Given an input string, reverse the string word by word.

For example,
Given s = "the sky is blue",
return "blue is sky the".

 public class Solution {
public String reverseWords(String s) {
if(s.equals(""))return s;
String arr[]=s.split(" ");
String new_word="";
for(int i=arr.length-1;i>=0;i--)
{
if(arr[i].equals(""))continue;
new_word+=arr[i]+" ";
}
new_word=new_word.toString().trim();
return new_word;
}
}

做完以后看了别人的答案 发现有用StringBuilder

所以又去学习了一下这个三个的区别 在100000复杂度下 StringBulder和buffer比string快的就不是一点了

所以:

1.如果要操作少量的数据用 = String

2.单线程操作字符串缓冲区 下操作大量数据 = StringBuilder 
3.多线程操作字符串缓冲区 下操作大量数据 = StringBuffer

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