h>
#include <string.h>
int size[], cnt[];
int asd;
class Union_Find_Set {
#define MAX_UNION_FIND_SET_SIZE 10005
public:
int setSize;
int father[MAX_UNION_FIND_SET_SIZE];
Union_Find_Set() {
setSize = ;
}
Union_Find_Set(int x) {
setSize = x;
clear(x);
}
void clear(int x) {
for (int i = ; i < x; i++) {
father[i] = i;
}
}
int getFather(int x) {
asd = cnt[x];
int ret = x, tmp;
while (ret != father[ret]) {
asd += cnt[father[ret]];
ret = father[ret];
}
int ttt = asd - cnt[ret];
while (x != father[x]) {
tmp = father[x];
father[x] = ret;
ttt -= cnt[x];
cnt[x] += ttt;
x = tmp;
}
return ret;
}
bool merge(int a, int b) {
a = getFather(a);
b = getFather(b);
if (a != b) {
father[a] = b;
cnt[a]++;
size[b] += (size[a] + );
return true;
} else {
return false;
}
}
int countRoot() {
int ret = ;
for (int i = ; i < setSize; i++) {
if (father[i] = i) {
ret++;
}
}
return ret;
}
};
Union_Find_Set ufs;
int main() {
int tt;
scanf("%d", &tt);
for (int jjjj = ; jjjj <= tt; jjjj++) {
printf("Case %d:\n", jjjj);
int n, q, a, b;
char t;
scanf("%d%d", &n, &q);
ufs.clear();
memset(size, , sizeof(size));
memset(cnt, , sizeof(cnt));
while (q--) {
getchar();
scanf("%c", &t);
if (t == 'T') {
scanf("%d%d", &a, &b);
ufs.merge(a, b);
} else if (t == 'Q') {
scanf("%d", &a);
int f = ufs.getFather(a);
printf("%d %d %d\n", f, size[f] + , asd);
}
}
}
return ;
}
Dragon Balls[HDU3635]的更多相关文章
- Dragon Balls(hdu3635带权并查集)
题意:n个城市有n个龙珠,T a,b 代表将龙珠a移动到b城市,Q a代表查询龙珠a所在城市,该城市有多少颗龙珠,该龙珠移动了多少次. 注意:移动时是将龙珠所在该城市所有龙珠都移动,每个龙珠不会再回 ...
- hdu3635 Dragon Balls
Problem Description Five hundred years later, the number of dragon balls will increase unexpectedly, ...
- hdu 3635 Dragon Balls(并查集)
Dragon Balls Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Tota ...
- hdu 3635 Dragon Balls (带权并查集)
Dragon Balls Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Tota ...
- hdu 3635 Dragon Balls
Dragon Balls Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Tot ...
- hdoj 3635 Dragon Balls【并查集求节点转移次数+节点数+某点根节点】
Dragon Balls Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Tota ...
- hdu 3635 Dragon Balls(并查集应用)
Problem Description Five hundred years later, the number of dragon balls will increase unexpectedly, ...
- Dragon Balls
Dragon Balls Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total ...
- HDU 3635:Dragon Balls(并查集)
Dragon Balls Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Tot ...
随机推荐
- dotnetnuke7.3.3 下弹出对话框(dnnConfirm())的使用
今天用dnn做一个列表里边有一个删除操作,就想做个对话框确定是否删除? 正常理解马上想到js的confirm("")函数,但是发现Dnn把这个函数给重写啦,弹出的对话框竟然是英文的 ...
- Nagios Windows客户端NSClient++ 0.4.x安装配置
NSClient++ 0.3.x和NSClient++ 0.4.x的配置完全不一样,官方的文档也没有全部更新.我记录下自己的一些操作. 一.下载安装NSClient++ 1.到http://nsc ...
- ESLint 规范项目代码
ESLint 由 JavaScript 红宝书 作者 Nicholas C. Zakas 编写, 2013 年发布第一个版本. NCZ 以可扩展.每条规则独立.不内置编码风格为理念编写了一个 lint ...
- Sublime + Chrome 本地调试 CSS 选择器
生成简单的 HTML 代码 使用MacDown写 Markdown,快捷键ALT+CMD+C拷贝成 HTML 代码 粘贴到 Sublime 中,加上 body 标签和 css 头 html <h ...
- C#学习 第十节
操作符(operator) 1.操作符的概览 从上到下优先级依次减弱: 2.操作符的本质 操作符的本质是函数的简记法: 计算机的操作符不能脱离与它关联的数据类型: 3.操作符的优先级 可以使用括号 4 ...
- `itchat`配置代理
config.py配置 首先,先找到itchat安装的目录,然后定位到config.py文件: import os, platform VERSION = '1.3.10' BASE_URL = 'h ...
- Java 习惯用法总结
转自:http://www.importnew.com/15605.html 首页 所有文章 资讯 Web 架构 基础技术 书籍 教程 我要投稿 更多频道 » Java 习惯用法总结 2015/04/ ...
- [USACO17JAN]Promotion Counting
线段树合并. 正解好像不是线段树合并,但是出于练手的目的写了线段树合并. 大概就是对于左右子树,如果有一个为空,返回非空的,如果都不为空,就把这两个整合到一起就行了. #include <ios ...
- 00074_Array类
1.Array类的概述 此类包含用来操作数组(比如排序和搜索)的各种方法.需要注意,如果指定数组引用为 null,则访问此类中的方法都会抛出空指针异常NullPointerException. 2.常 ...
- --- Error: failed to execute '.\ARMCC\bin\ArmAsm'
1.KEIL4在开发STM32程序时报: Error: failed to execute '.\ARMCC\bin\ArmAsm' 或是Error: failed to execute '.\ARM ...